Class 10 · Science · Chapter 10 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27

The Human Eye and the Colourful World

The Human Eye and the Colourful World

How to use this page:
1. Read — Activities 10.1 and 10.2, diagram, worked example, board tip
2. Check — each lesson has its own questions; the number follows the lesson
3. Mastery ★ — all of that lesson correct. Redo the wrong ones
4. The picture to remember is a prism spectrum: violet bends the most and red the least.

In NCERT this is chapter 10. The older Bihar book calls the same text chapter 11. Progress stays in this browser.

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  • 1 Parts of the eye and the power of accommodation
  • 2 Myopia and hypermetropia — which lens
  • 3 Presbyopia, bifocal lenses and eye donation
  • 4 Refraction through a prism — Activity 10.1
  • 5 Dispersion and recombination — Activity 10.2
  • 6 Atmospheric refraction — twinkling and advanced sunrise
  • 7 Scattering — blue sky, red sunset and the Tyndall effect
  • Chapter winner — every lesson at mastery ★

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1

Parts of the eye and the power of accommodation

आँख के भाग और समंजन क्षमता · NCERT 10.1 · accommodation · near point 25 cm

New
Parts of the eye and the power of accommodat…LensRetina
The lens bends light and forms the picture on the retina.
The eye is like a camera, but the lens can change its focal lengthNotes

The eyeball is roughly spherical and about 2.3 cm across. Light enters through a thin membrane, the cornea. Most of the bending happens at the outer surface of the cornea. The crystalline lens only makes the fine adjustment of focal length.

Behind the cornea is the iris. This dark muscular diaphragm changes the size of the pupil and so controls how much light enters. The lens forms an inverted, real image on the retina. Light-sensitive cells of the retina make electrical signals. The signals travel to the brain along the optic nerve.

PartJob
CorneaMost of the refraction
IrisLight amount through the pupil
Eye lensFine change of focal length
RetinaInverted real image
Optic nerveSignals to the brain
Accommodation — near and far, on the same retinaNotes

The lens is a fibrous, jelly-like material. The ciliary muscles can change its curvature a little. When the muscles are relaxed the lens becomes thin, the focal length increases and a distant object is clear. For a nearby object the muscles contract, the lens thickens and the focal length decreases.

The focal length cannot be made shorter than a limit. The smallest distance for clear, comfortable vision is the least distance of distinct vision. It is also called the near point. For a young adult with normal vision it is about 25 cm. The far point is infinity. A page held closer than this looks blurred and the eye feels strained.

Worked exampleExample

Question: What is the power of accommodation? What is the range of a normal eye?

Answer: It is the ability of the eye to focus near and distant objects on the retina by changing the focal length of the lens. A normal young eye sees clearly from 25 cm out to infinity.

10-second revision
  • Most refraction is at the cornea; the lens only fine-focuses
  • The image on the retina is inverted and real
  • Near point about 25 cm; far point infinity; accommodation means changing focal length
Board tip · BSEBBoard tip

In a BSEB definition write both words — ciliary muscle and focal length. “The eye shrinks” is incomplete.

Board tip · CBSEBoard tip

CBSE often asks where the image is formed. The answer is the retina, not the cornea or the pupil.

Check your understandingall correct = mastery ★
1
Where does the human eye form the image of an object?
Check
2
The near point of a normal young eye is about
Check
3
The ciliary muscles change the focal length of the eye lens.
Check
4
The ability of the eye to change its focal length is called ______.
Check
5
Write one difference between the job of the cornea and the job of the eye lens.
Check2 marks
6
For a distant object take the distance from the lens to the retina as 2.3 cm. Find the power of the eye in dioptres.
Check2 marks
Next lesson →
2

Myopia and hypermetropia — which lens

निकट-दृष्टि और दूर-दृष्टि — कौन-सा लेंस · NCERT 10.2 · myopia · hypermetropia

New
Myopia and hypermetropiaLensRetina
The lens bends light and forms the picture on the retina.
Two defects, two places where the image formsNotes

In myopia nearby objects are clear and distant ones are not. The far point comes closer than infinity. The image of a distant object forms in front of the retina. Two causes are possible — the lens is too curved, or the eyeball has become too long. A concave lens of suitable power corrects it.

In hypermetropia distant objects are clear and nearby ones are not. The near point shifts farther than 25 cm. The image of a nearby object forms behind the retina. The cause is a focal length that is too long, or an eyeball that is too small. A convex lens of suitable power corrects it.

DefectImageLens
MyopiaIn front of the retinaConcave
HypermetropiaBehind the retinaConvex
Worked example — far point 40 cmExample

Question: A person cannot see objects clearly beyond 40 cm. Find the nature and the power of the lens.

Formula: 1/f = 1/v − 1/u and P = 1/f, with f in metres.

Signs: For a distant object u = −∞. The image must lie at the far point, so v = −40 cm = −0.40 m.

Substitution: 1/f = 1/(−0.40) − 0 = −2.5 m⁻¹. So f = −0.40 m and P = −2.5 D.

A negative power means a concave lens.

10-second revision
  • Myopia: image in front of the retina; concave lens
  • Hypermetropia: image behind the retina; convex lens
  • If the far point is 40 cm, P = −2.5 D
Board tip · BSEBBoard tip

In a BSEB answer write all three — the name of the defect, where the image forms, and the lens.

Board tip · CBSEBoard tip

A CBSE calculation asks for the signs. Without u at infinity and a negative v you will not get −2.5 D.

Check your understandingall correct = mastery ★
1
Which lens corrects myopia?
Check
2
In hypermetropia, where does the image of a nearby object form?
Check
3
The far point of a myopic eye is at infinity.
Check
4
Hypermetropia is corrected by a ______ lens.
Check
5
A person has a far point of 40 cm. Find the power of the correcting lens. Write the formula, the substitution and the unit.
Check3 marks
Next lesson →
3

Presbyopia, bifocal lenses and eye donation

जरा-दूरदर्शिता, द्विफोकसी लेंस और नेत्रदान · NCERT 10.2 · presbyopia · cataract · eye donation

New
Presbyopia, bifocal lenses and eye donationLensRetina
The lens bends light and forms the picture on the retina.
Accommodation falls with ageNotes

For most people the near point slowly recedes with age. Nearby objects are no longer comfortable without glasses. This defect is presbyopia. The ciliary muscles gradually weaken and the lens loses flexibility.

Sometimes one person has both myopia and hypermetropia. Then a bifocal lens is used. The upper part is concave, for distant vision. The lower part is convex, for reading. These defects can also be corrected with contact lenses or by surgery.

In old age the lens sometimes becomes milky and cloudy. This is cataract. Vision may be lost in part or fully. Surgery can restore it.

Eye donation — the time limit, and who cannot donateCaution

The eyes must be removed within 4 to 6 hours of death. Inform the eye bank at once. Removal takes 10–15 minutes and does not disfigure the face. A donor may be of any age or sex. People who wear spectacles, and those who have had cataract surgery, can still donate.

A person infected with, or dead from, AIDS, hepatitis B or C, rabies, acute leukaemia, tetanus, cholera, meningitis or encephalitis cannot donate eyes. One pair of eyes can give vision to as many as four people with corneal blindness.

Worked example — two powers, two focal lengthsExample

Question: The power of the lens for distant vision is −4.0 D and for near vision it is +2.5 D. Find both focal lengths.

Formula: f = 1/P, and f is in metres when P is in dioptres.

Substitution: Distant vision, f = 1/(−4.0) = −0.25 m = −25 cm. This is a concave lens.

Near vision, f = 1/(+2.5) = 0.40 m = 40 cm. This is a convex lens. In a bifocal the upper part is concave and the lower part is convex.

10-second revision
  • Presbyopia: weak ciliary muscles and a less flexible lens
  • Bifocal: concave on top (far), convex below (near)
  • Eyes must be removed within 4–6 hours of death
Board tip · BSEBBoard tip

In a BSEB answer the bifocal sentence must not swap the upper and lower parts.

Board tip · CBSEBoard tip

In the CBSE relation f = 1/P the sign of P stays with the focal length. The focal length for −4.0 D is negative.

Check your understandingall correct = mastery ★
1
The upper part of a bifocal lens is
Check
2
In cataract the eye lens becomes milky and cloudy.
Check
3
The main cause of presbyopia is —
Check
4
Within what time must eyes be removed for donation? Name one illness in which donation is not possible.
Check2 marks
5
The upper part of a bifocal lens has power −2.0 D. Find the focal length in cm and state which kind of vision this part is for.
Check3 marks
Next lesson →
4

Refraction through a prism — Activity 10.1

प्रिज्म से अपवर्तन — क्रियाकलाप 10.1 · NCERT 10.3 · Activity 10.1 · angle of deviation

New
Refraction through a prismWhiteSeven colours
A glass prism spreads white light into seven colours.
A slab and a prism are not the sameNotes

The two faces of a glass slab are parallel, so the emergent ray stays parallel to the incident ray and only shifts sideways. The refracting faces of a prism are inclined to each other. The angle between the two lateral faces is the angle of the prism (∠A).

Because of the shape of the prism, the emergent ray bends at an angle to the direction of the incident ray. That angle is the angle of deviation (∠D).

Activity 10.1 — the path of the ray with four pinsActivity

Fix a sheet of white paper on a drawing board with drawing pins. Place a glass prism on its triangular base and trace the outline. Draw a straight line PE inclined to one refracting face, AB. Fix two pins, P and Q, on the line.

Look through the other face AC for the images of P and Q. Fix two more pins, R and S, so that R, S and the images of P and Q lie on one straight line. Remove the pins and the prism. PE meets the boundary at E. Join R and S and produce the line to meet the boundary at F. Join E and F.

Draw the normals at E and F. Mark the angle of incidence ∠i, the angle of refraction ∠r and the angle of emergence ∠e. PE is the incident ray, EF the refracted ray and FS the emergent ray. At the first face the ray goes from air into glass and bends towards the normal. At the second face it goes from glass into air and bends away from the normal.

Worked exampleExample

Question: Why is the ray that leaves a prism not parallel to the incident ray?

Answer: The two refracting faces of a prism are not parallel. At the first face the ray bends towards the normal and at the second face it bends away from the normal. The two bends do not cancel. The angle left between the incident and emergent rays is the angle of deviation.

10-second revision
  • First face: air to glass, towards the normal
  • Second face: glass to air, away from the normal
  • ∠D is the angle of deviation; in a slab it stays zero
Board tip · BSEBBoard tip

In a BSEB ray diagram name PE, EF, FS and the angles ∠i, ∠r, ∠e, ∠D. A diagram without names is counted incomplete.

Board tip · CBSEBoard tip

CBSE asks how the emergent ray differs for a slab and a prism. Write parallel versus deviation in one sentence.

Check your understandingall correct = mastery ★
1
How does the ray leaving a glass prism stand relative to the incident ray?
Check
2
At the first face of a prism, a ray entering from air into glass bends towards the normal.
Check
3
The angle between the incident ray and the emergent ray is called the angle of ______.
Check
4
In Activity 10.1, why are the pins R and S fixed?
Check
5
In Activity 10.1, which way does the ray bend at the first face and at the second face?
Check2 marks
6
The refractive index of glass is 1.50. Find the speed of light in glass. Take c = 3.0 × 108 m/s.
Check2 marks
Next lesson →
5

Dispersion and recombination — Activity 10.2

विक्षेपण और पुनर्योजन — क्रियाकलाप 10.2 · NCERT 10.4 · Activity 10.2 · the rainbow

New
Activity 10.2 — sunlight through a slit onto a prismActivity

Make a small hole or a narrow slit in the middle of a thick sheet of cardboard. Let sunlight fall on the slit so that you get a narrow beam of white light. Do not look straight at the sun; let the beam fall on the slit.

Take a glass prism and let this beam fall on one face. Turn the prism slowly until the light that comes out appears on a nearby screen. A beautiful band of colours appears. The order is violet, indigo, blue, green, yellow, orange and red — VIBGYOR. This band is called the spectrum. The splitting of white light into its component colours is dispersion.

Violet bends more, and a second prism joins the coloursNotes

Each colour bends through a different angle from the incident ray. Red bends the least and violet bends the most. So each colour leaves along its own path and stands apart on the screen.

Newton first obtained the spectrum of sunlight with a glass prism. A second prism used the same way did not split the colours any further. When a second identical prism was placed inverted relative to the first, all the colours passed through it and white light came out on the other side. Light that gives a spectrum like sunlight is called white light.

A rainbow forms in the sky after rain, in the direction opposite the sun. Tiny water drops act as prisms. They refract and disperse the sunlight, then reflect it inside the drop, and refract it again as it comes out. With the sun behind you, a rainbow can also be seen in a waterfall or a fountain.

Prism spectrum — violet bends the mostWhite lightPrismRed · leastViolet · mostThe order on the screen is VIBGYOR. Red is deviated least and violet the most.
White light enters the prism. On the screen red is at the top (least deviation) and violet at the bottom (most deviation).
Worked exampleExample

Question: Which colours lie at the two ends of the spectrum, and what does a second inverted prism do?

Answer: Violet is at one end and bends the most. Red is at the other end and bends the least. A second prism placed inverted joins these colours into one beam, and white light comes out.

10-second revision
  • Dispersion is white light splitting into colours; the band is the spectrum
  • Violet bends the most, red the least
  • An inverted second prism recombines the colours into white light
Board tip · BSEBBoard tip

When you write VIBGYOR for BSEB, put violet first. Do not give red the larger deviation.

Board tip · CBSEBoard tip

CBSE asks three steps for a rainbow — refraction, internal reflection, then refraction. “The drop is a prism” is only half the answer.

Check your understandingall correct = mastery ★
1
Which colour bends the most through a prism?
Check
2
The splitting of white light into its component colours is called —
Check
3
A second prism placed inverted relative to the first joins the spectrum back into white light.
Check
4
The colour that bends the least in the spectrum is ______.
Check
5
In which direction does a rainbow appear in the sky?
Check
6
The wavelength of blue light is 400 nm. The wavelength of red is about 1.8 times this. Find the wavelength of red in nm. In one sentence, say what a second inverted prism shows.
Check3 marks
Next lesson →
6

Atmospheric refraction — twinkling and advanced sunrise

वायुमंडलीय अपवर्तन — टिमटिमाना और आगे का सूर्योदय · NCERT 10.5 · stars · planets · sunrise by 2 minutes

New
Atmospheric refractionWhiteSeven colours
A glass prism spreads white light into seven colours.
Hot air wavers, and a star twinklesNotes

The hot air above a fire is lighter than the cooler air and has a slightly smaller refractive index. The medium does not stay still, so the apparent position of an object keeps wavering. That is atmospheric refraction on a small scale.

Starlight bends continuously in the atmosphere. Near the horizon a star appears slightly higher than its real position. The state of the atmosphere keeps changing, so the apparent position changes too. Stars are so far away that they behave as point sources. The light entering the eye is sometimes more and sometimes less — that is the twinkling.

Planets do not twinkle. They are nearer the earth and look like extended sources. The variations from a large number of point sources average out to zero.

Sunrise two minutes early, sunset two minutes late

Actual sunrise means the sun really crossing the horizon. Because of atmospheric refraction we see the sun about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset. The apparent flattening of the sun disc at sunrise and sunset has the same cause.

Worked exampleExample

Question: Stars twinkle and planets do not. Write one reason.

Answer: Atmospheric refraction acts on both. A star is a point source, so the flicker in its light reaches the eye. A planet is an extended source, so the flickers from different points average out.

10-second revision
  • Twinkling is atmospheric refraction; a star is a point source
  • Planets are extended sources, so they do not twinkle
  • The sun appears about 2 minutes early at sunrise and 2 minutes late at sunset
Board tip · BSEBBoard tip

For BSEB write both facts — the star appears higher, and the light flickers. The single word refraction is not enough.

Board tip · CBSEBoard tip

The CBSE question on planets asks for a comparison. Write point source and extended source together.

Check your understandingall correct = mastery ★
1
The twinkling of stars is caused by —
Check
2
Planets twinkle just as stars do.
Check
3
Because of atmospheric refraction, the sun is seen about how long before the actual sunrise?
Check
4
Why do planets not twinkle? Write it in two lines.
Check2 marks
5
Sunrise is seen about 2 minutes early and sunset about 2 minutes late. Find the total extra viewing time over 15 days, in minutes and in hours.
Check2 marks
Next lesson →
7

Scattering — blue sky, red sunset and the Tyndall effect

प्रकीर्णन — नीला आकाश, लाल सूर्यास्त और टिंडल · NCERT 10.6 · Tyndall · blue sky · red signal

New
ScatteringWhiteSeven colours
A glass prism spreads white light into seven colours.
Tyndall — the path shows only when the particles are colloidalNotes

The path of a beam through a true solution is not visible. In a colloidal solution the particles are larger, so the path of the beam becomes visible. Scattering of light by those particles produces this effect. It is called the Tyndall effect.

The atmosphere is a mixture of smoke, tiny water droplets, dust and molecules of air. A sunbeam entering a smoke-filled room through a small hole, or sunlight filtering through the mist of a dense forest, are examples. Very fine particles scatter mainly blue light. Larger particles scatter longer wavelengths. If the particles are large enough, the scattered light can even look white.

Blue scatters more, and red travels onNotes

Molecules of air and other fine particles are smaller than the wavelength of visible light. They scatter the shorter waves at the blue end more than the longer waves at the red end. The wavelength of red light is about 1.8 times that of blue light. The scattered blue light enters our eyes, so the clear sky looks blue.

With no atmosphere there would be no scattering and the sky would look dark. Passengers flying very high see a dark sky. At sunrise and sunset the light travels a long path through the atmosphere. Blue is scattered away on the way, and the less-scattered red light reaches the eye. Danger signals are red for the same reason — fog or smoke scatters red the least, so the colour stays the same at a distance.

Worked exampleExample

Question: Why does the sky look dark, not blue, to an astronaut?

Answer: The blue colour comes from scattering by fine particles in air. At a very great height that scattering is no longer effective. Without scattering the sky looks dark.

10-second revision
  • The Tyndall effect is scattering by colloidal particles
  • Blue is scattered more; the wavelength of red is about 1.8 times that of blue
  • A danger signal is red because red is scattered the least
Board tip · BSEBBoard tip

For BSEB join the blue sky and the red sunset with one rule — a shorter wavelength scatters more.

Board tip · CBSEBoard tip

CBSE keeps Tyndall and dispersion apart. Tyndall is scattering by particles. Dispersion is the splitting of colours in a prism.

Check your understandingall correct = mastery ★
1
The Tyndall effect is seen in which of these?
Check
2
The clear sky looks blue because —
Check
3
Danger signals are red because red light is scattered the least by fog.
Check
4
At sunset the light that mainly reaches the eye is ______.
Check
5
Why does the sun look red at sunset? Why is a danger signal made red?
Check3 marks
6
The wavelength of red light is 720 nm. Write it in metres in standard form.
Check2 marks
Question bank →

❓ Full question bank — with answers and explanations — 68 questions

No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.

Multiple choice

0/15
Pick one option. A wrong try brings a hint.
1
The focal length of the eye lens is changed by the
NCERT-style · practice1 mark
2
Where does most of the refraction in the human eye take place?
Board-style (practice)1 mark
3
The least distance of distinct vision is —
NCERT-style · practice1 mark
4
An image of a distant object forming in front of the retina is called —
Board-style (practice)1 mark
5
Hypermetropia is corrected by —
Board-style (practice)1 mark
6
In presbyopia the lower part of a bifocal lens is —
Board-style (practice)1 mark
7
At the first face of a prism the ray bends —
Board-style (practice)1 mark
8
Which colour has the greatest deviation in the spectrum?
NCERT-style · practice1 mark
9
To turn the spectrum of sunlight back into white, Newton placed the second prism —
Board-style (practice)1 mark
10
In the formation of a rainbow a water drop does not —
Board-style (practice)1 mark
11
Stars twinkle because of —
NCERT-style · practice1 mark
12
About how long after the actual sunset is the sun still seen?
Board-style (practice)1 mark
13
The clear sky is blue because fine particles —
Board-style (practice)1 mark
14
A danger signal is made red because —
Board-style (practice)1 mark
15
An example of the Tyndall effect is —
Board-style (practice)1 mark
↑ Question hub

True or false

0/8
1
The diameter of the eyeball is about 2.3 cm.
Board-style (practice)1 mark
2
The far point of a normal eye is 25 cm.
Board-style (practice)1 mark
3
Myopia is corrected by a convex lens.
Board-style (practice)1 mark
4
In cataract the lens becomes milky and cloudy.
Board-style (practice)1 mark
5
The ray leaving a glass slab is parallel to the incident ray.
Board-style (practice)1 mark
6
Red light bends more than violet light.
Board-style (practice)1 mark
7
A rainbow forms in the direction of the sun.
Board-style (practice)1 mark
8
If there were no atmosphere the sky would look dark.
Board-style (practice)1 mark
↑ Question hub

Fill in the blanks

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1
The size of the pupil is controlled by the ______.
Board-style (practice)1 mark
2
The near point of the eye is about ______ cm.
Board-style (practice)1 mark
3
A ______ lens is used for myopia.
Board-style (practice)1 mark
4
The angle of the prism is the angle between the two ______ faces.
Board-style (practice)1 mark
5
The band of colours is called the ______.
Board-style (practice)1 mark
6
The wavelength of red light is about ______ times that of blue light.
Board-style (practice)1 mark
7
For eye donation the eyes must be removed within ______ hours of death.
Board-style (practice)1 mark
8
Planets do not twinkle because they are ______ sources.
Board-style (practice)1 mark
↑ Question hub

Match

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1
Match the part with its job.
Board-style (practice)2 marks
Column B: A. Size of the pupil · B. Most of the refraction · C. Screen for the image · D. Signals to the brain
1. Cornea
2. Iris
3. Retina
4. Optic nerve
2
Match the effect with its cause.
NCERT-style · practice2 marks
Column B: A. Scattering · B. Atmospheric refraction · C. Dispersion · D. Atmospheric refraction of a point source
1. Twinkling of stars
2. Blue sky
3. Spectrum
4. Advanced sunrise
↑ Question hub

Assertion–reason

0/5
Check both statements, then see whether the reason explains the assertion.
1

Assertion (A): Myopia is corrected by a concave lens.

Reason (R): In this defect the image of a distant object forms in front of the retina.

Board-style (practice)1 mark
2

Assertion (A): The clear sky looks blue.

Reason (R): Red light is scattered more than blue light.

Board-style (practice)1 mark
3

Assertion (A): In a prism violet light bends the least.

Reason (R): Different colours have different deviations.

CBSE-style · competency-based (not a PYQ)1 mark
4

Assertion (A): Planets do not twinkle.

Reason (R): Sunrise appears about 2 minutes early because of atmospheric refraction.

Board-style (practice)1 mark
5

Assertion (A): Danger signals are red.

Reason (R): Red light is scattered the least by fog or smoke.

NCERT-style · practice1 mark
↑ Question hub

Coefficient practice

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These equations are not results of this chapter. They are only practice in filling coefficients.
1
This is coefficient practice. This equation is not a result of this chapter. Balance it by filling the coefficients.
Board-style (practice)1 mark
H2 + O2 → H2O
2
This is coefficient practice. This equation is not a result of this chapter. Balance it by filling the coefficients.
Board-style (practice)1 mark
N2 + H2 → NH3
3
This is coefficient practice. This equation is not a result of this chapter. Balance it by filling the coefficients.
Board-style (practice)1 mark
CH4 + O2 → CO2 + H2O
4
This is coefficient practice. This equation is not a result of this chapter. Balance it by filling the coefficients.
Board-style (practice)2 marks
Fe + O2 → Fe2O3
↑ Question hub

Classify

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1
Place each defect with the right lens.
Board-style (practice)2 marks
Myopia
Hypermetropia
Near vision in presbyopia
Normal eye, a book at 25 cm
2
Place each effect in its class.
NCERT-style · practice2 marks
The coloured band from a prism
Blue sky
Twinkling of stars
A beam visible in smoke
↑ Question hub

Very short answer

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1
Define the power of accommodation in one line.
Board-style (practice)1 mark
2
Write the near point and the far point for normal vision.
NCERT-style · practice1 mark
3
What is dispersion?
Board-style (practice)2 marks
4
What is the Tyndall effect?
Board-style (practice)2 marks
5
What is the angle of deviation?
Board-style (practice)2 marks
↑ Question hub

Short answer

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1
Write two causes of myopia and its correction.
Board-style (practice)3 marks
2
Write the difference between hypermetropia and presbyopia.
NCERT-style · practice3 marks
3
In Activity 10.2, what appears on the screen and what is the order of colours?
Board-style (practice)3 marks
4
Why is sunrise seen before the actual time?
Board-style (practice)3 marks
↑ Question hub

Long answer

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1
Trace the path of light through the human eye. Explain the power of accommodation.
Board-style (practice)5 marks
2
The far point of a myopic person is 2 m. Find the power of the lens. Show the formula, the substitution and the unit. What does this lens do?
NCERT-style · practice5 marks
3
Explain the blue sky, the red sunset and the red danger signal with one rule.
Board-style (practice)5 marks
↑ Question hub

BSEB model paper · practice

0/6

This model set is for practice. It is not an annual examination paper of any year.

1
A student in the last row sees the board blurred. The defect and the lens are —
BSEB model · practice (not an annual paper)1 mark
2
In hypermetropia the near point is —
BSEB model · practice (not an annual paper)1 mark
3
The short form used to remember the spectrum is ______.
BSEB model · practice (not an annual paper)1 mark
4
Can a person who wears spectacles still donate eyes? Write it in one sentence with the reason.
BSEB model · practice (not an annual paper)2 marks
5
The near point of a hypermetropic eye is 50 cm. Taking the normal near point as 25 cm, find the power of the lens.
BSEB model · practice (not an annual paper)3 marks
6
Write the two different observations of a prism in Activities 10.1 and 10.2. Make the difference between deviation and dispersion clear.
BSEB model · practice (not an annual paper)5 marks
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CBSE-style questions

0/6

These are competency-based practice questions. They are not a past paper and not a copy of a CBSE paper.

1
A student is given two lenses, −0.5 D and +2.0 D. The lens that clears a distant object for a myopic eye is —
CBSE-style · competency-based (not a PYQ)1 mark
2
After rain the sun is behind you and a coloured arc is in the sky ahead. The correct account is —
CBSE-style · competency-based (not a PYQ)1 mark
3

Assertion (A): A student in the last row cannot read the board.

Reason (R): The student has myopia and a concave lens can correct the defect.

CBSE-style · competency-based (not a PYQ)1 mark
4

Assertion (A): At a very great height the sky looks dark.

Reason (R): At that height dispersion stops because there is no prism.

CBSE-style · competency-based (not a PYQ)1 mark
5
A person cannot read a book at 25 cm, but sees a distant bus clearly. Name the defect, where the image forms, and the lens.
CBSE-style · competency-based (not a PYQ)3 marks
6
An experiment with two prisms returns white light. What does the experiment show, and why had violet bent more?
CBSE-style · competency-based (not a PYQ)3 marks
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🏛️ Board exam corner — Bihar Board (BSEB)— CBSE

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CBSE-style · competency-based

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🧠 What you learned + equation sheet

What you learned

WhatKeep this
Least distance of distinct visionलगभग 25 cm (युवा सामान्य नेत्र)
Myopiaअवतल लेंस; प्रतिबिंब रेटिना से पहले
Hypermetropiaउत्तल लेंस; प्रतिबिंब रेटिना के पीछे
Dispersionबैंगनी सबसे अधिक, लाल सबसे कम
Atmospheric refractionसूर्योदय लगभग 2 मिनट पहले
Scatteringनीला आकाश; खतरे का संकेत लाल

The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.