One’s own purpose.
Primary.
Class 9 · Maths · Chapter 14 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Statistics
How to use this page:
1. Read — Activity 1 · Exercise 14.1 · Activity 2 · Exercise 14.2 · Activity 3 · histogram · frequency polygon · Exercise 14.3 · mean · median · mode · Exercise 14.4, diagram, worked example, board tip
2. Check — each lesson has its own questions; the number follows the lesson
3. Mastery ★ — all of that lesson correct. Redo the wrong ones
4. The memory figure shows a histogram of touching bars and a frequency polygon joined through the class marks.
This page follows the Bihar textbook. Ganita Manjari uses a different order. Progress stays in this browser.
Last 7 days:
Everything is saved in this phone/browser — no login.
This chapter has no Short on the channel yet, so ten empty cards are not shown. The notes, diagrams and checks are complete.
आँकड़े और क्रियाकलाप 1 · Textbook 14.1–14.2 · Exercise 14.1
Statistics is sometimes the plural of data and sometimes the subject that teaches collection, presentation, analysis and conclusions. Facts or numbers gathered for a purpose are data.
Gather them yourself and they are primary. Take them from a register or a news report and they are secondary. Range = largest − smallest. A count with no purpose does not become data.
Divide the class into four groups. One group gathers the heights of 20 students, the second the absences of a month, the third the number of family members, the fourth the heights of 15 plants. Exercise 14.1 says: write five everyday data sets and call each primary or secondary.
Question: The heights are 140, 152, 148 and 161 cm. Find the range.
Formula: range = largest value − smallest value.
Substitution: 161 − 140 = 21.
Unit: centimetre.
A copy from a register is secondary, even if you made the table.
Write the unit with the range. Only 21 is incomplete if the data are in centimetres.
One’s own purpose.
Primary.
True.
161−140.
21 cm.
The first of the four groups.
Heights of 20 students.
Measuring the class heights yourself is primary. A price from a newspaper is secondary. Range = largest − smallest.
बारंबारता सारणी · Textbook 14.3 · Activity 2 · Exercise 14.2
An ungrouped table writes the count beside each value. If the values are many, make classes. Keep a convenient class size and take the first interval as the book says. In 0–5, the 5 is often not included, when the book says so.
Tally marks keep the count honest. The greatest frequency is the common class. The least is the rare one. The total must equal the number of observations.
The same four groups now turn their tables into frequencies. Choose the class size by looking at the range. Exercise 14.2 asks for tables such as blood groups, engineers’ distances (class size 5, first interval 0–5), humidity and heights. The 5 is not included if the book says so.
Question: The values are 2, 3, 2, 5, 3, 2. Write the frequency of 2 and the total.
Formula: frequency = the count of that value. Total = the sum of all frequencies.
Substitution: 2 appears three times. The total of observations is 6.
Unit: a count, no other unit.
In the classes 0–5 and 5–10, put 5 in the second class when the book says 5 is not included.
After the tally, write the number. Marks alone are not taken as the answer.
How often.
The count.
True.
Three times.
3.
5 goes in the second class 5–10, because the first interval does not include 5.
दंड आलेख और क्रियाकलाप 3 · Textbook 14.4 · Activity 3
A bar graph is good for separate names or classes. The length of a bar is proportional to the value. A gap is kept between the bars. Show every width the same, but the width is not used in the calculation.
Write the scale on the axis. Starting at zero keeps the picture honest. For two tables, keep one scale.
The same four groups draw a suitable bar graph of their data. Do not push the height group and the family group into one picture if the units differ. The bar questions of Exercise 14.3 use this idea, but they come after the next lesson.
Question: One bar stands for 12 students and the scale is 1 cm = 4 students. Find the length of the bar.
Formula: length = number ÷ one part of the scale.
Substitution: 12 ÷ 4 = 3.
Unit: centimetre.
Starting the axis away from zero makes a small gap look large. Start at zero.
Do not change the value by changing the width. In a bar graph the width carries no meaning.
Touching rectangles belong to a histogram.
A gap.
True.
12÷4.
3 cm.
The third activity.
A bar graph.
Length = 20 ÷ 5 = 4 cm.
False — the length shows the value. The width is kept the same.
आयतचित्र और असमान चौड़ाई · Textbook 14.4 · continuous classes
A histogram is the graph of a table of continuous classes. The rectangles touch. There is no gap. If the widths are equal, the length may be proportional to the frequency.
If the width changes, look at the area. Choose the smallest width. Rectangle length = (frequency ÷ class width) × minimum width. Drawing the raw frequency alone gives a wrong picture.
Question: The minimum width is 10. One class has width 20 and frequency 8. Find the rectangle length.
Formula: length = (frequency ÷ width) × minimum width.
Substitution: (8 ÷ 20) × 10 = 4.
Unit: the length unit of the graph.
Do not turn frequency 8 of width 20 into height 8. Show (8/20)×10 = 4.
Do not mix a bar graph and a histogram in one sentence. A gap means bars. Touching means a histogram.
No gap.
They touch.
True.
(8/20)×10.
4.
The area stays right on its own.
Proportional to the frequency.
Length = (9/30)×10 = 3.
बारंबारता बहुभुज और अभ्यास 14.3 · Class mark · Exercise 14.3
The midpoints of the tops of the rectangles are the class marks. Class mark = (lower limit + upper limit) / 2. Join them. Assume one imaginary class of frequency zero on each side, and the polygon closes.
A polygon can also be drawn without a histogram. For comparing two sections, two polygons on one axis work well. Exercise 14.3 asks for bars, histograms and polygons.
The order starts with the bar questions, then histograms and polygons. Compare two groups with two polygons. Find the class marks and plot the points. Put an imaginary zero class at both ends.
Question: Find the class mark of the class 10–20.
Formula: class mark = (lower limit + upper limit) / 2.
Substitution: (10 + 20) / 2 = 15.
Unit: the unit of the data.
The mark of 20–30 is 25, not 20 or 30. Show the average.
The imaginary class has frequency 0. Do not count it as real data.
10-second revision
(20+30)/2.
25.
True.
The average.
15.
Join the marks of imaginary classes of frequency 0 on both sides.
माध्य · Textbook 14.5 · ungrouped and frequency
The ungrouped mean is x̄ = (sum of all values) / n. In a frequency table, x̄ = Σ(f x) / Σf. x is the value or the class mark, and f is its frequency.
One very large salary pulls the mean up. Then the mean is not a good representative of the group. The salary table of Exercise 14.4 points to this. The unit is the unit of the data.
Question: The values are 4, 6, 6, 7 and 17. Find the mean.
Formula: x̄ = (Σx) / n.
Substitution: sum = 40, n = 5, x̄ = 40 / 5 = 8.
Unit: the unit of the values.
Writing only the sum and forgetting to divide by n is half an answer.
In a frequency mean, multiply each value by f. Adding only the x values is wrong.
10-second revision
The average.
Sum / n.
True.
40/5.
8.
The salary example.
Upwards.
x̄ = (2+3+7)/3 = 12/3 = 4.
False — the division is what makes the mean.
माध्यिका, बहुलक और अभ्यास 14.4 · Textbook 14.5 · Exercise 14.4
For the median, put the values in increasing order. If n is odd, the median is the value at place (n+1)/2. If n is even, average the (n/2)th and the next. The mode is the value that appears most often. There can be two modes.
Exercise 14.4 asks for goals, marks, an ordered list with x, the mode of one list, the mean of a salary frequency table, and when the mean is right and when the median is better.
1) Goals of ten matches: mean, median, mode. 2) All three for fifteen marks. 3) If the median of an increasing list is 63, find x. 4) The mode of the given list. 5) The mean of the salary table of 60 workers, by Σfx / Σf. 6) One situation where the mean is right and one where the median is better.
Question: Find the median and the mode of 4, 6, 6, 7, 17.
Formula: n = 5 is odd, so the place is (5+1)/2 = 3. The mode is the most frequent.
Substitution: The list is already increasing. The third value is 6. 6 appears twice, so the mode is 6.
Unit: the unit of the values.
Write the order before the median. Without the order the middle place catches the wrong value.
Mean 8 and median 6 belong to the same list. The large 17 pulls the mean. Write both.
10-second revision
(5+1)/2 = 3.
The third.
True.
The third place.
6.
Two middles.
The average of the 5th and the 6th.
Mean = 40/5 = 8. Median = 6. Mode = 6. 17 pulls the mean upwards.
Pick a type. The 35 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
Your own purpose.
Primary.
The difference.
Largest − smallest.
The limit rule.
Into 5–10.
A histogram touches.
Gaps.
Continuous classes.
They touch.
(8/20)×10.
4.
The average.
15.
Divide the sum.
Σx / n.
Each value × its count.
Σ(fx) / Σf.
(5+1)/2.
The third.
The greatest count.
The most frequent value.
40/5.
8.
Two middles.
The average of the 5th and the 6th.
False — measuring yourself is primary.
True.
False — one has gaps, the other has touching rectangles.
False — the length is (f / width) × minimum width.
True.
True.
False — increasing order comes first.
True — two values can appear most often, equally.
The range.
21.
The count.
3.
12/4.
3.
Unequal width.
4.
Class mark.
15.
The mean.
8.
(5+1)/2.
3.
Twice.
6.
Mean is the average, median the middle, mode the most frequent, range the difference.
1 is collection, 2 is the table, 3 is the bar graph, and 14.4 is the three measures.
Assertion (A): The rectangles of a histogram touch.
Reason (R): It is the graph of continuous classes and the area is proportional to the frequency.
Both are true and R is the reason.
Assertion (A): Mean = sum / n.
Reason (R): The mode is the most frequent value.
Both are true, but R does not explain the mean.
Assertion (A): For unequal widths the length is adjusted.
Reason (R): The raw frequency is always the height.
A is true. R is false.
Assertion (A): Primary data are copied from a newspaper.
Reason (R): Secondary data come from another source.
A is false. R is true.
Assertion (A): The median of 4, 6, 6, 7, 17 is 6 and the mean is 8.
Reason (R): 17 pulls the mean up, not the middle place.
Both are true and R is the reason.
Gaps mean a bar graph. Touching rectangles and area mean a histogram.
The sum and Σfx are the mean. The middle is the median. The most frequent is the mode.
Data the investigator gathers for a purpose of their own are primary.
Range = largest value − smallest value.
(lower limit + upper limit) / 2.
x̄ = (Σx) / n.
The ((n+1)/2)th place.
Mean 8, median 6, mode 6.
(8/20)×10 = 4.
The mark = 35. Length = 20/5 = 4 cm.
Mean = 60/3 = 20. Median = 10. 40 pulls the mean, so the median is the better representative.
Gathering yourself is primary. Taking from a source is secondary. A bar graph has gaps. A histogram touches. Range = 21 cm.
Mean is sum/n, median is the middle, mode is the most frequent. The values are 8, 6 and 6.
1 collection. 14.1 primary or secondary. 2 frequency table. 14.2 tables. 3 bar graph. 14.3 graphs. 14.4 mean, median, mode.
This model set is for practice. It is not a question from any year’s annual examination. Annual questions will be added only when a source page is available.
The average.
45.
The area.
Frequency and width.
12/3.
4.
True.
Median 10. Mean 20. 40 pulls the mean.
These are competency-based practice questions. They are not copies of a CBSE paper.
The source is someone else.
Secondary.
The mean gets pulled.
The median.
Assertion (A): A histogram has no gap between rectangles.
Reason (R): So the width never matters.
A is true. R is false — for unequal widths the length changes.
False — write the scale on the axis and start at zero.
Sum 75, mean 15. Median 9. One large day pulled the mean, so the median tells the fairer story. The unit is thousand rupees.
Measuring yourself is primary. A register is secondary. The height group is a primary collection.
Switch board with BSEB | CBSE above. The lessons follow the same NCERT chapter.
This page has no verified annual-exam question, because no source page has been added. The model set below is practice in the board pattern.
🏛️ Model questions on one page →
The verified label will be used only when a source page for the question is available.
These are case and assertion-reason practice items. Do not treat them as past CBSE questions.
Wrong questions return soon; correct ones return after a few days.
What you learned
| What | Keep this |
|---|---|
| Mean | Σx / n |
| Median | middle value |
| Mode | most frequent |
| Class mark | (lower+upper)/2 |
| Histogram | areas ∝ frequency |
| Unequal width | (f / width) × min width |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.