Class 9 · Science · Chapter 3: Atoms and Molecules

Class 9 Science Chapter 3: Important Questions with Answers

Bihar Board · NCERT · CBSE

No board-hosted Class 9 paper could be verified, so there are no previous-year questions here and no question carries a year. These are book-based important questions (with section and page) and all NCERT in-text and exercise questions. Answers are by Study With Me.

← Chapter 3: Atoms and Molecules — full notes, video, questions

📗 One-line answers (1 mark)

1Book-based · Intro · p. 311 mark

Who gave the name "Parmanu"?

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Maharishi Kanad.

2Book-based · 3.1.1 · p. 321 mark

State the law of conservation of mass.

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Mass can neither be created nor destroyed in a chemical reaction.

3Book-based · 3.1.2 · p. 321 mark

State the law of constant proportions.

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In a chemical substance the elements are always present in definite proportions by mass.

4Book-based · 3.1.2 · p. 321 mark

Which city did Dalton move to, to teach?

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Manchester (1793).

5Book-based · 3.2 · p. 331 mark

What is the radius of a hydrogen atom?

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About 10⁻¹⁰ m.

6Book-based · 3.2.1 · p. 341 mark

Expand IUPAC.

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International Union of Pure and Applied Chemistry.

7Book-based · Table 3.1 · p. 341 mark

What is the symbol of gold?

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Au.

8Book-based · 3.2.2 · p. 351 mark

Which isotope is the standard reference for atomic masses?

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Carbon-12.

9Book-based · Table 3.2 · p. 351 mark

Atomic mass of calcium?

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40 u.

10Book-based · 3.3.1 · p. 361 mark

Atomicity of chlorine?

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2 (diatomic, Cl₂).

11Book-based · 3.3.3 · p. 361 mark

Name the ions in NaCl.

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Na⁺ and Cl⁻.

12Book-based · Table 3.6 · p. 371 mark

Formula of the hydrogen carbonate ion?

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HCO₃⁻.

13Book-based · 3.4 · p. 371 mark

What is a chemical formula?

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A symbolic representation of the composition of a compound.

14Book-based · Example 3.1 · p. 391 mark

Molecular mass of water?

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18 u.

15Book-based · 3.5.3 · p. 411 mark

The Avogadro number honours whom?

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The Italian scientist Amedeo Avogadro.

📗 Short answers (2 marks)

16Book-based · Intro · p. 312 marks

Give a similarity and a limitation of the ideas of Kanad and Democritus.

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Both said that dividing matter ends in indivisible particles — Parmanu (Kanad), atoms (Democritus). Limitation: these were philosophical ideas, not tested by experiment till the eighteenth century.

17Book-based · Activity 3.1 · p. 312 marks

Briefly describe the method and conclusion of Activity 3.1.

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Y in the flask, X in an ignition tube, cork and weigh; tilt to mix, a reaction occurs; weigh again — same mass. Conclusion: conservation of mass.

18Book-based · 3.1.2 · p. 322 marks

Write any four postulates of Dalton's atomic theory.

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All matter is made of atoms; atoms are indivisible, neither created nor destroyed; atoms of an element are identical in mass and properties; atoms combine in small whole-number ratios.

19Book-based · 3.2.1 · p. 342 marks

In what ways are symbols of elements formed? Give examples.

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First letter of the name (H, C); first two letters (Al, Co); first and a later letter (Cl, Zn); from Latin/German/Greek names (Fe, Na, K).

20Book-based · 3.2.2 · p. 342 marks

Why was carbon-12 chosen as the standard, and what was used earlier?

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Earlier 1/16 of naturally occurring oxygen was the unit — oxygen forms compounds with many elements and gave mostly whole-number masses. In 1961 carbon-12 was chosen for a universally accepted unit: 1 u = 1/12 of C-12.

21Book-based · Fig. 3.4 · p. 352 marks

How does the fruit-seller example (Fig. 3.4) explain relative atomic mass?

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The seller calls a watermelon 12 units, cuts 12 pieces and weighs each fruit against one piece. Likewise each atom's mass is given relative to 1/12 of a C-12 atom.

22Book-based · 3.3 · p. 352 marks

Two differences between an atom and a molecule.

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An atom is the smallest particle of an element and mostly cannot exist independently; a molecule is a bonded group of two or more atoms that can exist independently and shows all properties of the substance.

23Book-based · 3.3.3 · p. 362 marks

Explain cations and anions with examples.

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Positively charged ion = cation (Na⁺, Ca²⁺, NH₄⁺); negatively charged = anion (Cl⁻, O²⁻, SO₄²⁻).

24Book-based · 3.4 · p. 382 marks

Write three rules for writing chemical formulae.

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Valencies/charges must balance; metal first, non-metal after; more than one polyatomic ion goes in brackets.

25Book-based · 3.4.1 · p. 392 marks

What does the bracket in Ca(OH)₂ mean? How many atoms in all?

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Two hydroxide (OH) groups are joined to one calcium; atoms = 1 Ca + 2 O + 2 H = 5.

26Book-based · 3.5.2 · p. 402 marks

Difference between molecular mass and formula unit mass.

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Both are sums of atomic masses; molecular mass for substances of molecules (H₂O 18 u), formula unit mass for substances of ions (NaCl 58.5 u).

27Book-based · 3.5.3 · p. 402 marks

Write the two meanings (number, mass) of 2H₂ + O₂ → 2H₂O.

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2 molecules H₂ + 1 molecule O₂ → 2 molecules H₂O; 4 u H₂ + 32 u O₂ → 36 u H₂O.

📗 Long answers (5 marks)

28Book-based · 3.1, 3.1.2 · p. 315 marks

State the two laws of chemical combination and how Dalton's theory explains them.

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(1) Conservation of mass: mass is neither created nor destroyed — Activity 3.1. (2) Constant proportions (Proust): elements in a compound are in a fixed mass ratio — water 1 : 8, ammonia 14 : 3. Dalton: atoms are neither created nor destroyed (→ law 1); the relative number and kinds of atoms are constant, in small whole numbers (→ law 2).

29Book-based · 3.2.2 · p. 345 marks

Explain how the atomic mass unit developed — CO example, oxygen standard, carbon-12.

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In CO, 3 g C + 4 g O; with C = 1, O = 1.33 — not whole. Earlier 1/16 of natural O was the unit (O forms many compounds, gives whole numbers). In 1961 carbon-12 became the standard: 1 u = 1/12 of one C-12 atom. Relative atomic mass = average atomic mass ÷ (1/12 of C-12). Fruit-seller analogy (Fig. 3.4).

30Book-based · 3.3.1, 3.3.3 · p. 365 marks

Explain molecule, atomicity and ion with examples.

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Molecule: smallest particle that exists independently — O₂, H₂O. Atomicity: number of atoms in a molecule — He, Ar 1; O₂, N₂ 2; O₃ 3; P₄ 4; S₈ poly. Ion: a charged particle — Na⁺ (cation), Cl⁻ (anion); polyatomic ions — NH₄⁺, SO₄²⁻, PO₄³⁻. Metal–non-metal compounds are made of ions.

31Book-based · 3.4.1 · p. 385 marks

Write by criss-cross: aluminium oxide, calcium oxide, sodium nitrate, calcium hydroxide, ammonium sulphate.

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Al³⁺, O²⁻ → Al₂O₃; Ca²⁺, O²⁻ → Ca₂O₂ → CaO (simplify); Na⁺, NO₃⁻ → NaNO₃; Ca²⁺, OH⁻ → Ca(OH)₂ (bracket, two OH); NH₄⁺, SO₄²⁻ → (NH₄)₂SO₄.

32Book-based · 3.5.3 · p. 405 marks

Explain the relation between mole, Avogadro number and molar mass (Fig. 3.5) with formulas and one example each.

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1 mole = 6.022 × 10²³ particles (N₀) = relative mass in grams. n = m/M (52 g He → 13 mol); n = N/N₀ (12.044 × 10²³ He → 2 mol); m = M × n (0.5 mol N₂ → 14 g); N = (m/M) × N₀ (46 g Na → 12.044 × 10²³ atoms).

33Book-based · 3.5.1, 3.5.2 · p. 395 marks

Find the molecular/formula unit masses: H₂, O₂, Cl₂, CO₂, CH₄, NH₃, ZnO, Na₂O (Zn = 65, Na = 23).

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H₂ 2 u; O₂ 32 u; Cl₂ 71 u; CO₂ 12 + 32 = 44 u; CH₄ 12 + 4 = 16 u; NH₃ 14 + 3 = 17 u; ZnO 65 + 16 = 81 u; Na₂O 46 + 16 = 62 u.

📘 NCERT in-text questions

34NCERT · pp. 32–33 · Q1

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations agree with the law of conservation of mass.

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Mass of reactants = 5.3 + 6 = 11.3 g; mass of products = 2.2 + 0.9 + 8.2 = 11.3 g. They are equal, so mass is conserved.

35NCERT · p. 33 · Q2

Hydrogen and oxygen combine in the ratio 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

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1 g H needs 8 g O, so 3 g H needs 3 × 8 = 24 g of oxygen.

36NCERT · p. 33 · Q3

Which postulate of Dalton's atomic theory is the result of the law of conservation of mass?

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Postulate (ii): atoms are indivisible particles which cannot be created or destroyed in a chemical reaction.

37NCERT · p. 33 · Q4

Which postulate of Dalton's atomic theory can explain the law of definite proportions?

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Postulate (vi): the relative number and kinds of atoms are constant in a given compound (with (v): atoms combine in small whole-number ratios).

38NCERT · p. 35 · Q1

Define the atomic mass unit.

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A mass unit equal to exactly one-twelfth of the mass of one atom of carbon-12 = 1 u.

39NCERT · p. 35 · Q2

Why is it not possible to see an atom with naked eyes?

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Atoms are extremely small (radius about 10⁻¹⁰ m, measured in nanometres) and atoms of most elements do not exist independently.

40NCERT · p. 39 · Q1

Write the formulae of (i) sodium oxide (ii) aluminium chloride (iii) sodium sulphide (iv) magnesium hydroxide.

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(i) Na₂O (ii) AlCl₃ (iii) Na₂S (iv) Mg(OH)₂

41NCERT · p. 39 · Q2

Write the names of the compounds: (i) Al₂(SO₄)₃ (ii) CaCl₂ (iii) K₂SO₄ (iv) KNO₃ (v) CaCO₃.

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(i) aluminium sulphate (ii) calcium chloride (iii) potassium sulphate (iv) potassium nitrate (v) calcium carbonate

42NCERT · p. 39 · Q3

What is meant by the term chemical formula?

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The symbolic representation of the composition of a compound — it shows the constituent elements and the number of atoms of each.

43NCERT · p. 39 · Q4

How many atoms are present in (i) an H₂S molecule (ii) a PO₄³⁻ ion?

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(i) 3 (2 H + 1 S) (ii) 5 (1 P + 4 O)

44NCERT · p. 40 · Q1

Calculate the molecular masses of H₂, O₂, Cl₂, CO₂, CH₄, C₂H₆, C₂H₄, NH₃, CH₃OH.

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H₂ 2 u; O₂ 32 u; Cl₂ 71 u; CO₂ 44 u; CH₄ 16 u; C₂H₆ 30 u; C₂H₄ 28 u; NH₃ 17 u; CH₃OH 32 u.

45NCERT · p. 40 · Q2

Calculate the formula unit masses of ZnO, Na₂O, K₂CO₃ (Zn = 65, Na = 23, K = 39, C = 12, O = 16 u).

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ZnO = 65 + 16 = 81 u; Na₂O = 2 × 23 + 16 = 62 u; K₂CO₃ = 2 × 39 + 12 + 3 × 16 = 138 u.

46NCERT · p. 42 · Q1

If one mole of carbon atoms weighs 12 grams, what is the mass (in grams) of 1 atom of carbon?

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12 g ÷ 6.022 × 10²³ = 1.99 × 10⁻²³ g.

47NCERT · p. 42 · Q2

Which has more atoms, 100 g of sodium or 100 g of iron (Na = 23 u, Fe = 56 u)?

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Na: 100/23 = 4.35 mol; Fe: 100/56 = 1.79 mol. More moles = more atoms — 100 g of sodium has more atoms.

📘 NCERT exercises

48NCERT · Ex. 1

A 0.24 g sample of a compound of oxygen and boron contains 0.096 g boron and 0.144 g oxygen. Calculate the percentage composition by weight.

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Boron = 0.096/0.24 × 100 = 40%; oxygen = 0.144/0.24 × 100 = 60%.

49NCERT · Ex. 2

3.0 g carbon burnt in 8.00 g oxygen gives 11.00 g CO₂. What mass of CO₂ forms when 3.00 g carbon is burnt in 50.00 g oxygen? Which law governs your answer?

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Still 11.00 g CO₂ — 3 g carbon combines with only 8 g oxygen; the remaining 42 g oxygen is left unused. Law of constant (definite) proportions.

50NCERT · Ex. 3

What are polyatomic ions? Give examples.

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Clusters of atoms carrying a fixed net charge that act as one ion — NH₄⁺, OH⁻, NO₃⁻, HCO₃⁻, CO₃²⁻, SO₄²⁻, PO₄³⁻.

51NCERT · Ex. 4

Write the chemical formulae: (a) magnesium chloride (b) calcium oxide (c) copper nitrate (d) aluminium chloride (e) calcium carbonate.

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(a) MgCl₂ (b) CaO (c) Cu(NO₃)₂ (d) AlCl₃ (e) CaCO₃

52NCERT · Ex. 5

Name the elements present in (a) quick lime (b) hydrogen bromide (c) baking powder (d) potassium sulphate.

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(a) CaO: calcium, oxygen (b) HBr: hydrogen, bromine (c) sodium hydrogen carbonate NaHCO₃: sodium, hydrogen, carbon, oxygen (d) K₂SO₄: potassium, sulphur, oxygen.

53NCERT · Ex. 6

Calculate the molar mass of (a) ethyne C₂H₂ (b) sulphur molecule S₈ (c) phosphorus molecule P₄ (P = 31) (d) HCl (e) HNO₃.

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(a) 2 × 12 + 2 = 26 g (b) 8 × 32 = 256 g (c) 4 × 31 = 124 g (d) 1 + 35.5 = 36.5 g (e) 1 + 14 + 48 = 63 g (per mole).

54NCERT · Ex. 7

What is the mass of (a) 1 mole of nitrogen atoms (b) 4 moles of aluminium atoms (Al = 27) (c) 10 moles of sodium sulphite Na₂SO₃?

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(a) 14 g (b) 4 × 27 = 108 g (c) M = 46 + 32 + 48 = 126 g; 10 × 126 = 1260 g.

55NCERT · Ex. 8

Convert into mole: (a) 12 g oxygen gas (b) 20 g water (c) 22 g carbon dioxide.

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(a) 12/32 = 0.375 mol (b) 20/18 = 1.11 mol (c) 22/44 = 0.5 mol.

56NCERT · Ex. 9

What is the mass of (a) 0.2 mole of oxygen atoms (b) 0.5 mole of water molecules?

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(a) 0.2 × 16 = 3.2 g (b) 0.5 × 18 = 9 g.

57NCERT · Ex. 10

Calculate the number of molecules of sulphur (S₈) in 16 g of solid sulphur.

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M(S₈) = 256 g; n = 16/256 = 0.0625 mol; N = 0.0625 × 6.022 × 10²³ = 3.76 × 10²² molecules.

58NCERT · Ex. 11

Calculate the number of aluminium ions in 0.051 g of aluminium oxide (Al = 27 u; mass of an ion = mass of the atom).

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M(Al₂O₃) = 54 + 48 = 102 g; n = 0.051/102 = 5 × 10⁻⁴ mol; each formula unit has 2 Al³⁺, so ions = 2 × 5 × 10⁻⁴ × 6.022 × 10²³ = 6.022 × 10²⁰.

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