The resultant is zero.
The forces are balanced, so the block does not move.
Class 9 · Science · Chapter 9 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Force and Laws of Motion
How to use this page:
1. Read — 9.1 carom · 9.2 coin · 9.3 tray · 9.4 carts · 9.5 balloon · 9.6 cork, diagram, worked example, board tip
2. Check — each lesson has its own questions; the number follows the lesson
3. Mastery ★ — all of that lesson correct. Redo the wrong ones
4. The memory figure shows two trolleys before and after a collision, with momentum arrows, when no outside unbalanced force acts.
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संतुलित और असंतुलित बल · Section 9.1 · friction
A push, a pull or a hit is the everyday idea of a force. A force can start an object, stop it, change its direction, or change its shape. A spring stretches and a rubber ball becomes oblong when it is pressed.
If strings X and Y on opposite faces of a block are pulled equally, the block does not move. Such forces are balanced. If the pull on one side is larger, the block moves that way. That force is unbalanced.
Only an unbalanced force changes rest or uniform motion. On a rough floor a small push is cancelled by friction, so the box does not slide. The moment the push exceeds friction, the box starts. Stop pedalling a bicycle and friction slows it. If friction were removed, the object would keep the speed it had already gained.
| Case | Forces | Result |
|---|---|---|
| X and Y equal | Balanced | Block stays |
| Larger pull one side | Unbalanced | Motion to that side |
| Push = friction | Balanced | Box stays put |
Question: Two children push a box from opposite sides with 40 N and 40 N. Why does the box not move?
Answer: The two forces are equal and opposite, so the resultant is zero. The forces are balanced. The state of motion does not change.
Write that balanced forces give no acceleration. Only “a force acts” stays incomplete.
Remember figure 9.4: a small push is balanced, a larger push is unbalanced.
The resultant is zero.
The forces are balanced, so the block does not move.
True — then the box does not slide.
Balanced forces do not do this job.
An unbalanced force.
Between the floor and the wheels.
Friction is opposite to the motion, so the speed falls.
Balanced forces have zero resultant and do not change the state of motion. An unbalanced force has a non-zero resultant and changes speed or direction.
प्रथम नियम — क्रियाकलाप 9.1 · Section 9.2 · Activity 9.1
Galileo watched a marble on an inclined plane. Rolling down, its speed rises. Rolling up, its speed falls. If the two planes are level and there is no friction, the marble does not change its speed.
An object stays at rest, or in uniform motion in a straight line, until an unbalanced force compels a change. That is the first law. The resistance to a change of state is inertia, so the law is also called the law of inertia.
If a bus stops suddenly the body wants to keep moving forward, so the passenger leans forward. A seat belt puts a force on the body and slows that forward motion. If the bus starts suddenly the feet move forward with the floor and the rest of the body stays back by inertia. On a sharp turn the body wants to keep going straight.
Make a pile of similar carom coins on a table. Give the bottom coin a sharp horizontal hit with the striker. If the hit is fast enough, only the bottom coin moves out. The coins above fall straight down onto the table because of their inertia. They do not run off horizontally with the striker.
Question: Why does a passenger fall forward when a moving bus brakes?
Answer: The brakes reduce the speed of the bus. The body of the passenger keeps its earlier motion because of inertia, so the passenger leans forward.
In the definition write both rest and uniform straight motion. Only rest stays incomplete.
Write the two bus cases apart: stopping throws you forward, a sudden start throws you back.
Only the bottom coin leaves.
The upper coins keep their rest by inertia and fall straight down.
True — inertia is the resistance to a change of state.
The body keeps the old motion.
Forward.
The conclusion of Galileo.
With no unbalanced force the speed does not change.
True — to reduce injury when the vehicle stops suddenly.
An object stays at rest or in uniform motion in a straight line until an unbalanced force changes that state. If a moving bus stops suddenly, the body keeps moving forward, so the passenger leans forward.
जड़त्व और द्रव्यमान — क्रियाकलाप 9.2 और 9.3 · Section 9.3 · Activities 9.2 · 9.3
9.2 Cover an empty glass with a stiff card and place a five-rupee coin on the card. Flick the card sharply sideways. The card flies off and the coin falls straight into the glass because of inertia. It does not run off with the card.
9.3 Place a water-filled tumbler on a tray and turn around fast with the tray. The water spills, because the water resists the change of state. A groove in a saucer keeps the cup from toppling in a sudden jerk.
Inertia is not the same in every object. An empty box is easy to push. A box full of books is hard. A football of a given size flies off. The same force on a stone of that size hardly moves the stone, and the foot can be hurt.
Mass is the measure of inertia. The SI unit is the kg. A heavier object has more inertia. A train has more inertia than a bicycle, so a force that gives a small cart a large speed makes almost no change in the train. Shake a branch hard and some leaves come off, because the branch moves and the leaves want to stay where they were.
Question: A rubber ball and a stone have the same size. Which has more inertia?
Answer: The stone has more mass, so it has more inertia. Mass is the measure of inertia.
With the definition of inertia, also write the unit kg.
A five-rupee coin is heavier than a one-rupee coin, so its inertia is larger.
Look at the mass.
The train has the greatest mass, so it has the greatest inertia.
False — the coin falls straight into the glass by inertia.
The SI unit is the kg.
Mass.
The branch moves. The leaves want to keep their state of rest by inertia, so some leaves come off. When the tray turns fast, the water also resists the change of state and spills.
संवेग और द्वितीय नियम — F = ma · Section 9.4 · formulas 9.1 to 9.5
A table-tennis ball does not hurt. A fast cricket ball can. A parked truck looks harmless. A truck moving even slowly can be dangerous. The effect depends on both mass and velocity.
Momentum is p = mv. Its direction is the direction of the velocity. The SI unit is kg m s⁻¹. An unbalanced force changes momentum.
The second law: the rate of change of momentum is proportional to the applied unbalanced force, in the direction of the force. For mass m, initial velocity u, final velocity v and time t, the change is m(v − u). The rate is m(v − u)/t = ma. In SI the constant of proportion is chosen as 1, so F = ma. 1 N = 1 kg m s⁻². If F = 0, then v stays equal to u. That is the mathematical form of the first law.
Question: A force acts for 2 s on an object of 5 kg. The velocity rises from 3 m s⁻¹ to 7 m s⁻¹. Find the magnitude of the force.
Formula: F = m(v − u)/t
Substitution: F = 5 kg × (7 − 3) m s⁻¹ / 2 s = 5 × 4 / 2
Answer: F = 10 N.
If this same 10 N acts for 5 s and u = 3 m s⁻¹, then v = u + Ft/m = 3 + (10 × 5)/5 = 13 m s⁻¹.
In a numerical write the formula, the values and the unit. Writing only 10 stays incomplete.
Remember the definition of 1 N: an acceleration of 1 m s⁻² in 1 kg.
p = mv.
kg times m s⁻¹, that is kg m s⁻¹. The newton is the unit of force.
k = 1.
F = ma.
False — the direction of momentum is the direction of the velocity.
Find both from F = ma.
F1 = 2 × 5 = 10 N and F2 = 4 × 2 = 8 N. The first force is larger.
Formula m = F/a. m1 = 5/10 = 0.50 kg. m2 = 5/20 = 0.25 kg. Total m = 0.75 kg. a = F/m = 5 N / 0.75 kg = 6.67 m s⁻².
तृतीय नियम — क्रियाकलाप 9.4 · Section 9.5 · Activity 9.4
Every action has an equal and opposite reaction, and the two forces act on two different objects. Join two spring balances. Fix one end to a wall. Whatever one balance pulls, the other shows the same amount the opposite way.
To walk, you push the road backward. The road pushes your foot forward. When a sailor jumps forward from a boat, the boat moves back. A gun pushes the bullet forward. The bullet pushes the gun backward with an equal force, so the gun recoils. The bullet has a small mass, so its acceleration is very large. The forces are equal. The accelerations need not be equal.
Let two children stand on two separate carts. Give them a bag of sand and ask them to play catch. Throwing the bag is the action. The child who throws gets an immediate opposite reaction and that cart moves back. A white line on the wheels makes the motion easy to see.
Then place two children on one cart and one child on the other. The accelerations differ even though the force is of the same kind. That is the second law, because the masses differ. The cart can be plywood of about 50 cm × 100 cm with ball-bearing wheels. A skateboard makes a straight line hard to keep.
Question: A massive truck parked by the road does not move when you push it. Did action and reaction cancel on one object?
Answer: No. Your push is on the truck and the push of the truck is on you. They are on two objects, so they do not cancel each other to zero. The huge mass of the truck makes the acceleration very small.
Always write that action and reaction do not act on the same object.
Give the gun and bullet pair with a sketch. Acceleration is inverse to the mass.
10-second revision
You push the road backward.
The road exerts an equal forward reaction on the foot.
False — they act on two different objects.
Figure 9.12.
Backward.
F is equal, and a = F/m.
The forces are equal. The bullet has a small m, so a is large.
True — even for the same kind of force, different masses give different accelerations.
Every action has an equal and opposite reaction, and they act on two different objects. The forces on the gun and the bullet are equal. The bullet has a small mass, so by a = F/m its acceleration is very large and the gun moves back slowly.
संवेग संरक्षण — क्रियाकलाप 9.5 और 9.6 · Section 9.6 · Activities 9.5 · 9.6
Two balls A and B move on one straight line with velocities uA and uB, and uA is larger. During the short collision time t, A exerts FAB on B and B exerts FBA on A. By the third law, FAB = −FBA.
From this, mA uA + mB uB = mA vA + mB vB, provided no external unbalanced force acts. The total momentum before the collision equals the total momentum after it. This is conservation of momentum. A conservation law is checked by experiment. It is not treated as proved by one experiment.
9.5 Inflate a large balloon and tie the neck. Tape a straw on the surface and pass a thread through the straw. Hold both ends. Open the neck. The escaping air goes one way and the straw moves the opposite way.
9.6 This is a teacher demonstration. Put a little water in a good glass test tube and fit a cork. Hang the tube horizontally on two strings. Heat it until steam blows the cork out. The tube recoils opposite to the cork. The cork is light, so its speed looks larger than the backward speed of the tube. Do not point the mouth toward a face.
Question: A bullet of 20 g moves at 150 m s⁻¹. The pistol has mass 2 kg. Both start at rest. Find the recoil velocity of the pistol.
Formula: m1 v1 + m2 v2 = 0, because the total momentum was zero before.
Substitution: 0.02 kg × 150 m s⁻¹ + 2 kg × v = 0, so 3 + 2v = 0.
Answer: v = −1.5 m s⁻¹. The negative sign means the direction opposite to the bullet.
Write the direction of the negative sign in a sentence. Only −1.5 stays incomplete.
In both 9.5 and 9.6 the light part moves fast and the heavy part moves slowly.
10-second revision
The system is isolated.
Total momentum does not change only when there is no external unbalanced force.
False — the balloon moves opposite to the air.
3 + 2v = 0.
1.5 m s⁻¹, opposite to the bullet.
Formula: 40 × 5 + 3 × 0 = (40 + 3) v. Substitution: 200 = 43 v. v = 200/43 = 4.65 m s⁻¹, in the direction of the jump.
समय बढ़ाओ तो बल घटता है · Second law · everyday cases
F = (mv − mu)/t. If the change of momentum is fixed, a larger time t means a smaller force.
While catching a fast ball, a fielder draws the hands back with the ball. The ball gets more time to stop, the acceleration falls, and the force of the impact on the hands falls. In a high jump a cushion or sand also increases the time and decreases the force.
A negative sign means the force is opposite to the motion. The force of the brakes is opposite to the velocity of the car.
Question: A car of 1000 kg moves at 108 km/h and stops in 4 s after the brakes are applied. Find the force of the brakes.
Formula: F = m(v − u)/t, and 108 km/h = 108 × 1000/3600 = 30 m s⁻¹.
Substitution: F = 1000 kg × (0 − 30) m s⁻¹ / 4 s = −30000/4.
Answer: F = −7500 N. The negative sign means the force is opposite to the motion.
Change km/h into m/s by multiplying by 5/18, then use the formula.
Write a negative force in words as “opposite to the motion”.
10-second revision
F = Δp / t.
A longer time makes the same change of momentum need a smaller force.
True — 108 × 5/18 = 30.
1000 × (0 − 30) / 4.
−7500 N, opposite to the motion.
The same idea as in a catch.
The stopping time increases, so the force decreases.
0 = 20² + 2a(50). 0 = 400 + 100a. a = −4 m s⁻². F = ma = 1 × (−4) = −4 N. Friction is 4 N opposite to the motion.
Pick a type. The 35 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
The resultant is zero.
The forces are balanced, so the state does not change.
A heavier object resists more.
Mass is the measure of inertia. The unit is the kg.
The feet go forward, the body stays back.
By inertia the body stays back.
Momentum is a vector.
The direction of momentum is the direction of velocity.
F = ma.
1 N = 1 kg × 1 m s⁻².
The first law from the second.
If the force is zero the velocity does not change.
F = ma.
F = 10 N.
The third law.
The bullet pushes the gun backward.
Activity 9.4.
The throw is the action. The cart moves back by the reaction.
3 + 2v = 0.
v = −1.5 m s⁻¹.
200 = 43v.
v = 200/43 = 4.65 m s⁻¹.
F = Δp/t.
Larger time, smaller force.
m(v−u)/t.
F = 1000 × (0−30)/4 = −7500 N.
The branch moves.
The leaves want to keep their state of rest.
False — the resultant is zero, so there is no acceleration.
True — the SI unit is the kg.
False — the direction is the direction of the velocity.
True — the unit is chosen from F = ma.
False — they act on two different objects.
True — this is conservation of momentum.
False — the tube recoils opposite to the cork.
False — by F = Δp/t the force decreases.
Its state.
The first law.
mv.
The direction is that of the velocity.
The newton.
kg m s⁻².
m s⁻².
The rate of change of velocity.
Backward.
Figure 9.12.
mA vA + mB vB.
The later velocities are v.
0.02 kg.
1000 g = 1 kg.
7500 N.
The sign is negative.
Momentum is kg m s⁻¹, force uses the newton, mass is the kg, and 1 N = 1 kg m s⁻².
9.1 is the straight fall, 9.2 the glass, 9.5 opposite the air, 9.6 opposite the cork.
Assertion (A): An unbalanced force can change the speed of an object.
Reason (R): An unbalanced force gives an acceleration.
Both are true and R explains A.
Assertion (A): Mass is the measure of inertia.
Reason (R): The unit of momentum is the newton.
A is true. R is false — the unit of momentum is kg m s⁻¹, not the newton.
Assertion (A): Drawing the hands back while catching a fast ball reduces the hurt.
Reason (R): A shorter time also decreases the force.
A is true. R is false — the force falls when the time increases, not when it decreases.
Assertion (A): Action and reaction cancel on the same object.
Reason (R): These forces act on two different objects.
A is false. R is true.
Assertion (A): With no external force the total momentum of two balls does not change in a collision.
Reason (R): During the collision the action and the reaction are equal and opposite.
Both are true and R explains this conservation.
Equal pulls and a resting book are balanced. A push past friction, and the brakes, are unbalanced.
Carom is inertia, F = ma is the second law, the gun is the third law, and total p is conservation.
Inertia is the tendency of an object to resist a change in its state of rest or of uniform motion.
Momentum is the product of mass and velocity, p = mv. Its direction is the direction of the velocity. The SI unit is kg m s⁻¹.
1 newton is the force that produces an acceleration of 1 m s⁻² in a mass of 1 kg.
If the bus stops, starts or turns suddenly, the luggage wants to keep its state by inertia and can fall. The rope holds it by an unbalanced force.
No external unbalanced force should act on the system.
u = 0, s = ut + ½at². 400 = ½ a × 400. a = 2 m s⁻². m = 7000 kg. F = ma = 7000 × 2 = 14000 N.
m = 0.2 kg. Take the forward direction as positive. u = 10, v = −5. Δp = m(v − u) = 0.2(−5 − 10) = −3 kg m s⁻¹. The magnitude is 3 kg m s⁻¹, opposite to the initial velocity.
F = ma = 1500 × (−1.7) = −2550 N. The magnitude is 2550 N, opposite to the motion.
Take one direction as positive. Total p = 1.5×2.5 + 1.5×(−2.5) = 0. After they stick, the total momentum is still 0, so the common velocity is 0.
First: without an unbalanced force an object stays at rest or in uniform straight motion. Second: the rate of change of momentum is proportional to the unbalanced force. Third: action and reaction are equal, opposite and on two objects. Put F = 0 in F = m(v−u)/t and v = u. The action is on one object and the reaction on the other, so they do not form a cancelling pair on one object.
Total momentum before = 60×5 + 55×(−6) = 300 − 330 = −30 kg m s⁻¹. After, (60+55)v = 115v. 115v = −30. v = −30/115 = −0.26 m s⁻¹. The direction is from right to left, the initial direction of the second player.
The forces on the insect and the car are equal and opposite, because they are an action-reaction pair. The changes of momentum also have equal magnitude. The velocity of the insect changes a lot because its mass is small, so it is killed. It is wrong to say that the change of momentum of the insect is larger, or that the car exerted a larger force because its speed was larger.
This model set is for practice. It is not a question from any year’s annual examination.
The first law.
If the force is zero, rest continues. A uniform velocity is also possible if it was already moving.
The carpet moves.
The dust wants to keep its state.
200 N, in the opposite direction.
Constant velocity means zero acceleration.
Yes. The velocity can be non-zero, but both its magnitude and its direction must stay constant. That is uniform straight-line motion.
m = 0.01 kg. a = (0 − 150)/0.03 = −5000 m s⁻². F = ma = 0.01 × (−5000) = −50 N. The magnitude is 50 N. Distance s = ut + ½at² = 150×0.03 + ½(−5000)(0.03)² = 4.5 − 2.25 = 2.25 m.
Mass of the wagons = 5×2000 = 10000 kg. Total mass with the engine = 18000 kg. Net force = 40000 − 5000 = 35000 N. a = F/m = 35000/18000 = 1.94 m s⁻².
These are competency-based practice questions. They are not copies of a CBSE paper.
Figure 9.4.
Friction balances the push.
F = m(v−u)/t.
F = 100×(8−5)/6 = 50 N.
Assertion (A): A heavy truck parked on the road does not move under a small push.
Reason (R): Action and reaction cancel on the same object.
A is true. R is false — the two forces are on different objects. The large mass of the truck makes the acceleration negligible.
Assertion (A): When air leaves a balloon, the balloon moves in the opposite direction.
Reason (R): If the external horizontal force is negligible, total momentum stays conserved.
Both are true and R explains A.
If no unbalanced force acts, the ball keeps a uniform velocity. It stops because friction opposes the motion. Rest is not a special natural state.
Before, p = 1×10 + 5×0 = 10 kg m s⁻¹. With no external force the total momentum after is also 10 kg m s⁻¹. (1+5)v = 10. v = 10/6 = 1.67 m s⁻¹.
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What you learned
| What | Keep this |
|---|---|
| Momentum | p = mv, unit kg m s⁻¹ |
| Force | F = ma, unit newton N |
| 1 newton | 1 kg × 1 m s⁻² |
| First law | F = 0 means v stays u |
| Third law | FAB = −FBA, two bodies |
| Conservation | mA uA + mB uB = mA vA + mB vB |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.