The line that meets the circle at one point.
Once the inward force is gone the stone moves along the tangent.
Class 9 · Science · Chapter 10 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Gravitation
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1. Read — 10.1 thread · 10.2 stone up · 10.3 paper · 10.4 bottle · 10.5 nail · 10.6 cork · 10.7 balance, diagram, worked example, board tip
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3. Mastery ★ — all of that lesson correct. Redo the wrong ones
4. The memory figure shows a mass label and a downward weight arrow together on the same object.
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चन्द्रमा की गति — क्रियाकलाप 10.1 · Section 10.1 · Activity 10.1
An object thrown upward comes back down. The Moon goes around the Earth. Newton asked: if the Earth pulls an apple, can it also pull the Moon?
A stone on a circle can keep a steady speed, but the direction changes at every point. A change of direction is an acceleration. The force for this acceleration points toward the centre. It is called the centripetal force. The moment the thread is released, the stone flies off along the tangent.
The centripetal force that stops the Moon from running off in a straight line is the attraction of the Earth. The apple also pulls the Earth, but the mass of the Earth is so large that its acceleration is not seen. Activity 8.11 of the previous chapter is only a reminder of circular motion. It is not an activity of this chapter.
Tie a small stone to one end of a thread. Hold the other end and whirl the stone. The stone moves in a circle. Release the thread. The stone flies off in a straight line along the tangent. Remove the inward force and the circle does not survive.
Question: The apple pulls the Earth. Why does the Earth not rush toward the apple?
Answer: By the third law the forces are equal. By the second law a = F/m. The mass of the Earth is far larger than the apple, so the acceleration of the Earth is negligible.
Write both the words tangent and centripetal force. Only “it revolves” stays incomplete.
Join the apple-and-Earth pair to the third law and the second law.
The line that meets the circle at one point.
Once the inward force is gone the stone moves along the tangent.
True — otherwise the Moon would move off in a straight line.
Activity 10.1.
The centripetal force.
a = F/m.
The forces are equal. The Earth has a large m, so a is very small.
Before, the stone moves in a circle and an inward force keeps changing the direction. When the thread is released the stone flies straight along the tangent. The attraction of the Earth keeps the Moon on its path in the same way.
सार्वत्रिक गुरुत्वाकर्षण नियम · Section 10.1.1 · F = GMm/d²
Every object in the universe attracts every other object. The force is proportional to the product of the masses and inversely proportional to the square of the distance. The direction is along the line joining the centres.
F = G M m / d². G is the universal gravitation constant. The accepted value from the measurement of Cavendish is 6.673 × 10⁻¹¹ N m² kg⁻². The law is universal because it applies to small and large bodies, in the sky and on the Earth.
If the distance becomes 6 times, the force becomes 36 times smaller. That is the inverse square. Two friends sitting close feel no such force, because it is tiny. Only a large mass makes the force show up in daily life. The law binds us to the Earth and explains the motion of the Moon, the motion of the planets and the tides.
Question: The Earth has mass 6 × 10²⁴ kg, the Moon 7.4 × 10²² kg, and the distance is 3.84 × 10⁸ m. G = 6.7 × 10⁻¹¹ N m² kg⁻². Find the force.
Formula: F = G M m / d²
Substitution: F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 7.4 × 10²²) / (3.84 × 10⁸)²
Answer: F = 2.01 × 10²⁰ N.
Do not forget d² in the formula. If you write d, the inverse square is lost.
If the distance is halved the force becomes 4 times. This ratio comes up often.
1/d².
(2d)² = 4d², so the force becomes 1/4.
True — F d² / (M m) gives this unit.
Inverse square.
d².
F is proportional to M m.
The product doubles, so the force doubles.
G, M, m and d².
F = 2.01 × 10²⁰ N.
The force is proportional to the product of the masses and inversely proportional to the square of the distance, F = GMm/d². If the distance is halved, d² becomes one quarter, so the force becomes 4 times.
मुक्त पतन और g — क्रियाकलाप 10.2 और 10.3 · Section 10.2 · g = 9.8 m s⁻²
10.2 Throw a stone upward. It reaches a height and then starts falling. Falling under the gravity of the Earth alone is free fall. The direction does not change, the speed does, so there is an acceleration. That acceleration is g.
10.3 Drop a sheet of paper and a stone together. The paper arrives later, because air friction on the paper is larger. In a jar from which the air has been removed, both fall together. The story of Galileo at Pisa says the same thing.
The force on the stone is F = m g. For the Earth, g = G M / R². With M = 6 × 10²⁴ kg, R = 6.4 × 10⁶ m and G = 6.7 × 10⁻¹¹ N m² kg⁻², g = 9.8 m s⁻². The falling mass is not in this formula, so hollow or solid, large or small, the acceleration is the same.
Near the Earth, write g in place of a in the equations of uniform acceleration: v = u + gt, s = ut + ½ gt², v² = u² + 2gs. Take the acceleration as positive along the velocity and negative when it opposes the motion. g falls a little with height and toward the equator.
Question: A car falls off a ledge and reaches the ground in 0.5 s. Take g = 10 m s⁻². Find the speed and the distance.
Formula: v = u + gt and s = ut + ½ gt². u = 0.
Substitution: v = 0 + 10 × 0.5 = 5. s = 0 + ½ × 10 × (0.5)² = 5 × 0.25.
Answer: v = 5 m s⁻¹ downward, s = 1.25 m.
The unit of g is m s⁻², not the newton. The newton is the unit of weight.
If the paper falls late, write air as the reason, not the mass.
The unit of acceleration.
g = 9.8 m s⁻².
True — once air resistance is gone, mass does not change the rate.
The square of the radius of the Earth.
R².
Formula v² = u² + 2gs. u = 0. v² = 2 × 9.8 × 19.6 = 384.16. v = 19.6 m s⁻¹ downward.
द्रव्यमान और भार · Sections 10.3 and 10.4 · W = mg
Mass is the measure of inertia. It does not change on the Earth, the Moon or in space. Weight is the force with which the Earth pulls the object.
W = m g. The unit is the newton and the direction is vertically downward. Where g is constant, weight is proportional to mass, so a balance that seems to read mass is really measuring weight.
The mass of the Moon is less than the mass of the Earth. From the universal law, weight on the Moon comes out about 1/6 of the weight on the Earth. The mass does not change.
| Point | Mass | Weight |
|---|---|---|
| What it is | Measure of inertia | Gravitational force |
| Unit | kg | N |
| If the place changes | Does not change | Changes with g |
Question: An object has mass 10 kg. Find the weight on the Earth, g = 9.8 m s⁻². What is the weight on the Moon?
Formula: W = m g, and on the Moon W_m = W / 6.
Substitution: W = 10 kg × 9.8 m s⁻² = 98 N. W_m = 98 / 6.
Answer: 98 N on the Earth, about 16.3 N on the Moon. The mass is 10 kg in both places.
Even if a balance shows kg, write that it is calibrated from weight.
If the Earth weight is 10 N, the Moon weight is 10/6 = 1.67 N. Do not forget the fraction.
The measure of inertia.
Mass does not change. Weight becomes about 1/6.
True — W = mg.
W = mg.
98 N.
1/6.
10/6 = 1.67 N.
Mass is the measure of inertia, a scalar, unit kg, and it does not change with place. Weight is the gravitational force, a vector, unit newton, and it changes with g. W = mg.
प्रणोद और दाब · Section 10.5 · pascal
A pointed pin enters a board more easily. Standing, your feet sink into sand. Lying down, the body does not sink as much. In both cases the force is your weight.
The force perpendicular to a surface is called thrust. Pressure = thrust / area. The SI unit is N m⁻², called the pascal (Pa). A smaller area gives a larger pressure. That is why a nail has a point, a knife has an edge, and a building has a wide foundation.
Liquids and gases are fluids. In a confined fluid, pressure is transmitted undiminished in every direction.
Question: A wooden block of 5 kg is 40 cm × 20 cm × 10 cm. Find the pressure on the 20 cm × 10 cm face and on the 40 cm × 20 cm face. g = 9.8 m s⁻².
Formula: thrust F = m g, pressure = F / area.
Substitution: F = 5 × 9.8 = 49 N. Smaller area = 0.20 × 0.10 = 0.02 m². Larger area = 0.40 × 0.20 = 0.08 m².
Answer: P₁ = 49 / 0.02 = 2450 Pa. P₂ = 49 / 0.08 = 612.5 Pa.
Change cm² into m² by multiplying by 10⁻⁴. 200 cm² = 0.02 m².
One thrust, two areas. The smaller area gives the larger pressure — write that sentence.
10-second revision
N/m².
The pascal. 1 Pa = 1 N m⁻².
True — pressure = force / area.
Pa = N/m².
Area.
F = mg.
5 × 9.8 = 49 N.
The area is larger.
A larger area decreases the pressure and the ground does not sink.
The weight of the bag is the thrust. A thin strap has a small area, so pressure = thrust/area becomes large and the shoulder hurts.
उत्प्लावन — क्रियाकलाप 10.4, 10.5 और 10.6 · Sections 10.5.2 · 10.5.3
In a pool the body feels light. A bucket feels heavier once it is out of the well. An iron ship floats. The same iron as a sheet can sink. The reason is buoyancy.
An object immersed in a fluid feels an upward force. That force equals the weight of the fluid displaced. If the density of the object is less than the fluid, it floats. If the density is greater, it sinks. Density = mass / volume, unit kg m⁻³.
10.4 Close an empty plastic bottle with an airtight stopper and put it in a bucket of water. The bottle floats. Push it down. The deeper the push, the larger the upward force, until the bottle is fully immersed. Release it and it returns to the surface. Weight pulls down. Water pushes up.
10.5 Place an iron nail on the surface of water. The nail sinks. The downward weight is greater than the upthrust of the water.
10.6 Take a cork and an iron nail of equal mass. The cork floats and the nail sinks. The density of cork is less than water. The density of the nail is greater.
Question: 50 g of a substance has volume 20 cm³. The density of water is 1 g cm⁻³. Will the object float or sink?
Formula: density = mass / volume.
Substitution: density = 50 g / 20 cm³ = 2.5 g cm⁻³.
Answer: 2.5 is greater than 1 for water, so the object sinks.
Write the float-or-sink decision from density, not only from the words iron or wood.
A ship floats even though it is iron, because the average density stays less than water.
10-second revision
Activities 10.5 and 10.6.
The density of the nail is greater than water, so it sinks.
True — the upthrust grows until the bottle is fully immersed.
The unit is kg m⁻³.
Volume.
The density of cork is less than water, so the upthrust is greater than its weight and it floats. The density of the nail is greater than water, so it sinks.
आर्किमिडीज़ और आपेक्षिक घनत्व — क्रियाकलाप 10.7 · Sections 10.6 · 10.7 · Activity 10.7
Hang a stone from a rubber string or a spring balance. Note the extension or the reading in air. Lower the stone slowly into water. The extension of the string, or the reading of the balance, decreases. Once the stone is fully immersed there is no further decrease, because the displaced volume no longer increases.
The extension was due to the weight. The decrease means the water exerts an upward force. That is buoyancy.
A body immersed fully or partly feels an upward force equal to the weight of the fluid displaced. That is the principle of Archimedes. Ships, submarines, lactometers and hydrometers rest on it.
Relative density = density of the substance / density of water. If both densities use the same unit, the ratio has no unit. If the relative density of silver is 10.8 and the density of water is 10³ kg m⁻³, the density of silver is 10.8 × 10³ kg m⁻³.
If a balance reads 42 kg, the buoyancy of air makes the reading a little small, so the real mass is a little more than 42 kg. At the same reading a bag of cotton is really heavier than an iron bar, because the cotton has a larger volume and a larger buoyancy of air.
Question: The relative density of silver is 10.8. The density of water is 10³ kg m⁻³. Find the density of silver in SI.
Formula: density = relative density × density of water.
Substitution: density = 10.8 × 10³ kg m⁻³.
Answer: 1.08 × 10⁴ kg m⁻³. Relative density has no unit.
In 10.7, answer “why no further decrease” with volume, not with weight.
Do not attach kg or N to an answer that is a relative density.
10-second revision
The weight of the fluid, not only its volume.
The upward force equals the weight of the displaced fluid.
False — the displaced volume stops increasing, so there is no further fall.
A ratio of like quantities.
There is no unit.
Water is 10³ kg m⁻³.
10.8 × 10³ = 1.08 × 10⁴ kg m⁻³.
Air exerts a small upward force, so the reading is a little less than the real weight. The real mass is more than 42 kg.
Pick a type. The 35 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
Activity 10.1.
Straight motion along the tangent.
(3d)² = 9d².
The force becomes 1/9.
Cavendish.
6.673 × 10⁻¹¹ N m² kg⁻².
9.8 near the Earth.
g.
Activity 10.3.
Air friction on the paper is larger. In a vacuum both fall together.
The unit of force.
The newton.
1/6.
60/6 = 10 N.
P = F/A.
Smaller area, larger pressure.
mg.
49 N.
Activity 10.6.
Lower density floats, higher density sinks.
A ratio of like quantities.
There is no unit.
Water is 1 g cm⁻³.
2.5 > 1, so it sinks.
s = ½ gt².
½ × 10 × 0.25 = 1.25 m.
The buoyancy of air is upward.
The real mass is a little more than 42 kg.
False — the law is for all objects. Between light objects the force is very small.
False — the falling mass is not in g = GM/R².
True — what changes is the weight.
True — 1 Pa = 1 N m⁻².
False — buoyancy acts upward.
False — the ratio has no unit. kg m⁻³ is the unit of density.
False — after full immersion the volume does not increase, so the reading stops falling.
True — the product becomes 4 times.
The centre.
The centre of the circle.
G.
The universal constant.
9.8.
GM/R².
mg.
In newtons.
The pascal.
N/m².
Volume.
kg m⁻³.
10800, or 1.08 × 10⁴.
1.08 × 10⁴.
1/6.
The mass does not change.
G uses N m² kg⁻², g uses m s⁻², weight uses N, pressure uses Pa.
10.1 is the tangent, 10.3 the paper, 10.5 the nail, 10.7 the reading.
Assertion (A): When the distance doubles, the gravitational force becomes one quarter.
Reason (R): The force is inversely proportional to the square of the distance.
Both are true and R explains A.
Assertion (A): In a vacuum a heavy object and a light object fall at the same rate.
Reason (R): g is proportional to the mass of the falling object.
A is true. R is false — g = GM/R² does not depend on the mass.
Assertion (A): Weight decreases on the Moon.
Reason (R): Mass is the measure of inertia.
Both are true, but R does not explain why the weight falls. The weight falls because g on the Moon is smaller.
Assertion (A): The unit of relative density is kg m⁻³.
Reason (R): Relative density is a ratio of two densities.
A is false. R is true — a ratio has no unit.
Assertion (A): An iron nail sinks in water.
Reason (R): The density of the nail is greater than the density of water.
Both are true and R explains A.
The kg and staying constant belong to mass. W = mg and 1/6 belong to weight.
The nail and 2.5 g cm⁻³ sink. Cork and a lower density float.
F = G M m / d².
When an object falls under the gravitational force of the Earth alone, the motion is free fall. The acceleration is g.
Mass does not change with place and the unit is the kg. Weight W = mg can change with place and the unit is the newton.
Pressure is thrust per unit area. The SI unit is the pascal, 1 Pa = 1 N m⁻².
The upward force on an immersed body equals the weight of the fluid displaced.
g = (6.7 × 10⁻¹¹ × 6 × 10²⁴) / (6.4 × 10⁶)² = 4.02 × 10¹⁴ / 4.096 × 10¹³ = 9.8 m s⁻².
At the top v = 0. 0 = 49² + 2(−9.8)s. s = 2401/19.6 = 122.5 m. Time to go up = 49/9.8 = 5 s. Total time to return = 10 s.
Thrust = 5 × 9.8 = 49 N. Area = 0.40 × 0.20 = 0.08 m². Pressure = 49/0.08 = 612.5 Pa.
The cotton is heavier. Its volume is larger, so the buoyancy of air is larger. For the same reading the real weight, and the mass, of the cotton must be greater than that of the iron.
F = GMm/d². Uses: binding us to the Earth, the motion of the Moon, the motion of the planets, and the tides of the Moon and the Sun. If the distance is d/2, each d² is replaced by d²/4. The force is in the ratio 1/(d²/4) = 4/d², that is 4 times.
Mass is inertia, in kg, constant. Weight is a force, W = mg, in newtons, downward. W = 10 × 9.8 = 98 N. On the Moon 98/6 ≈ 16.3 N. In the figure the label m = 10 kg stays the same in both places, and the downward arrow is 98 N on the Earth and about 16.3 N on the Moon.
Buoyancy is the upward force of a fluid. Archimedes: this force equals the weight of the fluid displaced. Water pushes up, so the balance reading falls. After full immersion the displaced volume does not increase, so there is no further fall. If the density is less than the fluid the object floats. If it is greater, the object sinks.
This model set is for practice. It is not a question from any year’s annual examination.
1/d².
The force becomes 4 times.
Both F and m increase.
a = F/m = g, and the mass cancels.
Weight.
W = mg.
The buoyant force acts upward.
The density of plastic is less than water. The upthrust is greater than its weight, so it rises and floats.
Density = 500/350 = 1.43 g cm⁻³. This is greater than 1 g cm⁻³, so the packet sinks.
These are competency-based practice questions. They are not copies of a CBSE paper.
Pressure = weight / area.
Larger area, smaller pressure.
W = mg.
m is constant. W on the Moon is about 1/6.
Assertion (A): The tip of a nail is kept sharp.
Reason (R): The same force on a small area gives a large pressure.
Both are true and R explains A.
Assertion (A): The upthrust on an object in water acts downward.
Reason (R): By Archimedes this force equals the weight of the fluid displaced.
A is false — buoyancy acts upward. R is true.
The mass is still 10 kg. At a height g is a little smaller, so the weight W = mg falls a little. A balance measures weight and is marked in kg, so the reading on the mountain can be a little low. The grain has not decreased.
The shape of the boat displaces a large amount of water. The average density stays less than water, so the upthrust equals or exceeds the weight and the boat floats. The solid lump has a density greater than water and displaces less water, so it sinks.
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What you learned
| What | Keep this |
|---|---|
| Universal force | F = GMm/d² |
| G | 6.673 × 10⁻¹¹ N m² kg⁻² |
| g | 9.8 m s⁻² near the Earth |
| Weight | W = mg, unit N |
| Moon | weight about 1/6 of Earth |
| Relative density | no unit |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.