Recall the table of Activity 2.1 — phenolphthalein in a base…
Phenolphthalein is colourless in acid and pink in a base. NaOH is a base.
Class 10 · Science · Chapter 2 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Acids, Bases and Salts
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अम्ल और क्षारक — स्वाद से सूचक तक · NCERT 2.1, 2.1.1 · Activities 2.1, 2.2 · In-text Q page 18
The sour taste of food comes from acids and the bitter taste from bases. But in a laboratory nothing is ever tasted — so we use indicators.
Litmus is a purple dye extracted from lichen, a plant of the Thallophyta group. In a solution that is neither acidic nor basic it stays purple. Turmeric, red cabbage leaves and the coloured petals of hydrangea, petunia and geranium are also natural indicators. Methyl orange and phenolphthalein are synthetic indicators.
Collect HCl, H2SO4, HNO3, CH3COOH, NaOH, Ca(OH)2, KOH, Mg(OH)2 and NH4OH from the laboratory. Put a drop of each on a watch-glass and test it with a drop of red litmus, blue litmus, phenolphthalein and methyl orange. Record your observations in Table 2.1.
| Indicator | In acid | In base |
|---|---|---|
| Blue litmus | red | no change |
| Red litmus | no change | blue |
| Phenolphthalein | colourless | pink |
| Methyl orange | red | yellow |
(Board questions ask exactly these indicator colours — learn the table.)
Keep finely chopped onion with strips of cloth in a bag in the fridge overnight — the strips pick up the onion smell. Put dilute HCl on one strip and dilute NaOH on another: in the base (NaOH) the onion smell is lost, in the acid it stays. The smell of vanilla essence and clove oil is also destroyed in a base.
Substances whose odour changes in an acidic or basic medium are called olfactory indicators — very useful for visually impaired students.
When basic soap is rubbed on a turmeric (curry) stain on a white cloth, the stain turns reddish-brown, and after rinsing with water it is yellow again — turmeric is a natural indicator.
Question: Three test tubes contain distilled water, an acidic solution and a basic solution. You are given only red litmus paper — how will you identify each?
Answer (structure):
Objective questions often ask “What colour does phenolphthalein give in a base?” (pink) and “Litmus is obtained from…?” (lichen). Learn the colour table of all four indicators.
CBSE asks reasoning questions like “identify three solutions using only red litmus” — write both the sequence and the reason.
Recall the table of Activity 2.1 — phenolphthalein in a base…
Phenolphthalein is colourless in acid and pink in a base. NaOH is a base.
True — litmus is a natural indicator obtained from lichen; it is purple in a neutral solution.
The smell of an olfactory indicator changes in a basic medium.
Onion, vanilla and clove oil are olfactory indicators — their smell disappears in a base (NaOH) and stays in an acid.
क्रियाकलाप 2.3, 2.4 — अम्ल और क्षारक की धातु से अभिक्रिया · NCERT 2.1.2 · Activities 2.3, 2.4 · Exercises 5, 10
Take zinc granules in a test tube and add dilute sulphuric acid. Fix the tube in a stand and pass the gas from the delivery tube through soap solution — gas-filled bubbles form. Bring a burning candle near the bubbles: the gas burns with a “pop” sound. It is hydrogen.
Repeat with dilute HCl, HNO3 and CH3COOH — record your observations. Every acid gives a salt and hydrogen gas with the metal.
Take zinc granules and NaOH solution in a test tube and warm it. Hydrogen is given off here too, and the salt sodium zincate is formed.
(Na2ZnO2 = sodium zincate — its negative ion is made of the metal and oxygen.) Caution: such reactions do not happen with all metals.
| Word equation | Balanced equation |
|---|---|
| zinc + dilute sulphuric acid → zinc sulphate + hydrogen | Zn + H2SO4 → ZnSO4 + H2 |
| magnesium + dilute hydrochloric acid → magnesium chloride + hydrogen | Mg + 2HCl → MgCl2 + H2 |
| aluminium + dilute sulphuric acid → aluminium sulphate + hydrogen | 2Al + 3H2SO4 → Al2(SO4)3 + 3H2 |
| iron + dilute hydrochloric acid → iron(II) chloride + hydrogen | Fe + 2HCl → FeCl2 + H2 |
Question: Equal lengths of magnesium ribbon are taken in test tubes A and B. HCl is added to A and acetic acid (CH3COOH) to B — same amount and concentration. In which tube will fizzing be more vigorous, and why?
Answer: In tube A. HCl is a strong acid — it ionises completely in water and gives more H+; acetic acid is weak — it gives fewer H+. More H+ = faster reaction = more vigorous fizzing of H2.
A 2-mark BSEB question: “Which gas is evolved when an acid reacts with a metal? How will you test it?” — write the equation and the pop test.
CBSE asks comparison questions like Exercise 10 (HCl vs CH₃COOH) — explain with strong/weak acid and the amount of H⁺.
This gas burns with a “pop” near a burning candle.
There are 2 Na atoms on the right — what goes before NaOH on the left?
Na: 2 = 2, O: 2 = 2, H: 2 = 2, Zn: 1 = 1 ✓ — sodium zincate + hydrogen.
Which acid gives more H⁺ ions?
HCl ionises completely and gives more H⁺, so H₂ forms faster in A.
क्रियाकलाप 2.5 — धातु कार्बोनेट और हाइड्रोजनकार्बोनेट + अम्ल · NCERT 2.1.3 · Activity 2.5 · In-text Q page 22 (Q3) · Exercise 2
Take sodium carbonate (Na2CO3) in test tube A and sodium hydrogencarbonate (NaHCO3) in B and add dilute HCl to both — a gas comes out with brisk effervescence. Pass it through lime water Ca(OH)2: it turns milky. The gas is CO2.
Why milky? Insoluble white calcium carbonate forms:
With excess CO2 the milkiness disappears — soluble calcium hydrogencarbonate forms:
Question: Metal compound A reacts with dilute HCl to produce effervescence. The gas evolved extinguishes a burning candle. Write a balanced equation if one of the compounds formed is calcium chloride.
Answer: The gas that puts out a candle is CO2, and the salt is CaCl2 — so A = calcium carbonate (CaCO3, e.g. limestone/marble).
“The gas that turns lime water milky” and “why the milkiness disappears on passing excess gas” — both equations keep appearing in 2-mark questions.
CBSE asks the Exercise 2 type MCQ (“egg-shell + solution → milky”) and the “identify compound A” case question.
An acid is needed on a carbonate to release CO₂ — which of the four is an acid?
Egg-shell is CaCO₃; only HCl (an acid) releases CO₂ from it. The other three are salts. (NCERT Exercise 2)
There are 2 Na on the left — put 2 before NaCl, then count Cl.
Na: 2 = 2, C: 1 = 1, O: 3 = 3, H: 2 = 2, Cl: 2 = 2 ✓
उदासीनीकरण और ऑक्साइड — क्रियाकलाप 2.6, 2.7 · NCERT 2.1.4, 2.1.5, 2.1.6 · Activities 2.6, 2.7 · In-text Q page 22 (Q1) · Exercises 3, 14
Take about 2 mL dilute NaOH in a test tube and add two drops of phenolphthalein — the solution turns pink. Now add dilute HCl drop by drop — at some point the colour disappears (the acid has cancelled the effect of the base). Add a few drops of NaOH again — the colour is pink again.
An acid and a base cancel each other's effect and form salt and water — this is a neutralisation reaction.
Take a little copper(II) oxide (black) in a beaker and add dilute HCl slowly while stirring. The solution turns bluish-green and the oxide dissolves — copper(II) chloride forms.
This is just like base + acid, so metallic oxides are basic.
In Activity 2.5, CO2 (an oxide of a non-metal) reacted with lime water Ca(OH)2 (a base) to give salt and water — exactly what an acid does. So non-metallic oxides are acidic.
Q1: Why should curd and sour substances not be kept in brass and copper vessels?
Answer: Curd and sour foods contain acids (lactic, citric etc.). These react with the copper/brass metal to form poisonous salts, spoiling the food and making it harmful.
Exercise 3: 10 mL of NaOH solution is completely neutralised by 8 mL of HCl. How much of the same HCl is needed for 20 mL of the NaOH?
Answer: Twice the NaOH → twice the HCl = 16 mL (option d).
“What is a neutralisation reaction? Give two examples” (Exercise 14) — a sure 2-mark question. Write the definition + two balanced equations (NaOH + HCl; Ca(OH)₂ + H₂SO₄).
CBSE asks an observation-based question on Activity 2.6: “Why did the pink colour disappear?” — mention both the indicator and neutralisation.
The base has doubled, so the acid…?
In neutralisation acid and base react in a fixed ratio — double the NaOH, double the HCl: 2 × 8 = 16 mL. (NCERT Exercise 3)
The salt formed is CuCl₂ — the colour of copper(II) salts?
Choose the nature of this oxide and what it reacts with to give salt + water: CO2
CO₂ is the oxide of the non-metal carbon.
Non-metallic oxides are acidic — CO₂ reacts with the base Ca(OH)₂ to give CaCO₃ + H₂O.
सभी अम्लों में क्या समान है? — H⁺ आयन, विद्युत चालन, शुष्क HCl · NCERT 2.2, 2.2.1 · Activities 2.8, 2.9 · In-text Q page 25 (Q1–3) · Exercises 6, 7, 8
Fix two nails on a rubber cork in a beaker and connect them to a 6 V battery, a bulb and a switch. Pour dilute HCl, dilute H2SO4, a glucose solution and alcohol into the beaker in turn.
Observation: in the acid solutions the bulb glows; in glucose and alcohol it does not.
Conclusion: acids give ions in water — the cation H+ — so current flows. Glucose and alcohol contain hydrogen but do not give H+ in water; so they are not acids (Exercise 6).
Take about 1 g NaCl in a test tube, add conc. H2SO4 and heat — HCl gas forms and is dried by a guard tube containing anhydrous CaCl2. Bring dry blue litmus near this dry gas — no change. Moist blue litmus — red!
Why? H+ ions from HCl form only in the presence of water. H+ cannot exist alone — it joins a water molecule to make the hydronium ion H3O+:
That is why acids do not show acidic behaviour in the absence of water (Exercise 8).
Question: Why does distilled water not conduct electricity, whereas rain water does?
Answer: Distilled water is pure — it has no dissolved ions, so no current flows. Rain water has dissolved CO2 (and SO2, NO2) from the air forming carbonic acid etc., which give H+ and other ions — so rain water conducts.
“Why does dry HCl gas not change the colour of dry litmus?” — a favourite BSEB short-answer question. Mention the need for water and H₃O⁺.
CBSE asks a diagram-based question on Activity 2.8 — “in which beakers will the bulb glow and why?” Reason with ions formed / not formed.
Why did the bulb not glow in their solutions in Activity 2.8?
Acidic character comes from forming H⁺(aq) in water. Glucose/alcohol do not ionise — no ions, no current, no acidity. (Exercise 6)
False — dry HCl forms no H⁺ ions; only with water (moisture) does H₃O⁺ form and litmus turn red.
The name starts with “hydro…” and the formula is H₃O⁺.
H⁺ cannot exist alone; H⁺ + H₂O → H₃O⁺ (hydronium ion).
क्षारक जल में, क्षार क्या है, और तनुकरण — अम्ल को जल में डालो · NCERT 2.2.1 · Activity 2.10 · In-text Q page 25 (Q4–6)
Substances that give hydroxide ions OH−(aq) on dissolving in water are bases. Bases that are soluble in water are called alkalis — e.g. NaOH, KOH, NH4OH; Ca(OH)2 is sparingly soluble. All alkalis are bases, but not all bases are alkalis (Cu(OH)2, Fe(OH)3 are insoluble bases). Alkalis are soapy to touch, bitter and corrosive.
Neutralisation in ions: the H+ of the acid and the OH− of the base combine to form water —
Take 10 mL water in a beaker, add a few drops of conc. H2SO4 and swirl slowly. Touch the base of the beaker — warm! Repeat with NaOH pellets — warm again. Mixing a concentrated acid or base with water is highly exothermic.
When diluting a concentrated acid, add the acid slowly to water, with stirring. If you add water to concentrated acid, so much heat is released that the mixture may boil and splash out, cause burns and even crack the glass container (local over-heating).
Effect of dilution: adding water decreases the concentration of H3O+ (or OH−) ions per unit volume — the solution becomes dilute. Dissolving more NaOH in NaOH solution increases the OH− concentration.
Q4: While diluting, why add acid to water and not water to acid? — Answer: the process is highly exothermic; adding water to acid may make the mixture splash out and cause burns or crack the vessel. Adding acid slowly to water spreads the heat through the larger amount of water.
Q5: How is the H3O+ concentration affected on diluting an acid? — it decreases (fewer ions per unit volume).
Q6: How is OH− concentration affected when more base is dissolved in NaOH solution? — it increases.
“Why is acid added to water?” is asked for 2 marks almost every year — write the word exothermic and splashing/burns.
CBSE assertion–reason: “A: All alkalis are bases. R: All bases are soluble in water.” — A true, R false.
The process is exothermic — where is it safe to spread the heat?
Adding acid slowly to water spreads the heat through a large volume of water; the reverse can make the mixture splash out.
False — only water-soluble bases (NaOH, KOH…) are alkalis. Insoluble bases like Cu(OH)₂ are not alkalis. The correct statement: all alkalis are bases.
On dilution the number of ions stays the same but the volume increases — concentration per unit volume decreases (it does not become zero).
pH पैमाना — क्रियाकलाप 2.11 · NCERT 2.3 · Activity 2.11
pH tells how many H⁺ (hydronium) ions a solution has. The scale runs from 0 to 14.
A drop of one pH unit means the H⁺ concentration rises about ten times. So a solution of pH 2 is a stronger acid than one of pH 3.
Test a few everyday solutions with universal indicator or pH paper and write the nature of each. The colours are only a rough guide.
| Substance | Approx. pH | Nature |
|---|---|---|
| Dilute HCl | 1 | strong acid |
| Lemon juice | 2–3 | acid |
| Vinegar | 3 | acid |
| Milk | 6 | weak acid |
| Pure water | 7 | neutral |
| Baking-soda solution | 8–9 | weak base |
| Lime water | 10–11 | base |
| Dilute NaOH | 13–14 | strong base |
Question: Two solutions have pH 1 and pH 5. Which is more acidic, and why?
Answer: The solution of pH 1 is more acidic, because a lower pH means a higher concentration of H⁺ ions. The gap is 4 units, so the H⁺ concentration is about 10⁴ = 10,000 times higher.
Objective items ask “which is stronger, pH 2 or pH 4?” — always pick the lower pH. Also remember the scale is 0–14.
A case may give a table and ask which solution harms teeth or metal. Tie pH to the amount of H⁺ and give the reason in one sentence.
The lower the pH, the more H⁺.
pH 2 is the smallest, so it has the most H⁺. pH 8 is basic.
True — pH 7 is neutral. Below 7 is acid and above 7 is base.
The top end of the scale.
A strong base (such as dilute NaOH) has a pH near 13–14.
pH का दैनिक जीवन और मिट्टी — क्रियाकलाप 2.12 · NCERT 2.3 · Activity 2.12
Take about 2 g of soil and 5 mL of water in a test tube, shake, and filter. Read the pH of the filtrate with universal indicator paper. Most crops grow well in soil that is about neutral to slightly acidic (around 6–7). Very acidic soil is treated with lime (CaO or Ca(OH)₂) to raise the pH.
Question: After overeating there is a burning feeling. Lemon, vinegar or baking soda — which would you choose?
Answer: The burning comes from extra acid. Lemon and vinegar are themselves acids, so they would make it worse. Baking soda is a mild base — it neutralises the acid to a salt and water, so that is the right remedy.
For 2 marks on “why do teeth decay?”: sweets → acid in the mouth → pH below 5.5 → enamel decays. Also write one way to prevent it.
A case may contrast bee and wasp stings. A base for the acidic sting, a weak acid for the basic sting — do not swap the pair.
A limit a little below neutral.
When the mouth pH falls below 5.5, the calcium phosphate of enamel decays.
False — milk of magnesia, Mg(OH)₂, is a base (an antacid). It neutralises the extra acid.
A bee releases methanoic acid.
A mild base (baking soda) neutralises the acidic sting. Vinegar is for a wasp’s basic sting.
लवणों के परिवार और उनके विलयन का pH — क्रियाकलाप 2.13, 2.14 · NCERT 2.4 · Activities 2.13, 2.14
Neutralisation of an acid and a base gives a salt and water. Salts made from the same acid sit in one family, because they share the same anion.
| Family | Parent acid | Examples |
|---|---|---|
| Chloride | HCl | NaCl, KCl, CaCl₂ |
| Sulphate | H₂SO₄ | Na₂SO₄, CuSO₄, CaSO₄ |
| Nitrate | HNO₃ | NaNO₃, KNO₃ |
| Carbonate | H₂CO₃ | Na₂CO₃, CaCO₃ |
| Sodium salts | various acids | NaCl, Na₂SO₄, Na₂CO₃, NaHCO₃ |
Potassium sulphate K₂SO₄, sodium sulphate Na₂SO₄, calcium sulphate CaSO₄, magnesium sulphate MgSO₄, copper sulphate CuSO₄, sodium chloride NaCl, sodium nitrate NaNO₃, sodium carbonate Na₂CO₃ and ammonium chloride NH₄Cl. Keep the charges balanced: SO₄²⁻ needs two Na⁺, but only one Ca²⁺.
Dissolve the salt in distilled water and test with litmus and pH paper. The rule is simple:
Answer: Na₂CO₃ is made from the strong base NaOH and the weak carbonic acid. In water the carbonate ion reacts with water to give OH⁻, so the pH is above 7 and red litmus turns blue.
Matching items often pair a salt with the nature of its solution. Learn three pairs: NaCl neutral, washing soda basic, NH₄Cl acidic.
If the reason is asked, do not stop at “pH is 8”. Write that it comes from a strong base and a weak acid, so the solution is basic.
Both HCl and NaOH are strong, so a solution of NaCl stays neutral (pH ≈ 7).
Strong acid + weak base.
NH₄Cl comes from strong HCl and weak NH₄OH, so the solution is acidic. Na₂CO₃ and CH₃COONa are basic.
Choose the nature of each salt solution.
The solution leans toward whichever parent — acid or base — is strong.
Na₂CO₃ is basic, KNO₃ (strong + strong) is neutral, CuSO₄ (strong acid + weak base) is acidic.
साधारण नमक और क्लोर-क्षार प्रक्रिया · NCERT 2.4.1, 2.4.2
The salt in our food is sodium chloride (NaCl) — from sea water and from rock salt. Electrolysis of its aqueous solution (brine) is called the chlor-alkali process, because the products are chlorine and an alkali (NaOH).
Chlorine is released at the anode (positive electrode) and hydrogen at the cathode (negative electrode). NaOH is not formed at the anode — it stays in the solution.
Question: During the electrolysis of brine one gas first bleaches moist red litmus. Which gas is it?
Answer: Chlorine. It is released at the anode and is a bleaching agent, so it removes the colour of litmus. The other gas is H₂ — it burns with a pop and does not bleach litmus.
Do not forget water in the equation — without water, NaOH is not formed. The coefficients are 2, 2, 2, 1, 1.
A case may give a table of products and uses. Tie each gas to its electrode; do not write only the name.
Cl₂ needs two NaCl, and two water as well.
Cl₂ is released at the anode and H₂ at the cathode. NaOH stays in the solution.
True — positive ions move to the cathode; reduction of water produces H₂.
विरंजक चूर्ण · NCERT 2.4.3
Passing chlorine over dry slaked lime, Ca(OH)₂, gives bleaching powder. In the examination the formula written is CaOCl₂. The atom-balanced form is:
Ca(OCl)₂ is the active part — it releases chlorine for bleaching and disinfection. CaOCl₂ is the short formula of that mixture.
Do not leave it open to air — moisture and CO₂ slowly make it lose chlorine.
Question (2 marks): Write the formula of bleaching powder and one use in drinking water.
Answer: Formula CaOCl₂ (or Ca(OCl)₂). It releases chlorine in water, which kills germs — so it keeps drinking water from becoming infected.
“CaOCl₂ is the formula of…?” comes straight as an objective item. Slaked lime is Ca(OH)₂, quicklime is CaO — do not mix them up.
When you write a use, name the industry (textiles / drinking water). Do not stop at “cleaning”.
Bleaching powder is made by passing chlorine over dry slaked lime.
True — it releases chlorine and kills germs.
Write CaOCl₂ in a board answer. In the balanced equation the active part is Ca(OCl)₂.
बेकिंग सोडा — NaHCO₃ · NCERT 2.4.4
The formula of baking soda is NaHCO₃. It is a mildly basic salt. In the soda-ash process it is formed by:
On heating it decomposes — this is what makes a cake or bread rise, because bubbles of CO₂ get trapped in the dough.
Answer: NaHCO₃ alone needs the heat of an oven to make the dough rise. Baking powder also contains a solid acid such as tartaric acid. As soon as water is added, the acid and NaHCO₃ give CO₂ even at room temperature, so the dough rises without strong heat. The leftover acid finally neutralises sodium carbonate, otherwise the cake would taste bitter.
The difference between NaHCO₃ and Na₂CO₃·10H₂O is asked every year. Baking soda gives CO₂ on heating; washing soda is mainly for cleaning and glass.
Do not write “air” as the reason a cake rises. The reason is CO₂ gas, and write 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂.
Double NaHCO₃ so that sodium is two on the left.
Decomposition of NaHCO₃ releases CO₂, which makes bubbles in the dough.
True — it is a mild base and neutralises extra stomach acid.
धावन सोडा — Na₂CO₃·10H₂O · NCERT 2.4.5
Heating baking soda gives sodium carbonate. Dissolving it in water and recrystallising attaches ten molecules of water of crystallisation — that is washing soda.
It is a basic salt. Uses:
Answer: In Na₂CO₃·10H₂O the 10H₂O after the dot is water of crystallisation. Those water molecules are part of the crystal lattice, not water standing separately. On heating, this water leaves as steam and the crystal loses its shape.
Writing ·10H₂O in the formula is compulsory. If you write only Na₂CO₃, that is soda ash, not washing soda.
Write the hard-water use with the reason: Ca²⁺/Mg²⁺ become insoluble carbonates.
Washing soda is the decahydrate of sodium carbonate — Na₂CO₃·10H₂O.
Glass, soap and paper are all accepted answers.
False — Na₂CO₃ comes from a strong base and a weak acid, so the solution is basic.
क्रिस्टलन-जल और प्लास्टर ऑफ़ पेरिस — क्रियाकलाप 2.15 · NCERT 2.4.6, 2.4.7 · Activity 2.15
Heat a few crystals of blue copper sulphate in a dry boiling tube. The colour changes from blue to white and drops of water collect at the cool mouth of the tube. Those drops came from water inside the crystal. Put 2–3 drops of water on the cold white powder — the blue colour returns.
Water fixed in a definite proportion in the crystal lattice is called water of crystallisation. CuSO₄·5H₂O has five molecules, so it is copper sulphate pentahydrate.
When gypsum, CaSO₄·2H₂O, is heated carefully at 373 K (100 °C), three-quarters of its water of crystallisation leaves. What remains is plaster of Paris — CaSO₄·½H₂O. The atom-balanced form:
On adding water it sets again as a hard mass of gypsum — that is how casts, bandages and toys set. The volume increases a little while setting, so fine lines of a mould get filled.
Caution: keep POP away from moisture, in an airtight tin. If heated too strongly it becomes dead-burnt gypsum and then does not set properly.
Answer: Heat removed the water of crystallisation from CuSO₄·5H₂O and left white CuSO₄. When drops are added, those five molecules join the lattice again and the blue pentahydrate is re-formed. The return of the colour proves that the water was part of the crystal, not a separate impurity.
Write the temperature 373 K. Both ½H₂O and (CaSO₄)₂·H₂O are accepted — half a molecule per formula unit.
Write Activity 2.15 in the order of observations: blue → heat → white + drops → water → blue again. Marks are cut if the order breaks.
As water of crystallisation leaves, CuSO₄·5H₂O becomes white anhydrous CuSO₄.
True — heating CaSO₄·2H₂O at 373 K gives CaSO₄·½H₂O.
Write the five water molecules separately on the right.
बोर्ड रिवीजन — पूरा अध्याय एक नज़र में · Chapter 2 · equation sheet
| Name | Formula | One identity |
|---|---|---|
| Baking soda | NaHCO₃ | heat → CO₂ |
| Washing soda | Na₂CO₃·10H₂O | glass, soap |
| Bleaching powder | CaOCl₂ | Cl₂ + Ca(OH)₂ |
| Gypsum | CaSO₄·2H₂O | raw material of POP |
| Plaster of Paris | CaSO₄·½H₂O | 373 K, sets with water |
| Blue vitriol | CuSO₄·5H₂O | heat → white |
Question: A white powder gives CO₂ on heating, and the solid left crystallises with water to washing soda. What was the original powder?
Answer: Baking soda, NaHCO₃. On heating, 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂. The Na₂CO₃ that remains takes up ten water molecules and becomes Na₂CO₃·10H₂O.
In a long answer write the general equation first, then one balanced example, then the test (pop or lime water). All three parts earn full marks.
Assertion-reason items pair pH with the nature of a salt. The reason is a correct explanation only when it is the cause of the assertion; being true is not enough.
CaOCl₂ is bleaching powder. Baking soda is NaHCO₃, washing soda is Na₂CO₃·10H₂O and gypsum is CaSO₄·2H₂O.
Acid + metal → salt + hydrogen. It is identified by the pop sound.
True — for example CuO + 2HCl → CuCl₂ + H₂O. That is base-like behaviour.
Pick a type. The 45 check questions at the end of each lesson are separate — all correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
Look at the indicator table.
Phenolphthalein is colourless in acid and pink in a base.
Red in acid, yellow in a base.
Methyl orange turns red in an acidic medium.
A plant of Thallophyta.
Litmus is a purple dye extracted from lichen.
Olfactory indicators change in a base.
NaOH is a base — the smell of onion, vanilla and clove is lost in it.
The gas with the pop sound.
Acid + metal → salt + hydrogen.
The gas from a carbonate and an acid.
CO₂ forms a white precipitate of CaCO₃ with lime water, Ca(OH)₂.
The colour of copper(II) chloride.
CuO + 2HCl → CuCl₂ + H₂O. CuCl₂ is blue-green.
Conductivity comes from ions.
Glucose and alcohol do not give H⁺, so no current flows.
The acidic property comes from the ion.
Without water HCl cannot give H⁺, so dry litmus does not change.
Activity 2.10 is exothermic.
Add the acid slowly to water and swirl. The other way round, water can boil and splash.
Lower pH = more H⁺.
At pH 1 the amount of H⁺ is the greatest.
A little below neutral.
Below pH 5.5 the calcium phosphate of enamel decays.
It has to neutralise extra stomach acid.
A base such as Mg(OH)₂ makes a salt and water with the extra acid.
Strong base + weak acid.
A solution of sodium carbonate is basic, with pH above 7.
Chlorine at the positive electrode.
Cl₂ at the anode, H₂ at the cathode, and NaOH in the solution.
The product of lime and chlorine.
Bleaching powder is CaOCl₂. CaO is quicklime.
The gas from heating baking soda.
2NaHCO₃ → Na₂CO₃ + H₂O + CO₂.
Ten waters of crystallisation.
Washing soda is sodium carbonate decahydrate.
Water of crystallisation leaves.
The colour turns white and drops of water collect on the tube.
Near 100 °C, carefully.
Heating gypsum at 373 K gives CaSO₄·½H₂O.
False — alkalis are only those bases that dissolve in water. CuO is a base but not an alkali.
True — glucose contains hydrogen and still is not an acid.
True — CaCO₃ changes into soluble Ca(HCO₃)₂.
False — add the acid slowly to water. The process is exothermic.
True — a salt of a strong acid and a strong base.
False — it comes from a strong acid and a weak base, so it is acidic.
True — that is why a base such as baking soda soothes it.
False — moisture and CO₂ make it lose chlorine.
True — this is how a bandage or a cast sets.
False — a base gives OH⁻. Taste is never used as a test in the laboratory.
The gas given off is hydrogen.
Neutralisation produces a salt and water.
A hydrogen ion does not stay alone; it becomes H₃O⁺.
Not every base is an alkali.
7 is the neutral point.
Sodium hydrogencarbonate.
The formula is Na₂CO₃·10H₂O.
Two molecules of water of crystallisation.
The pentahydrate — five waters.
Never pour water into the acid.
NaHCO₃ baking soda, Na₂CO₃·10H₂O washing soda, CaOCl₂ bleaching powder, CaSO₄·½H₂O plaster of Paris.
Phenolphthalein pink, methyl orange red in acid, blue litmus red in acid, red litmus blue in a base. Methyl orange and blue litmus are both red in acid.
NaCl is neutral. Na₂CO₃ and CH₃COONa are basic. NH₄Cl is acidic.
Assertion (A): Hydrogen is released when Zn reacts with dilute HCl.
Reason (R): An acid reacts with a metal to give a salt and hydrogen gas.
Both A and R are true and R is the reason for A.
Assertion (A): A glucose solution does not turn blue litmus red.
Reason (R): Glucose contains hydrogen.
Both are true, but containing hydrogen does not explain why it is not an acid — ions must form.
Assertion (A): Dry HCl gas does not change the colour of dry blue litmus.
Reason (R): Dry HCl already contains free H⁺ ions.
A is true, R is false. H⁺ is formed only in the presence of water.
Assertion (A): A solution of pH 2 is more acidic than one of pH 5.
Reason (R): A lower pH means a higher H⁺ concentration.
Both are true and R is the correct explanation.
Assertion (A): All bases dissolve in water to form alkalis.
Reason (R): Alkalis are the bases that are soluble in water.
A is false — CuO does not dissolve. R is the correct definition.
Assertion (A): A cake rises when baking soda is heated.
Reason (R): On heating, NaHCO₃ gives carbon dioxide.
Both are true and CO₂ is the reason the cake rises.
Identify each reaction.
The first is acid-metal, the second neutralisation, the third a carbonate.
Identify the gas.
Pop is hydrogen, milkiness is carbon dioxide, bleaching is chlorine.
Choose the nature of the oxide.
Metal oxides are usually basic, non-metal oxides usually acidic. Water is neutral.
Choose the nature from the pH.
Below 7 acid, 7 neutral, above 7 base.
A base that dissolves in water is called an alkali.
The gas burns with a pop when a burning splint is brought near it.
Water fixed in a definite proportion in the crystal lattice is water of crystallisation. Example: CuSO₄·5H₂O.
Insoluble CaCO₃ and extra CO₂ form soluble calcium hydrogencarbonate.
The one that turns red litmus blue is the base. Dip that blue paper in the rest — the one that turns it red again is the acid. The one with no change is water.
Sour substances are acidic. They can react with the copper or brass and form poisonous salts.
An acid is sour, turns blue litmus red and gives H⁺ in water. A base is bitter and soapy, turns red litmus blue and gives OH⁻ in water.
Tooth enamel decays when the mouth pH falls below 5.5. If the stomach has too much acid, an antacid such as Mg(OH)₂ neutralises it.
Cl₂ is used to disinfect drinking water, H₂ to hydrogenate vegetable oil, and NaOH to make soap.
Baking soda is NaHCO₃; on heating it gives CO₂ and makes a cake rise. Washing soda is Na₂CO₃·10H₂O; it is used in glass and soap and removes hardness of water.
Prepare dry HCl from solid NaCl and concentrated sulphuric acid. Dry blue litmus does not change; moist blue litmus turns red. So H⁺ forms only when water is present: HCl + H₂O → H₃O⁺ + Cl⁻.
Heating gypsum, CaSO₄·2H₂O, at 373 K gives plaster of Paris, CaSO₄·½H₂O. On adding water it sets again as a hard mass of gypsum. Uses: a cast for a broken bone, and decorative moulds.
Passing ammonia and carbon dioxide into brine gives baking soda: NaCl + H₂O + CO₂ + NH₃ → NaHCO₃ + NH₄Cl. On heating, 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂. Recrystallising Na₂CO₃ gives washing soda: Na₂CO₃ + 10H₂O → Na₂CO₃·10H₂O.
This model set is for practice. It is not a question from any year’s annual examination, so it is not marked “verified”. Annual questions will be added only when a source page is available.
The base that dissolves in water.
NaOH dissolves in water, so it is an alkali. CuO is a base but not an alkali.
Half the water of gypsum.
Gypsum is CaSO₄·2H₂O and POP is CaSO₄·½H₂O.
Ordinary rain is slightly acidic too; below 5.6 it is called acid rain.
Passing Cl₂ over Ca(OH)₂ gives CaOCl₂. Use: bleaching cloth, or disinfecting drinking water.
pH from 0 to 14 tells the amount of H⁺. Below 7 is acid (lemon, about pH 2), 7 is neutral (pure water), above 7 is base (NaOH, about pH 14). Enamel decays when the mouth pH falls below 5.5.
These are competency-based practice questions. They are not copies of a CBSE paper.
Enamel is attacked by acid.
The lowest pH gives the most H⁺. A (pH 2) is the most harmful to enamel.
A strong acid gives more H⁺.
HCl is a strong acid and acetic acid (vinegar) is weak. The reaction is faster in A.
Assertion (A): A farmer adds lime if the soil is too acidic.
Reason (R): Lime is a basic oxide and neutralises acid.
Both are true and R is the correct reason.
Assertion (A): A solid acid is also mixed into baking powder.
Reason (R): The acid makes baking soda more basic.
A is true. R is false — the acid makes CO₂ from NaHCO₃ and neutralises the carbonate that is left.
A is baking soda (NaHCO₃) and B is washing soda. 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂.
This is acid rain. It slowly dissolves a marble monument (CaCO₃) and, by lowering the pH of a river, harms fish and other aquatic life.
Switch board with BSEB | CBSE above. The lessons follow the same NCERT chapter.
This page has no verified annual-exam question, because no source page has been added. The model set below is practice in the board pattern.
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These are case and assertion-reason practice items. Do not treat them as past CBSE questions.
Wrong questions return soon; correct ones return after a few days.
What you learned
| What | Balanced equation |
|---|---|
| Acid + metal | Zn + H₂SO₄ → ZnSO₄ + H₂ |
| Base + metal | 2NaOH + Zn → Na₂ZnO₂ + H₂ |
| Acid + carbonate | Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂ |
| Neutralisation | NaOH + HCl → NaCl + H₂O |
| Basic oxide | CuO + 2HCl → CuCl₂ + H₂O |
| Chlor-alkali | 2NaCl + 2H₂O → 2NaOH + Cl₂ + H₂ |
| Baking soda, heat | 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂ |
| Blue vitriol, heat | CuSO₄·5H₂O → CuSO₄ + 5H₂O |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.