Class 9 · Science · Chapter 4 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27

Structure of the Atom

Structure of the Atom

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4. The memory picture of the first three Bohr shells labels K, L and M with 2, 8 and 8 electrons.

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  • 1 Charged particles — Activity 4.1
  • 2 The Thomson model
  • 3 Rutherford and the gold foil
  • 4 Bohr orbits and the neutron
  • 5 Sharing electrons into shells — Activity 4.2
  • 6 Valency and the outer shell
  • 7 Atomic number and mass number
  • 8 Isotopes and isobars
  • Chapter winner — every lesson at mastery ★

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1

Charged particles — Activity 4.1

आवेशित कण — क्रियाकलाप 4.1 · Bihar 4.1 · Activity 4.1

New
Charged particles+Nucleus in the centreElectrons in orbitsShells fill in order
A positive nucleus sits in the middle, electrons occupy fixed shells outside.
Charge by rubbing, particles inside the atomNotes

Dalton had called the atom indivisible. By the end of the century static electricity showed that the story was incomplete. On rubbing, an object becomes charged. The charge does not arrive as new matter from outside. It comes from particles inside the atom.

By 1900 one sub-atomic particle had been identified, the electron. The identification belongs to J. J. Thomson. The symbol is e−. The charge is taken as minus one and the mass as negligible.

Goldstein saw canal rays in 1886. They were positively charged radiations. The proton opened from them. The proton charge equals the electron charge with the opposite sign. The mass is about 2000 times the electron mass. The symbol is p+. The mass is taken as one unit and the charge as plus one. An atom with one proton and one electron is neutral.

Activity 4.1 — the comb and the glass rodActivity

This activity has two parts. Do not turn them into Activity 4.2.

A. Comb dry hair. Does the comb then attract small pieces of paper?

B. Rub a glass rod with a silk cloth and bring the rod near an inflated balloon. Watch what happens.

When two objects are rubbed they take up an electric charge. The question is where the charge came from. The answer is that the atom is divisible and contains charged particles. An electron comes away more easily. The proton stays inside.

Worked exampleExample

Question: An atom has one electron and one proton. What charge does it carry?

Formula: total charge = charge of the proton + charge of the electron.

Substitution: (+1) + (−1) = 0.

Unit: this is the same charge unit in which the proton is +1 and the electron is −1. The atom is neutral.

10-second revision
  • Electron: Thomson, charge −1
  • Proton: canal rays, charge +1, mass ~2000 times
  • One of each gives a total charge 0
Board tip · BSEBBoard tip

Join canal rays and the proton in one sentence. Only “a positive particle” stays incomplete.

Board tip · CBSEBoard tip

The factor 2000 belongs to the proton and the electron. The neutron mass is about equal to the proton mass.

Check your understandingall correct = mastery ★
1
Canal rays are —
Check
2
The mass of an electron is about equal to the mass of a proton.
Check
3
The electron was identified by ______.
Check
4
The charge of an atom with one proton and one electron is —
Check
5
Write both parts of Activity 4.1 and say where the charge comes from.
Check2 marks
Next lesson →
2

The Thomson model

थॉमसन का मॉडल · Bihar 4.2.1 · positive sphere

New
The Thomson model+Nucleus in the centreElectrons in orbitsShells fill in order
The first shell holds 2 electrons, the second 8. The outer shell decides the valency.
An atom like a watermelonNotes

Thomson was the first to give a model of the structure of the atom. Electrons are embedded in a sphere of positive charge, like currants in a Christmas pudding. The watermelon picture says the same thing. The red part is the positive charge and the seeds are the electrons.

Two points sit in the model. The atom is a positive sphere and the electrons are sunk in it. The negative and positive charges are equal, so the whole atom is neutral.

There is no nucleus in this model. Neutrality is explained. The later scattering experiment is not. It is not a Thomson statement that the nucleus holds only nucleons.

Do not add a nucleus to this modelCaution

The gold foil and the nucleus belong to Rutherford. If the question asks only for the neutral sphere of Thomson, writing the nucleus changes the answer.

Worked exampleExample

Question: Why is the atom neutral in the Thomson model?

Formula: total charge = positive charge + negative charge.

Substitution: the two charges are equal in size, so the sum is 0.

Unit: the result is 0 in the charge unit. The sphere is positive, the electrons are negative, and the whole atom is neutral.

10-second revision
  • Electrons embedded in a positive sphere
  • Equal charges, neutral atom
  • No nucleus in this model
Board tip · BSEBBoard tip

Write the two points in order: the sphere, then the equality of the charges.

Board tip · CBSEBoard tip

Keep the limit in one line too. The model does not explain the scattering.

Check your understandingall correct = mastery ★
1
In the Thomson model the atom has a separate nucleus.
Check
2
In the Thomson model the place of the electrons is —
Check
3
Write the two points of the Thomson model and one limit.
Check3 marks
4
In the Thomson model the positive charge is spread through a ______.
Check
Next lesson →
3

Rutherford and the gold foil

रदरफोर्ड और सोने की पत्ती · Bihar 4.2.2 · scattering · unnumbered picture

New
Rutherford and the gold foil+Nucleus in the centreElectrons in orbitsShells fill in order
A positive nucleus sits in the middle, electrons occupy fixed shells outside.
A thin foil, heavy alpha particlesNotes

Rutherford wanted to know how the electrons sit in the atom. Fast alpha particles were sent at a thin gold foil. The foil was about 1000 atoms thick, and still as thin as possible. Alpha particles are doubly charged helium ions. The mass is 4 u, so a fast particle carries a good deal of energy. Because they are heavier than protons, large deflections were not expected.

The results went the other way. Most particles went straight through. Some bent by small angles. About one in every 12000 bounced back. Rutherford found that rebound astonishing.

There are three conclusions. Most of the space is empty, because most particles did not bend. The positive charge occupies a very small space, because few particles bent. All the positive charge and the mass sit in a very small volume, because very few particles turned by about 180° and came back. The radius of the nucleus came out about 105 times smaller than the radius of the atom.

The nuclear model: there is a positive nucleus and nearly all the mass is there. Electrons revolve in circular paths. The nucleus is very small compared with the atom. A revolving electron can lose energy and fall into the nucleus, so the model does not explain the stability of the atom.

The unnumbered field pictureActivity

This picture has no activity number. Do not write 4.3.

A child with closed eyes who throws stones at a wall hears a sound every time. Thrown at a barbed-wire fence, most stones pass through the gaps and no sound comes. The gold foil is like that fence. Most alpha particles pass through empty space. A particle that comes back has hit the small dense place called the nucleus.

Worked exampleExample

Question: About how many of 12000 alpha particles rebound, and how much smaller is the nuclear radius than the atom?

Formula: rebounding particles = total particles / 12000. The radius ratio is about 1 : 105.

Substitution: 12000 / 12000 = 1 particle. The radius is about 105 times smaller.

Unit: the count is one particle. The radius comparison is a factor, not grams.

10-second revision
  • Most particles go straight, so the space is empty
  • About 1/12000 rebounds
  • Mass and positive charge sit in the nucleus
Board tip · BSEBBoard tip

Write the three observations and the three conclusions apart. Mixing them in one sentence costs marks.

Board tip · CBSEBoard tip

The drawback is a separate question. The discovery of the nucleus is right. The explanation of stability is not.

Check your understandingall correct = mastery ★
1
The gold-foil experiment discovered —
Check
2
Alpha particles are electrons.
Check
3
About one alpha particle in every ______ rebounds.
Check
4
Most alpha particles going straight through means —
Check
5
Write one drawback of the Rutherford model.
Check2 marks
6
On a foil of another metal the pattern of empty space and a small nucleus should still appear.
Check
Next lesson →
4

Bohr orbits and the neutron

बोहर की कक्षा और न्यूट्रॉन · Bihar 4.2.3 and 4.2.4

New
Bohr orbits and the neutron+Nucleus in the centreElectrons in orbitsShells fill in order
A positive nucleus sits in the middle, electrons occupy fixed shells outside.
An orbit that does not lose energyNotes

To remove the drawback of Rutherford, Niels Bohr stated two points. Only certain special orbits are allowed inside the atom. These are called discrete orbits. While revolving in these orbits the electron does not lose energy.

These orbits are also called energy levels. They are named K, L, M, N or n = 1, 2, 3, 4. When the shells are complete the atom is more stable and less reactive. That point opens later in valency.

In 1932 J. Chadwick found another particle. It has no charge and its mass is nearly equal to the proton mass. The name is neutron. The symbol is n. Every atom except hydrogen has neutrons in the nucleus. The mass of an atom is the sum of the masses of the protons and the neutrons. Both sit in the nucleus, so they are also called nucleons.

There are three particles: the electron negative, the proton positive, the neutron uncharged. A neutron is not made by sticking an electron and a proton together.

Worked exampleExample

Question: A helium atom has atomic mass 4 u and two protons in its nucleus. How many neutrons does it have?

Formula: neutrons = mass number − protons. The mass number here is 4.

Substitution: 4 − 2 = 2.

Unit: 2 neutrons. About 2 u of the mass belongs to them, because each neutron is about 1 u.

10-second revision
  • A discrete orbit does not radiate energy
  • Orbits K, L, M, N
  • Neutron: Chadwick, 1932, charge 0
Board tip · BSEBBoard tip

Write both Bohr points in full. Only “an orbit” does not separate him from Rutherford.

Board tip · CBSEBoard tip

In the helium question show 4 − 2 = 2. Only “two”, with no subtraction, stays incomplete.

Check your understandingall correct = mastery ★
1
According to Bohr, in a discrete orbit the electron —
Check
2
A neutron is formed by an electron and a proton joining.
Check
3
The neutron was discovered in 1932 by ______.
Check
4
If helium has 2 protons and mass 4 u, the neutrons are —
Check
5
Write the charge of the three sub-atomic particles and the name of the person linked with each.
Check3 marks
Next lesson →
5

Sharing electrons into shells — Activity 4.2

इलेक्ट्रॉन बाँटना — क्रियाकलाप 4.2 · Bihar 4.3 · Activity 4.2 · 2n^2

New
Three rules, the first eighteen elementsNotes

Bohr and Bury showed how to share electrons into orbits.

First rule: the maximum number of electrons in a shell is 2n2. n is the orbit number.

Shelln2n^2
K12
L28
M318
N432

Second rule: the outermost shell does not hold more than 8 electrons. Third rule: electrons are not put in an outer shell until the inner shells are filled. The filling is stepwise.

The table of the first eighteen elements stops here. Argon is 2, 8, 8. The 2n2 maximum of M is 18, but in argon M is the outer shell, so it holds 8. The counts 2, 8, 8 in the picture are the outer filling. The full capacity of M is 18. Helium has 2 electrons in its outer shell and valency 0. The octet of 8 belongs to the later inert elements.

Activity 4.2 — a static model of the first eighteenActivity

Make a static atomic model of the first eighteen elements that shows the electronic configuration. From hydrogen to argon, fill K, L and M. Fill the inner shell first. Carbon is 2, 4. Sodium is 2, 8, 1. Argon is 2, 8, 8. Do not write charges on the model. Write only the shell and the number of electrons.

First three shells — when M is outermostK · 2L · 8M · 8nucleusK shell · 2 electronsL shell · 8 electronsM shell · 8 electronsArgon is like this: 2, 8, 8By 2n² the M maximum is 18The outer shell holds at most 8The dots are electrons. The counts 2, 8, 8 are the outer filling, not the full capacity of M.
K has 2, L has 8, M has 8. This is the outer order of argon. By 2n^2 the maximum of M is 18, and the outer shell stops at 8.
Worked exampleExample

Question: What is the 2n2 maximum for the M shell? How many does argon have in M?

Formula: maximum = 2n2. For M, n = 3. The outer-shell rule is separate.

Substitution: 2 × 32 = 2 × 9 = 18. In argon M is outermost, so it holds 8. The configuration is 2, 8, 8.

Unit: the capacity is 18 electrons. That shell in argon has 8 electrons.

10-second revision
  • 2n^2: K 2, L 8, M 18, N 32
  • Outer shell at most 8
  • Sodium 2, 8, 1 and carbon 2, 4
Board tip · BSEBBoard tip

Write both 2n^2 and the outer limit. Do not turn the capacity of M into 8 by writing only 2, 8, 8.

Board tip · CBSEBoard tip

Sodium is 2, 8, 1. Both 2, 8 and 8, 2, 1 are the wrong order.

Check your understandingall correct = mastery ★
1
The 2n^2 maximum in the L shell is —
Check
2
The outermost shell can hold 18 electrons.
Check
3
The electronic configuration of sodium is ______.
Check
4
If both K and L are full, the total number of electrons is —
Check
5
Write the electron distribution of carbon and sodium. Which rule says the inner shell fills first?
Check3 marks
6
Activity 4.2 is a static model of the first eighteen elements.
Check
Next lesson →
6

Valency and the outer shell

संयोजकता और बाहरी कोश · Bihar 4.4 · octet

New
Valency and the outer shellNaClAn electron moved across — Na⁺ and Cl⁻
The metal gives electrons and becomes a positive ion; the non-metal takes them.
Lose, gain or shareNotes

The electrons of the outer shell are the valence electrons. If the outer shell is completely full, the valency is zero. Helium has 2 outer electrons. The later inert elements have 8. An outer shell of 8 electrons is an octet.

An atom loses, gains or shares electrons to complete the octet. The number of electrons used in that work is the valency. Hydrogen, lithium and sodium have one electron in the outer shell, so the valency is 1. Magnesium is 2, aluminium is 3.

If the outer electrons are close to a full shell, the count turns around. Fluorine has 7 in the outer shell. Losing seven is hard and gaining one is easy. The valency is 8 − 7 = 1, not 7. Oxygen has 6, so the valency is 2. Chlorine is 1, sulphur is 2. Silicon has 4 in the outer shell, so the valency is 4. The table gives phosphorus both 3 and 5.

Worked exampleExample

Question: Find the valency of oxygen, chlorine and magnesium.

Formula: near a full shell, valency = 8 − outer electrons. Far from it, valency = outer electrons.

Substitution: oxygen 8 − 6 = 2. Chlorine 8 − 7 = 1. Magnesium loses 2 outer electrons, valency 2.

Unit: the three answers are counts: 2, 1 and 2.

10-second revision
  • Valence electrons = the outer shell
  • Valency 0 when the outer shell is full
  • Valency of F and Cl is 1, of O and S is 2
Board tip · BSEBBoard tip

Do not write 7 for fluorine. The paper needs 8 − 7 on the page.

Board tip · CBSEBoard tip

Do not call helium an octet. Its full shell is 2 and the valency is 0.

Check your understandingall correct = mastery ★
1
The valency of fluorine is —
Check
2
The valency of silicon is ______.
Check
3
The valency of helium is 2 because the outer shell has 2 electrons.
Check
4
Write the valency of chlorine, sulphur and magnesium with a reason.
Check3 marks
Next lesson →
7

Atomic number and mass number

परमाणु क्रमांक और द्रव्यमान संख्या · Bihar 4.5 · Z and A

New
Atomic number and mass numberHHeLiBeBCNOFNeNaMgSimilar properties repeat down a group
Properties repeat with atomic number — down a group.
Protons are the identity, nucleons are the massNotes

The atomic number Z is the number of protons in the nucleus. Every atom of an element has the same Z. An element is identified by its protons. For hydrogen Z = 1. For carbon Z = 6. In a neutral atom the electrons also equal Z.

Almost the whole mass belongs to protons and neutrons. Both are in the nucleus and are called nucleons. Mass number = number of protons + number of neutrons. Carbon has 6 + 6 = 12, so the mass is 12 u. Aluminium has 13 protons and 14 neutrons, mass number 27.

The way to write it: mass number above, atomic number below, symbol in the middle. Nitrogen is 147N. This is not a chemical equation. The mass number of oxygen is 8 + 8 = 16. Sulphur is 16 + 16 = 32.

Worked exampleExample

Question: An atom has 8 electrons and 8 protons. Find the atomic number and the charge.

Formula: Z = number of protons. Charge = protons − electrons, in the neutral unit.

Substitution: Z = 8. Charge = 8 − 8 = 0.

Unit: the atomic number is 8. The charge is 0. This is a neutral oxygen atom.

10-second revision
  • Z = protons = electrons of a neutral atom
  • A = protons + neutrons
  • Nitrogen with 14 and 7
Board tip · BSEBBoard tip

Keep the mass number and the unit of atomic mass apart. The number is 32, the mass is about 32 u.

Board tip · CBSEBoard tip

Write the mass number above the symbol and the atomic number below. Reversing them changes the meaning of an isotope.

Check your understandingall correct = mastery ★
1
The atomic number is equal to —
Check
2
The mass number is only the number of protons.
Check
3
The mass number of sulphur is ______.
Check
4
The charge of an atom with 8 protons and 8 electrons is —
Check
5
Define atomic number and mass number. Give one number each for carbon as an example.
Check3 marks
Next lesson →
8

Isotopes and isobars

समस्थानिक और समभारिक · Bihar 4.6 · average mass

New
Isotopes and isobars+Nucleus in the centreElectrons in orbitsShells fill in order
A positive nucleus sits in the middle, electrons occupy fixed shells outside.
Same number, or same massNotes

Some atoms of an element have the same atomic number and different mass numbers. These are isotopes. Hydrogen has three forms. Protium has 1 proton and 0 neutrons. Deuterium has 1 proton and 1 neutron. Tritium has 1 proton and 2 neutrons. 126C and 146C of carbon are isotopes. So are 35 and 37 of chlorine.

Each isotope is a pure substance. Chemical properties stay alike and physical properties change. The average mass comes from the percentages. In nature chlorine is 35 u and 37 u in the ratio 3:1. No single atom has a mass of 35.5 u.

The uses differ. One isotope of uranium is a fuel in nuclear reactors. One isotope of cobalt is used in the treatment of cancer. One isotope of iodine is used in the treatment of goitre. Tincture of iodine is not that isotope.

Isobars are atoms of different elements that have the same mass number and different atomic numbers. Calcium has atomic number 20 and argon has 18. Both have mass number 40. Isotopes share Z. Isobars share A.

35.5 is not one atomCaution

The average belongs to the sample. Show 3:1 or 75% and 25% in the answer. Do not write tincture as the use of the isotope.

Worked exampleExample

Question: The chlorine isotopes 35 u and 37 u are in the ratio 3:1. Find the average atomic mass.

Formula: average = (3 × 35 + 1 × 37) / 4.

Substitution: (105 + 37) / 4 = 142 / 4 = 35.5.

Unit: 35.5 u. This is an average. Do not write 35.5 u on one single atom.

10-second revision
  • Isotopes: same Z, different A
  • Chlorine average 35.5 u
  • Isobars: Ar and Ca, A = 40
Board tip · BSEBBoard tip

In an average question show the sum with the percent or with 3:1. Writing 35.5 from memory alone is incomplete.

Board tip · CBSEBoard tip

Write one pair of each: Cl-35 and Cl-37, and Ar-40 and Ca-40.

Check your understandingall correct = mastery ★
1
Isotopes differ in —
Check
2
An isotope of iodine is used to make tincture of iodine.
Check
3
Argon and calcium are ______, because both have mass number 40.
Check
4
The chlorine average is 35.5 u because —
Check
5
Write the number of protons, neutrons and electrons in protium, deuterium and tritium, as in a table.
Check3 marks
6
If X has 6 protons and 6 neutrons and Y has 6 protons and 8 neutrons, the two are isotopes.
Check
Question bank →

❓ Full question bank — with answers and explanations — 67 questions

No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.

Multiple choice

0/14
Pick one option. A wrong try brings a hint.
1
The discovery of canal rays is linked with —
Board-style (practice)1 mark
2
The mass of a proton compared with an electron is about —
Board-style (practice)1 mark
3
The Thomson model calls the atom neutral because —
Board-style (practice)1 mark
4
In alpha scattering most particles —
Board-style (practice)1 mark
5
A limit of the Rutherford model is —
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6
The discovery of the neutron belongs to —
Board-style (practice)1 mark
7
The 2n^2 maximum of the M shell is —
Board-style (practice)1 mark
8
The correct configuration of sodium is —
Board-style (practice)1 mark
9
The valence electrons in a Cl− ion are —
Board-style (practice)1 mark
10
The atomic number is fixed by —
Board-style (practice)1 mark
11
An isobar pair is —
Board-style (practice)1 mark
12
The valency and name of the element with Z = 3 —
Board-style (practice)1 mark
13
Filled shells of Na+ mean —
Board-style (practice)1 mark
14
The average of the bromine isotopes 79 (49.7%) and 81 (50.3%) is near —
Board-style (practice)1 mark
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True or false

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1
Thomson said that the nucleus contains only nucleons.
Board-style (practice)1 mark
2
The mass of an electron is about 1/2000 of the mass of a proton.
Board-style (practice)1 mark
3
The protium nucleus contains a neutron.
Board-style (practice)1 mark
4
The valency of helium is 0.
Board-style (practice)1 mark
5
Every chlorine atom has a mass of 35.5 u.
Board-style (practice)1 mark
6
The chemical properties of isotopes are alike.
Board-style (practice)1 mark
7
The mass of an alpha particle is 4 u.
Board-style (practice)1 mark
8
The outermost shell holds the M-shell 2n^2 maximum of 18.
Board-style (practice)1 mark
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Fill in the blanks

0/8
1
Canal rays were seen in ______.
Board-style (practice)1 mark
2
The nuclear radius is about ______ times smaller than the radius of the atom.
Board-style (practice)1 mark
3
The K shell holds at most ______ electrons.
Board-style (practice)1 mark
4
The atomic number of carbon is ______.
Board-style (practice)1 mark
5
The mass number of aluminium is ______.
Board-style (practice)1 mark
6
The valency of oxygen is ______.
Board-style (practice)1 mark
7
The average atomic mass of chlorine is ______ u.
Board-style (practice)1 mark
8
The isobar pair of mass number 40 places ______ with argon.
Board-style (practice)1 mark
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Match

0/2
1
Match the scientist with the identification.
Board-style (practice)2 marks
Column B: A. Canal rays · B. Nucleus · C. Neutron · D. Electron
1. Thomson
2. Goldstein
3. Rutherford
4. Chadwick
2
Match the pair with its class.
NCERT-style · practice2 marks
Column B: A. Isobars of mass 40 · B. Isotopes of carbon · C. Isotopes of hydrogen · D. Isotopes of chlorine
1. Protium and tritium
2. Cl-35 and Cl-37
3. Argon-40 and calcium-40
4. Carbon-12 and carbon-14
↑ Question hub

Assertion–reason

0/5
Check both statements, then see whether the reason explains the assertion.
1

Assertion (A): Most of the space inside the atom is empty.

Reason (R): Most alpha particles went straight through the gold foil.

Board-style (practice)1 mark
2

Assertion (A): In a Bohr discrete orbit the electron does not lose energy.

Reason (R): This removes the falling drawback of the Rutherford model.

Board-style (practice)1 mark
3

Assertion (A): Isotopes have the same chemical properties.

Reason (R): The physical properties of isotopes are always the same too.

CBSE-style · competency-based (not a PYQ)1 mark
4

Assertion (A): The Thomson model has a positive nucleus.

Reason (R): The nucleus was found from alpha scattering.

Board-style (practice)1 mark
5

Assertion (A): The average atomic mass of chlorine is 35.5 u.

Reason (R): Argon and calcium are isobars.

CBSE-style · competency-based (not a PYQ)1 mark
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Coefficient practice

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This chapter has no chemical equation. Do not balance a nuclear symbol. Below is only the water coefficient practice, and it is not a result of this chapter.
1
This is coefficient practice and not a result of this chapter. A nuclear symbol is not an equation. Fill coefficients on the water reaction H2 + O2 → H2O (blank = 1).
Board-style (practice)1 mark
H2 + O2 → H2O
2
This is coefficient practice and not a result of this chapter. Do not balance a symbol such as 14 over 7 N here. Fill the coefficients of H2 + O2 → H2O, and write 1 on oxygen as well (blank = 1).
Board-style (practice)1 mark
H2 + O2 → H2O
3
This is coefficient practice and not a result of this chapter. Balance the water reaction from the previous chapter. The equation line has no coefficients. Blank = 1.
Board-style (practice)1 mark
H2 + O2 → H2O
4
This is coefficient practice and not a result of this chapter. The shell counts 2, 8, 8 are not coefficients. Balance only H2 + O2 → H2O (blank = 1).
Board-style (practice)1 mark
H2 + O2 → H2O
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Classify

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1
Place each particle by its charge.
Board-style (practice)2 marks
Electron
Proton
Neutron
Alpha particle
2
Place each pair as isotopes or isobars.
NCERT-style · practice2 marks
Protium, deuterium
Argon-40, calcium-40
Carbon-12, carbon-14
Cl-35, Cl-37
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Very short answer

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1
What are canal rays?
Board-style (practice)1 mark
2
Write one limitation of the Thomson model.
NCERT-style · practice2 marks
3
Define mass number.
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4
What are isobars? Give one pair.
NCERT-style · practice2 marks
5
Define valency in one line.
Board-style (practice)1 mark
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Short answer

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1
Write two points of the Rutherford model and one drawback.
NCERT-style · practice3 marks
2
Write the configurations of carbon, sodium and argon among the first eighteen. Write the outer-shell rule separately.
Board-style (practice)3 marks
3
Explain the valency of silicon and oxygen with the example.
NCERT-style · practice3 marks
4
The bromine isotopes are 79Br 49.7% and 81Br 50.3%. Find the average atomic mass.
Board-style (practice)3 marks
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Long answer

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1
Compare the three models: Thomson, Rutherford and Bohr. For each model write one point and one limit or improvement.
Board-style (practice)5 marks
2
Explain atomic number, mass number, isotopes and isobars with examples. Write two uses of isotopes.
NCERT-style · practice5 marks
3
The average atomic mass of a sample is 16.2 u. Find the percentages of the isotopes 16X and 18X. Also show 35.5 u of chlorine from the ratio 3:1.
NCERT-style · practice5 marks
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BSEB model paper · practice

0/6

This model set is for practice. It is not a question from the annual examination of any year. Annual questions will be added only when a source page is available.

1
The gold foil was about —
BSEB model · practice (not an annual paper)1 mark
2
The configuration of inert argon is —
BSEB model · practice (not an annual paper)1 mark
3
The number of neutrons in helium is ______ when the mass is 4 u and the protons are 2.
BSEB model · practice (not an annual paper)1 mark
4
What conclusion follows from the comb part of Activity 4.1?
BSEB model · practice (not an annual paper)2 marks
5
Why are the K and L shells of Na+ called complete? Separately state the outer electrons of the chloride ion.
BSEB model · practice (not an annual paper)3 marks
6
Write the three Bohr-Bury rules. Give the configurations of carbon, sodium and an atom whose K and L shells are full. Also write the 2n^2 maximum of M.
BSEB model · practice (not an annual paper)5 marks
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CBSE-style questions

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These are competency-based practice questions. They are not copies of a CBSE paper.

1
A student says the M shell can never hold more than 8 electrons, because the picture shows 8. The right correction is —
CBSE-style · competency-based (not a PYQ)1 mark
2
12000 alpha particles fall on the gold foil. The most reasonable expectation is —
CBSE-style · competency-based (not a PYQ)1 mark
3

Assertion (A): Cl− has 8 valence electrons.

Reason (R): Chlorine 2, 8, 7 gains one electron and becomes 2, 8, 8.

CBSE-style · competency-based (not a PYQ)1 mark
4

Assertion (A): Tincture of iodine is made from an isotope of iodine.

Reason (R): One isotope of iodine is used in the treatment of goitre.

CBSE-style · competency-based (not a PYQ)1 mark
5
A student calls the neutron a pair of an electron and a proton, because the charge is zero. What is the mistake? Write the Chadwick fact.
CBSE-style · competency-based (not a PYQ)3 marks
6
A sample average is 16.2 u and the isotopes are 16 and 18. Find the percentage of the heavier one. Why is this average like the 35.5 of chlorine?
CBSE-style · competency-based (not a PYQ)3 marks
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🏛️ Board exam corner — Bihar Board (BSEB)— CBSE

Switch board with BSEB | CBSE above. The lessons follow the same NCERT chapter.

BSEB model · practiceBoard tip

This page has no verified annual-exam question, because no source page has been added. The model set below is practice in the board pattern.

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CBSE-style · competency-based

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🧠 What you learned + equation sheet

What you learned

WhatKeep this
Protoncharge +1, mass about 1 u
Electroncharge −1, mass about 1/2000 u
Neutroncharge 0, mass about 1 u, none in protium
Shell rule2n^2, and at most 8 in the outer shell
Chlorine average35.5 u from 35 and 37 in the ratio 3:1
Isobar pairargon and calcium, both mass number 40

The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.