The light-sensitive screen.
The lens forms an inverted real image on the retina.
Class 10 · Science · Chapter 10 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
The Human Eye and the Colourful World
How to use this page:
1. Read — Activities 10.1 and 10.2, diagram, worked example, board tip
2. Check — each lesson has its own questions; the number follows the lesson
3. Mastery ★ — all of that lesson correct. Redo the wrong ones
4. The picture to remember is a prism spectrum: violet bends the most and red the least.
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आँख के भाग और समंजन क्षमता · NCERT 10.1 · accommodation · near point 25 cm
The eyeball is roughly spherical and about 2.3 cm across. Light enters through a thin membrane, the cornea. Most of the bending happens at the outer surface of the cornea. The crystalline lens only makes the fine adjustment of focal length.
Behind the cornea is the iris. This dark muscular diaphragm changes the size of the pupil and so controls how much light enters. The lens forms an inverted, real image on the retina. Light-sensitive cells of the retina make electrical signals. The signals travel to the brain along the optic nerve.
| Part | Job |
|---|---|
| Cornea | Most of the refraction |
| Iris | Light amount through the pupil |
| Eye lens | Fine change of focal length |
| Retina | Inverted real image |
| Optic nerve | Signals to the brain |
The lens is a fibrous, jelly-like material. The ciliary muscles can change its curvature a little. When the muscles are relaxed the lens becomes thin, the focal length increases and a distant object is clear. For a nearby object the muscles contract, the lens thickens and the focal length decreases.
The focal length cannot be made shorter than a limit. The smallest distance for clear, comfortable vision is the least distance of distinct vision. It is also called the near point. For a young adult with normal vision it is about 25 cm. The far point is infinity. A page held closer than this looks blurred and the eye feels strained.
Question: What is the power of accommodation? What is the range of a normal eye?
Answer: It is the ability of the eye to focus near and distant objects on the retina by changing the focal length of the lens. A normal young eye sees clearly from 25 cm out to infinity.
In a BSEB definition write both words — ciliary muscle and focal length. “The eye shrinks” is incomplete.
CBSE often asks where the image is formed. The answer is the retina, not the cornea or the pupil.
The light-sensitive screen.
The lens forms an inverted real image on the retina.
The least distance of distinct vision.
For a normal young eye the near point is about 25 cm.
True — with relaxed muscles the lens is thin and the focal length increases.
The English word is accommodation.
It is called accommodation, or the power of accommodation.
Most of the refraction of the rays takes place at the cornea. The eye lens makes the fine adjustment of focal length so that the image falls on the retina.
For a distant object u is infinite, so f = v = 2.3 cm = 0.023 m. Formula P = 1/f. P = 1/0.023 = about 43.5 D. The unit is the dioptre.
निकट-दृष्टि और दूर-दृष्टि — कौन-सा लेंस · NCERT 10.2 · myopia · hypermetropia
In myopia nearby objects are clear and distant ones are not. The far point comes closer than infinity. The image of a distant object forms in front of the retina. Two causes are possible — the lens is too curved, or the eyeball has become too long. A concave lens of suitable power corrects it.
In hypermetropia distant objects are clear and nearby ones are not. The near point shifts farther than 25 cm. The image of a nearby object forms behind the retina. The cause is a focal length that is too long, or an eyeball that is too small. A convex lens of suitable power corrects it.
| Defect | Image | Lens |
|---|---|---|
| Myopia | In front of the retina | Concave |
| Hypermetropia | Behind the retina | Convex |
Question: A person cannot see objects clearly beyond 40 cm. Find the nature and the power of the lens.
Formula: 1/f = 1/v − 1/u and P = 1/f, with f in metres.
Signs: For a distant object u = −∞. The image must lie at the far point, so v = −40 cm = −0.40 m.
Substitution: 1/f = 1/(−0.40) − 0 = −2.5 m⁻¹. So f = −0.40 m and P = −2.5 D.
A negative power means a concave lens.
In a BSEB answer write all three — the name of the defect, where the image forms, and the lens.
A CBSE calculation asks for the signs. Without u at infinity and a negative v you will not get −2.5 D.
The image is forming in front of the retina and must be shifted back.
Myopia is corrected with a concave lens.
The eyeball is too small, or the focal length is too long.
In hypermetropia the image forms behind the retina. A convex lens brings it onto the retina.
False — the far point comes closer than infinity. The person sees clearly only up to a few metres.
Extra focusing power is needed.
Hypermetropia is corrected by a convex (converging) lens.
1/f = 1/v − 1/u. u = −∞, v = −0.40 m. 1/f = 1/(−0.40) = −2.5 m⁻¹. P = −2.5 D. The lens is concave.
जरा-दूरदर्शिता, द्विफोकसी लेंस और नेत्रदान · NCERT 10.2 · presbyopia · cataract · eye donation
For most people the near point slowly recedes with age. Nearby objects are no longer comfortable without glasses. This defect is presbyopia. The ciliary muscles gradually weaken and the lens loses flexibility.
Sometimes one person has both myopia and hypermetropia. Then a bifocal lens is used. The upper part is concave, for distant vision. The lower part is convex, for reading. These defects can also be corrected with contact lenses or by surgery.
In old age the lens sometimes becomes milky and cloudy. This is cataract. Vision may be lost in part or fully. Surgery can restore it.
The eyes must be removed within 4 to 6 hours of death. Inform the eye bank at once. Removal takes 10–15 minutes and does not disfigure the face. A donor may be of any age or sex. People who wear spectacles, and those who have had cataract surgery, can still donate.
A person infected with, or dead from, AIDS, hepatitis B or C, rabies, acute leukaemia, tetanus, cholera, meningitis or encephalitis cannot donate eyes. One pair of eyes can give vision to as many as four people with corneal blindness.
Question: The power of the lens for distant vision is −4.0 D and for near vision it is +2.5 D. Find both focal lengths.
Formula: f = 1/P, and f is in metres when P is in dioptres.
Substitution: Distant vision, f = 1/(−4.0) = −0.25 m = −25 cm. This is a concave lens.
Near vision, f = 1/(+2.5) = 0.40 m = 40 cm. This is a convex lens. In a bifocal the upper part is concave and the lower part is convex.
In a BSEB answer the bifocal sentence must not swap the upper and lower parts.
In the CBSE relation f = 1/P the sign of P stays with the focal length. The focal length for −4.0 D is negative.
The part for distant vision sits on top.
The upper concave lens is for distant vision. The lower convex lens is for near vision.
True — surgery can restore the vision.
It comes with age.
In presbyopia the ciliary muscles weaken and the lens becomes less flexible.
Within 4 to 6 hours of death. Donation is not possible in AIDS, hepatitis B or C, rabies, acute leukaemia, tetanus, cholera, meningitis or encephalitis.
f = 1/P = 1/(−2.0) = −0.50 m = −50 cm. A negative focal length is a concave lens. The upper part is for distant vision.
प्रिज्म से अपवर्तन — क्रियाकलाप 10.1 · NCERT 10.3 · Activity 10.1 · angle of deviation
The two faces of a glass slab are parallel, so the emergent ray stays parallel to the incident ray and only shifts sideways. The refracting faces of a prism are inclined to each other. The angle between the two lateral faces is the angle of the prism (∠A).
Because of the shape of the prism, the emergent ray bends at an angle to the direction of the incident ray. That angle is the angle of deviation (∠D).
Fix a sheet of white paper on a drawing board with drawing pins. Place a glass prism on its triangular base and trace the outline. Draw a straight line PE inclined to one refracting face, AB. Fix two pins, P and Q, on the line.
Look through the other face AC for the images of P and Q. Fix two more pins, R and S, so that R, S and the images of P and Q lie on one straight line. Remove the pins and the prism. PE meets the boundary at E. Join R and S and produce the line to meet the boundary at F. Join E and F.
Draw the normals at E and F. Mark the angle of incidence ∠i, the angle of refraction ∠r and the angle of emergence ∠e. PE is the incident ray, EF the refracted ray and FS the emergent ray. At the first face the ray goes from air into glass and bends towards the normal. At the second face it goes from glass into air and bends away from the normal.
Question: Why is the ray that leaves a prism not parallel to the incident ray?
Answer: The two refracting faces of a prism are not parallel. At the first face the ray bends towards the normal and at the second face it bends away from the normal. The two bends do not cancel. The angle left between the incident and emergent rays is the angle of deviation.
In a BSEB ray diagram name PE, EF, FS and the angles ∠i, ∠r, ∠e, ∠D. A diagram without names is counted incomplete.
CBSE asks how the emergent ray differs for a slab and a prism. Write parallel versus deviation in one sentence.
That angle is called the angle of deviation.
Because the faces are inclined, the emergent ray bends from the incident ray by the angle of deviation.
True — from a rarer to a denser medium the ray bends towards the normal.
The English word is deviation.
This is the angle of deviation ∠D. The angle of the prism ∠A is a different thing.
The alignment, while looking through the second face.
R and S fix the path of the emergent ray. They lie on one line with the images of P and Q.
At face AB the ray goes from air into glass and bends towards the normal. At face AC it goes from glass into air and bends away from the normal.
v = c/n = (3.0 × 108) / 1.50 = 2.0 × 108 m/s.
विक्षेपण और पुनर्योजन — क्रियाकलाप 10.2 · NCERT 10.4 · Activity 10.2 · the rainbow
Make a small hole or a narrow slit in the middle of a thick sheet of cardboard. Let sunlight fall on the slit so that you get a narrow beam of white light. Do not look straight at the sun; let the beam fall on the slit.
Take a glass prism and let this beam fall on one face. Turn the prism slowly until the light that comes out appears on a nearby screen. A beautiful band of colours appears. The order is violet, indigo, blue, green, yellow, orange and red — VIBGYOR. This band is called the spectrum. The splitting of white light into its component colours is dispersion.
Each colour bends through a different angle from the incident ray. Red bends the least and violet bends the most. So each colour leaves along its own path and stands apart on the screen.
Newton first obtained the spectrum of sunlight with a glass prism. A second prism used the same way did not split the colours any further. When a second identical prism was placed inverted relative to the first, all the colours passed through it and white light came out on the other side. Light that gives a spectrum like sunlight is called white light.
A rainbow forms in the sky after rain, in the direction opposite the sun. Tiny water drops act as prisms. They refract and disperse the sunlight, then reflect it inside the drop, and refract it again as it comes out. With the sun behind you, a rainbow can also be seen in a waterfall or a fountain.
Question: Which colours lie at the two ends of the spectrum, and what does a second inverted prism do?
Answer: Violet is at one end and bends the most. Red is at the other end and bends the least. A second prism placed inverted joins these colours into one beam, and white light comes out.
When you write VIBGYOR for BSEB, put violet first. Do not give red the larger deviation.
CBSE asks three steps for a rainbow — refraction, internal reflection, then refraction. “The drop is a prism” is only half the answer.
10-second revision
The end of the spectrum with the larger deviation.
Violet bends the most and red the least.
The coloured band of Activity 10.2.
This splitting is dispersion. The band of colours is the spectrum.
True — this is the recombination Newton observed.
The last colour of VIBGYOR.
Red bends the least. Violet bends the most.
The sun should be behind you.
A rainbow forms opposite the sun. The drops act as tiny prisms.
Wavelength of red = 1.8 × 400 = 720 nm. An inverted second prism joins the colours back into white light, so sunlight is made of seven colours. Violet has a greater deviation than red.
वायुमंडलीय अपवर्तन — टिमटिमाना और आगे का सूर्योदय · NCERT 10.5 · stars · planets · sunrise by 2 minutes
The hot air above a fire is lighter than the cooler air and has a slightly smaller refractive index. The medium does not stay still, so the apparent position of an object keeps wavering. That is atmospheric refraction on a small scale.
Starlight bends continuously in the atmosphere. Near the horizon a star appears slightly higher than its real position. The state of the atmosphere keeps changing, so the apparent position changes too. Stars are so far away that they behave as point sources. The light entering the eye is sometimes more and sometimes less — that is the twinkling.
Planets do not twinkle. They are nearer the earth and look like extended sources. The variations from a large number of point sources average out to zero.
Actual sunrise means the sun really crossing the horizon. Because of atmospheric refraction we see the sun about 2 minutes before the actual sunrise and about 2 minutes after the actual sunset. The apparent flattening of the sun disc at sunrise and sunset has the same cause.
Question: Stars twinkle and planets do not. Write one reason.
Answer: Atmospheric refraction acts on both. A star is a point source, so the flicker in its light reaches the eye. A planet is an extended source, so the flickers from different points average out.
For BSEB write both facts — the star appears higher, and the light flickers. The single word refraction is not enough.
The CBSE question on planets asks for a comparison. Write point source and extended source together.
10-second revision
Air whose refractive index keeps changing.
Twinkling of stars is due to atmospheric refraction.
False — planets are extended sources and the variations in their light average out to zero.
Sunset is seen about this much later as well.
The sun is seen about 2 minutes early at sunrise and about 2 minutes late at sunset.
Planets are nearer the earth and look like extended sources. The variation in light from a large number of points averages out to zero, so no twinkling is seen.
Extra time in one day = 2 + 2 = 4 minutes. Over 15 days, 15 × 4 = 60 minutes = 1 hour.
प्रकीर्णन — नीला आकाश, लाल सूर्यास्त और टिंडल · NCERT 10.6 · Tyndall · blue sky · red signal
The path of a beam through a true solution is not visible. In a colloidal solution the particles are larger, so the path of the beam becomes visible. Scattering of light by those particles produces this effect. It is called the Tyndall effect.
The atmosphere is a mixture of smoke, tiny water droplets, dust and molecules of air. A sunbeam entering a smoke-filled room through a small hole, or sunlight filtering through the mist of a dense forest, are examples. Very fine particles scatter mainly blue light. Larger particles scatter longer wavelengths. If the particles are large enough, the scattered light can even look white.
Molecules of air and other fine particles are smaller than the wavelength of visible light. They scatter the shorter waves at the blue end more than the longer waves at the red end. The wavelength of red light is about 1.8 times that of blue light. The scattered blue light enters our eyes, so the clear sky looks blue.
With no atmosphere there would be no scattering and the sky would look dark. Passengers flying very high see a dark sky. At sunrise and sunset the light travels a long path through the atmosphere. Blue is scattered away on the way, and the less-scattered red light reaches the eye. Danger signals are red for the same reason — fog or smoke scatters red the least, so the colour stays the same at a distance.
Question: Why does the sky look dark, not blue, to an astronaut?
Answer: The blue colour comes from scattering by fine particles in air. At a very great height that scattering is no longer effective. Without scattering the sky looks dark.
For BSEB join the blue sky and the red sunset with one rule — a shorter wavelength scatters more.
CBSE keeps Tyndall and dispersion apart. Tyndall is scattering by particles. Dispersion is the splitting of colours in a prism.
10-second revision
The particles are large enough for the path of the beam to show.
Colloidal particles scatter light and the path of the beam becomes visible. In a true solution the path is not seen.
The wavelength of red is about 1.8 times that of blue.
Fine particles in air scatter blue light more than red.
True — red keeps its colour over a long distance.
The colour with the least scattering.
Along the long path blue is scattered away and red light reaches the eye.
At sunset the light travels a long path through the atmosphere. Blue light of shorter wavelength is scattered away on the way, and the less-scattered red light reaches the eye. Fog or smoke also scatters red the least, so the signal stays red at a distance.
1 nm = 10−9 m. 720 nm = 720 × 10−9 m = 7.2 × 10−7 m.
Pick a type. The 39 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
The muscles that make the lens thin or thick.
The ciliary muscles change the curvature of the lens and so its focal length.
The lens only makes the fine adjustment.
Most of the refraction occurs at the outer surface of the cornea.
The near point of a normal young eye.
For a normal young eye it is about 25 cm. The far point is infinity.
Near is clear, far is blurred.
This is myopia and it is corrected by a concave lens.
The image forms behind the retina.
A convex lens provides the extra focusing power.
The lower part is used for reading.
The lower convex lens is for near vision. The upper concave lens is for distant vision.
Rarer to denser.
At the first face the ray goes from air into glass and bends towards the normal.
The first colour of VIBGYOR.
Violet bends the most and red the least.
A second prism the same way up neither splits the colours further nor joins them.
An inverted second prism recombines the colours and gives white light.
The drop works like a tiny prism.
The drop refracts, disperses, reflects internally and refracts again.
A point source and changing air.
Starlight bends continuously in the atmosphere and the light reaching the eye flickers.
Sunrise is also seen about this much earlier.
Atmospheric refraction keeps the sun visible for about 2 minutes more.
The shorter wavelength scatters more.
Fine particles scatter blue light more than red light.
The same colour should be seen from far away.
Red is scattered the least, so the signal stays red at a distance.
Colloidal particles make the path visible.
Smoke particles scatter the light and the path of the beam becomes visible.
True — the book gives this size.
False — 25 cm is the near point. The far point is infinity.
False — myopia uses a concave lens. A convex lens is for hypermetropia.
True — surgery can restore vision.
True — this is not so for a prism. There an angle of deviation remains.
False — violet bends the most and red the least.
False — a rainbow forms in the direction opposite the sun.
True — the blue colour comes from scattering.
The iris controls the amount of light through the pupil.
It is a dark muscular diaphragm.
For a normal young eye the near point is about 25 cm.
The least distance of distinct vision.
A concave lens brings the image of a distant object onto the retina.
The image has to be brought onto the retina.
The angle of the prism is between the two refracting lateral faces.
Not the triangular base.
The band of component colours is called the spectrum.
Dispersion produces this band.
The wavelength of red is about 1.8 times that of blue.
That is why blue scatters more.
The eyes must be removed within 4 to 6 hours.
Inform the eye bank at once.
Planets are extended sources and the variations average out.
A star is a point source.
Cornea refracts, the iris controls the pupil, the retina is the screen, the optic nerve carries signals.
Twinkling and advanced sunrise are refraction. The blue sky is scattering. The spectrum is dispersion.
Assertion (A): Myopia is corrected by a concave lens.
Reason (R): In this defect the image of a distant object forms in front of the retina.
Both are true and R is the correct explanation of A.
Assertion (A): The clear sky looks blue.
Reason (R): Red light is scattered more than blue light.
A is true. R is false — blue is scattered more, red less.
Assertion (A): In a prism violet light bends the least.
Reason (R): Different colours have different deviations.
A is false — violet bends the most. R is true.
Assertion (A): Planets do not twinkle.
Reason (R): Sunrise appears about 2 minutes early because of atmospheric refraction.
Both are true, but R does not explain A. They are separate facts.
Assertion (A): Danger signals are red.
Reason (R): Red light is scattered the least by fog or smoke.
Both are true and R is the correct reason.
Myopia is concave. Hypermetropia, and the near part of presbyopia, are convex. A normal eye needs no lens.
The band is dispersion. The blue sky and Tyndall are scattering. Twinkling is atmospheric refraction.
Accommodation is the ability to focus near and distant objects on the retina by changing the focal length of the eye lens.
The near point is about 25 cm. The far point is infinity.
Dispersion is the splitting of white light into its component colours. The band of those colours is called the spectrum.
Scattering of light by colloidal particles makes the path of a beam visible. This is the Tyndall effect.
The angle of deviation is the angle between the ray leaving the prism and the direction of the incident ray.
The lens may be too curved, or the eyeball may be too long. The image of a distant object forms in front of the retina. A concave lens of suitable power brings the image onto the retina.
In hypermetropia the near image forms behind the retina because the focal length is too long or the eyeball is too small. A convex lens is used. Presbyopia comes with age, when the ciliary muscles weaken and the lens is less flexible. If both defects occur together, a bifocal lens is used.
A narrow beam of white light leaves the prism as a band of colours. The order is VIBGYOR — violet, indigo, blue, green, yellow, orange and red. Violet bends the most and red the least.
Actual sunrise is the moment the sun crosses the horizon. The atmosphere bends the rays so that the sun is seen even while it is still below the horizon. The difference is about 2 minutes. Sunset is also seen about 2 minutes late.
Light enters through the cornea, where most of the refraction occurs. The iris controls the amount of light through the pupil. The lens fine-focuses and forms an inverted real image on the retina. Signals go to the brain along the optic nerve. In accommodation the ciliary muscles make the lens thin or thick. With relaxed muscles the focal length increases and a distant object is clear. With contracted muscles the focal length decreases and a nearby object is clear. The near point is about 25 cm.
The formula is 1/f = 1/v − 1/u and P = 1/f. For a distant object u = −∞ and v = −2 m. 1/f = 1/(−2) − 0 = −0.5 m⁻¹. P = −0.5 D. The unit is the dioptre. The concave lens forms the image of a distant object at the far point, so that it falls on the retina.
Fine particles scatter a shorter wavelength more. The wavelength of red is about 1.8 times that of blue, so blue scatters more and the sky looks blue. At sunset the long path scatters blue away and red reaches the eye. Fog also scatters red the least, so a danger signal stays red at a distance. With no atmosphere the sky would look dark.
This model set is for practice. It is not an annual examination paper of any year.
A distant object is not clear.
This is myopia. A concave lens is used.
Reading matter has to be held farther than 25 cm.
The near point shifts farther than the normal 25 cm.
VIBGYOR — from violet to red.
The first letters of the seven English colour names.
Yes. Spectacles, cataract surgery, diabetes or hypertension do not stop eye donation, unless the person is on the excluded list of communicable diseases.
u = −0.25 m, v = −0.50 m. 1/f = 1/v − 1/u = 1/(−0.50) − 1/(−0.25) = −2 + 4 = +2 m⁻¹. P = +2 D. The lens is convex.
In 10.1 a ray passes through the prism and bends from its direction by the angle of deviation. It bends towards the normal at the first face and away from the normal at the second. In 10.2 white light splits into a band of colours. Deviation is the angle by which the whole beam bends. Dispersion is the splitting of colours through different angles, violet bending the most and red the least.
These are competency-based practice questions. They are not a past paper and not a copy of a CBSE paper.
A negative power is a concave lens.
Myopia needs a concave lens. −0.5 D is concave.
A rainbow forms opposite the sun.
A water drop, like a tiny prism, refracts, disperses and reflects the light internally.
Assertion (A): A student in the last row cannot read the board.
Reason (R): The student has myopia and a concave lens can correct the defect.
Both are true and R is the correct reason.
Assertion (A): At a very great height the sky looks dark.
Reason (R): At that height dispersion stops because there is no prism.
A is true. R is false — the reason is that scattering becomes weak, not dispersion.
This is hypermetropia. The image of a nearby object forms behind the retina. A convex lens of suitable power is used.
The first prism splits white light into a spectrum and the inverted second prism joins the colours. This shows that white light is made of seven colours. Violet has a larger deviation than red, so it separates to the other end of the band.
Switch board with BSEB | CBSE above. The lessons follow the same NCERT chapter.
This page has no verified annual-exam question, because no source page has been added. The model set below is practice in the board pattern.
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What you learned
| What | Keep this |
|---|---|
| Least distance of distinct vision | लगभग 25 cm (युवा सामान्य नेत्र) |
| Myopia | अवतल लेंस; प्रतिबिंब रेटिना से पहले |
| Hypermetropia | उत्तल लेंस; प्रतिबिंब रेटिना के पीछे |
| Dispersion | बैंगनी सबसे अधिक, लाल सबसे कम |
| Atmospheric refraction | सूर्योदय लगभग 2 मिनट पहले |
| Scattering | नीला आकाश; खतरे का संकेत लाल |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.