On one side they are not adjacent.
On opposite sides of the common arm.
Class 9 · Maths · Chapter 6 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Lines and Angles
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1. Read — Terms · linear pair · vertically opposite · Exercise 6.1 · transversal · corresponding · alternate · co-interior · Exercise 6.2 · angle sum · Exercise 6.3, diagram, worked example, board tip
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4. The memory figure shows two parallel lines cut by a transversal, with one pair of alternate angles marked equal.
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रेखा, कोण और आसन्न कोण · Textbook 6.2 · adjacent · complementary
A piece with two ends is a segment. A ray has one end. A line runs both ways. The book may write the segment, the ray, the length and the line all as AB. Take the meaning from the sentence. Three or more points on one line are collinear, otherwise non-collinear.
Two rays from one endpoint make an angle. Acute is between 0° and 90°, a right angle is exactly 90°, obtuse is between 90° and 180°, a straight angle is 180°, and reflex is between 180° and 360°. If the sum is 90° they are complementary. If the sum is 180° they are supplementary. Adjacent angles share the vertex and one arm, and the other arms lie on opposite sides of the common arm.
Question: One angle is 35°. Find its complement and its supplement.
Relations: complement = 90° − the given angle. Supplement = 180° − the given angle.
Substitution: complement = 90° − 35° = 55°. Supplement = 180° − 35° = 145°.
Swapping 90° and 180° for complement and supplement is the common slip. Write both words in the answer.
Do not write a sum of 180° just because the angles are adjacent. That condition belongs to a linear pair.
On one side they are not adjacent.
On opposite sides of the common arm.
False — a sum of 90° is complementary. Supplementary angles add to 180°.
A right angle is 90°.
180°.
Subtract from 90.
90° − 70° = 20°.
A common vertex, a common arm, and the other arms on opposite sides of the common arm. No. A linear pair exists only when the other arms form a line.
रैखिक युग्म — अभिगृहीत 6.1 और 6.2 · Textbook 6.4 · linear pair axiom
Axiom 6.1: if a ray stands on a line, the two adjacent angles formed add to 180°. Such angles are a linear pair. The converse is Axiom 6.2: if two adjacent angles add to 180°, their non-common arms form a line. Together they are called the linear pair axiom.
A converse swaps the given fact and the conclusion. In 6.1, “the ray stands on a line” is given and the sum is the conclusion. In 6.2 the sum is given and the line is the conclusion. Both are axioms here, not theorems.
Question: One angle of a linear pair is 65°. Find the other.
Axiom: a linear pair adds to 180°.
Substitution: the other = 180° − 65° = 115°.
Both 6.1 and 6.2 are axioms. Writing the converse as a theorem is wrong in this chapter.
In the 115° answer show 180° − 65°. Only 115° can lose half the marks.
A straight angle.
180°.
True — this is Axiom 6.2.
Subtract from 180.
140°.
If a ray stands on a line, the adjacent angles add to 180°. The converse: if adjacent angles add to 180°, the other arms form a line. Both are the linear pair axiom.
शीर्षाभिमुख कोण — प्रमेय 6.1 · Textbook 6.4 · Theorem 6.1 · Exercise 6.1
Two lines crossing at O make two pairs of vertically opposite angles. Theorem 6.1: they are equal. The proof uses a linear pair. One angle makes 180° with each neighbour. Subtract the same angle and the facing angles are left equal.
In a ratio question, take the 180° of the linear pair first, then share the parts. A vertically opposite angle repeats that measure across the crossing. It does not create a new measure.
Question: Two lines cross at O. ∠POR : ∠ROQ = 5 : 7. Find all four angles.
Linear pair: ∠POR + ∠ROQ = 180°. The parts are 5 + 7 = 12.
Substitution: ∠POR = (5/12) × 180° = 75°. ∠ROQ = (7/12) × 180° = 105°.
Vertically opposite: the facing angles are also 105° and 75°.
Do not multiply each part of the ratio by 180°. First take the sum of the parts, 12, then 5/12 and 7/12.
If four angles are asked, write the vertically opposite repeats. Only two angles are half an answer.
Theorem 6.1.
Equal.
True — both neighbouring pairs are 180°.
5/12 × 180.
75°. The larger is 105°.
The facing measure is the same.
105°. The neighbour is 75°.
The vertically opposite angle is 40°. Each neighbour, from a linear pair, is 180° − 40° = 140°. The four angles are 40°, 140°, 40° and 140°.
False — the sum is 180°. The angles are 75° and 105°.
तिर्यक और संगत कोण · Textbook 6.5 · Axiom 6.3
A line that cuts two or more lines at distinct points is a transversal. Four angles appear at each cut. Those outside the strip are exterior and those between are interior. Angles in the same position are corresponding.
The perpendicular distance between parallel lines is the same everywhere. Axiom 6.3: if a transversal cuts parallel lines, each corresponding pair is equal. The converse also holds: if one corresponding pair is equal, the lines are parallel.
Draw parallels along two ruled lines of the notebook and cut them with a transversal. Measure a corresponding pair. They come out equal. This is not a numbered activity. The book says to repeat the checks of earlier classes here. A measurement does not replace the axiom, but it makes the figure clear.
Question: m ∥ n and one corresponding angle on the transversal is 72°. Find its corresponding partner and the co-interior partner.
Axiom 6.3: the corresponding partner = 72°.
Co-interior: 180° − 72° = 108°.
Corresponding angles are not alternate angles. Look at the same position, not the crossed place inside the strip.
When the converse is used to prove parallel, one pair is enough. Measuring all four pairs is not required.
The cuts are separate.
It cuts two or more lines at distinct points.
True — Axiom 6.3.
180 − 72.
108°.
The converse of 6.3.
The lines are parallel.
I will draw two parallel ruled lines and a transversal and measure one corresponding pair. Equal measures are linked to Axiom 6.3. The measurement itself is not the proof.
एकांतर और सह-आंतरिक कोण · Textbook 6.5 · Theorems 6.2 to 6.5
Inside the strip, angles on opposite sides of the transversal are alternate interior angles. The book sometimes calls them only alternate angles. Interior angles on the same side are co-interior. They are also called consecutive interior angles or allied angles.
If the lines are parallel, alternate angles are equal and co-interior angles add to 180°. Theorems 6.2 and 6.4 say this. The converses 6.3 and 6.5 prove the lines parallel. One pair is enough.
Question: m ∥ n. One alternate interior angle is 65°. Find the other alternate and the co-interior angle.
Theorem 6.2: the other alternate = 65°.
Theorem 6.4: co-interior = 180° − 65° = 115°.
Do not write co-interior angles as equal. Their sum is 180°. Alternate and corresponding angles are the equal ones.
On the figure an alternate pair is inside the strip on opposite sides of the transversal. A corresponding pair sits in the same position.
10-second revision
Theorem 6.2.
Equal.
True — Theorem 6.4.
180 − 65.
115°.
Theorem 6.5.
The lines are parallel.
The co-interior angle = 180° − 110° = 70°, Theorem 6.4. The alternate partner = 110°, Theorem 6.2.
False — alternate angles are on opposite sides and are equal. Co-interior angles are on the same side and are supplementary.
एक ही रेखा के समांतर रेखाएँ · Textbook 6.6 · Theorem 6.6 · Exercise 6.2
Theorem 6.6: lines which are parallel to the same line are parallel to each other. The same fact runs for more than two lines. A helper parallel is drawn and corresponding or alternate angles are matched.
An exercise often gives one angle 135° and another 40° and asks for the angle between. The helper line makes a co-interior or alternate link with both parallels. 180° − 135° = 45°, then 45° + 40° = 85°. The unit is the degree.
Question: PQ ∥ RS. One co-interior angle is 135° and a further alternate angle is 40°. Find the angle between.
Step: 180° − 135° = 45°. This is the piece on the helper line.
Sum: 45° + 40° = 85°.
Do not add 135° straight to 40°. First find 180° − 135° = 45°, then add 40°.
Do not write “both are parallel” for Theorem 6.6 without the reason. Write that both are parallel to a third line.
10-second revision
Theorem 6.6.
m ∥ n.
False — the book says the fact also runs for more than two lines.
45 + 40.
85°.
AB ∥ EF, because lines parallel to the same line are parallel to each other. This is Theorem 6.6.
त्रिभुज का कोण योग और बाह्य कोण · Textbook 6.7 · Theorem 6.7 · Theorem 6.8 · Exercise 6.3
Theorem 6.7: the three angles of a triangle add to 180°. In the proof a line is drawn through a vertex parallel to the opposite side. Alternate angles match the other two angles, and the three make a straight angle.
Theorem 6.8: if a side is extended, the exterior angle equals the sum of the two interior angles far from it. So it is greater than each of those two. In a right triangle, 90° + one angle + the other = 180°.
Question: Two angles of a triangle are 50° and 60°. Find the third and the exterior angle far from them.
Theorem 6.7: 50° + 60° + x = 180°, so x = 70°.
Theorem 6.8: exterior angle = 50° + 60° = 110°.
Do not write the exterior angle equal to the interior angle beside it. It makes 180° with that one as a linear pair. The two far angles are the ones that add.
70° and 110° are two parts of one answer. Writing only the third angle leaves out the exterior-angle part.
10-second revision
Theorem 6.7.
180°.
False — with the next angle it is a linear pair. The exterior angle equals the sum of the two far interior angles.
180 − 110.
70°.
The sum of both.
50° + 60° = 110°.
90° + 35° + y = 180°, so y = 55°. The exterior angle = 35° + 55° = 90°, by Theorem 6.8.
Pick a type. The 35 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
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Opposite sides of the common arm.
On opposite sides.
From 180.
140°.
Axiom 6.1.
180°.
Theorem 6.1.
Equal.
7/12 × 180.
105°.
Axiom 6.3.
Equal.
Theorem 6.2.
Equal.
Theorem 6.4.
180°.
Theorem 6.6.
m ∥ n.
Theorem 6.7.
180°.
Theorem 6.8.
The sum of the two far interior angles.
The converse.
Parallel.
First 45, then add 40.
85°.
False — 180° is the condition for a linear pair.
True — together they are called the linear pair axiom.
False — Theorem 6.1 says they are equal. Their neighbours are supplementary.
False — the cuts are at distinct points.
False — their sum is 180°.
True — Theorem 6.6.
False — it equals the sum of both far interior angles.
True.
90.
Supplementary is 180.
115.
180 − 65.
75.
5/12 × 180.
6.3.
The linear pair is 6.1 and 6.2.
115.
180 − 65.
70.
180 − 110.
110.
50 + 60.
85.
45 + 40.
Corresponding and alternate are equal, co-interior are supplementary, and vertically opposite are equal at a crossing.
6.1 is the linear pair, 6.3 corresponding, 6.6 parallelism, and 6.7 the angle sum.
Assertion (A): A linear pair adds to 180°.
Reason (R): If a ray stands on a line, the adjacent angles make a straight angle.
Both are true and R is the correct reason.
Assertion (A): Vertically opposite angles are equal.
Reason (R): The angles of a triangle add to 180°.
Both are true, but R does not explain vertically opposite angles.
Assertion (A): Alternate angles on parallel lines are equal.
Reason (R): Co-interior angles are equal too.
A is true. R is false — co-interior angles add to 180°.
Assertion (A): The exterior angle equals the interior angle next to it.
Reason (R): The exterior angle equals the sum of the two far interior angles.
A is false. R is true, Theorem 6.8.
Assertion (A): m ∥ l and n ∥ l imply m ∥ n.
Reason (R): Lines parallel to the same line are parallel to each other.
Both are true and R explains A as Theorem 6.6.
Corresponding and alternate are equal. Co-interior and a linear pair give 180°.
The linear pair is 6.1. Parallelism is 6.6. The angle sum is 6.7.
Adjacent angles whose other arms form a line are a linear pair, and their sum is 180°.
If two lines intersect, the vertically opposite angles are equal.
The complement is 20°. The supplement is 110°.
A line that cuts two or more lines at distinct points is a transversal.
An exterior angle of a triangle equals the sum of the two far interior angles.
(5/12) × 180° = 75° and (7/12) × 180° = 105°. The vertically opposite angles are 75° and 105° as well.
Corresponding 58°, alternate 58°, co-interior 180° − 58° = 122°.
The third = 180° − 115° = 65°. The exterior = 40° + 75° = 115°.
If a ray stands on a line the sum is 180°, and the converse is also an axiom. Vertically opposite angles are equal. (2/5) × 180° = 72° and (3/5) × 180° = 108°. The four angles are 72°, 108°, 72° and 108°.
Corresponding equal, alternate equal, co-interior sum 180°. The measures are 70°, 70° and 110°. If one corresponding or alternate pair is equal, or one co-interior pair adds to 180°, the lines are parallel.
Lines parallel to the same line are parallel to each other. The angles of a triangle add to 180°. An exterior angle equals the sum of the two far interior angles. 180° − 135° = 45°, and 45° + 40° = 85°.
This model set is for practice. It is not a question from any year’s annual examination. Annual questions will be added only when a source page is available.
A linear pair.
180° − 130° = 50°.
The sum is 180°.
Supplementary.
40.
180 − 140.
True.
180° − 48° = 132°. Alternate angles are equal by Theorem 6.2 and co-interior angles are supplementary by Theorem 6.4.
These are competency-based practice questions. They are not copies of a CBSE paper.
The sum is 180°.
On parallel lines, co-interior angles are supplementary.
Theorem 6.6.
Lines parallel to the same line are parallel to each other.
Assertion (A): The three angles of a triangle add to 180°.
Reason (R): A linear pair also adds to 180°.
Both are true, but R is not the reason for the angle sum. The reason uses a parallel and alternate angles.
False — the linear pair shares 180°, so the angles are 75° and 105°.
The corresponding angle is 68° and the co-interior angle is 112°. The measurement makes the figure clear. The proof comes from Axiom 6.3 and Theorem 6.4.
The third = 180° − 115° = 65°. The exterior = 48° + 67° = 115°. 115° is larger than both 48° and 67°, because it is their sum.
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What you learned
| What | Keep this |
|---|---|
| Linear pair | 180° |
| Vertically opposite | equal |
| Corresponding | equal if parallel |
| Alternate | equal if parallel |
| Co-interior | sum 180° |
| Triangle | angle sum 180° |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.