The atomic number is 6, arrangement 2, 4.
There are four electrons in the outer shell, so the valency is four.
Class 10 · Science · Chapter 4 · बिहार बोर्ड (BSEB)CBSE · NCERT 2026-27
Carbon and its Compounds
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सहसंयोजक बंध और चतुर्संयोजकता — क्रियाकलाप 4.1 · NCERT 4.1 · Activity 4.1
The atomic number of carbon is 6. The electron arrangement is 2, 4. It needs four more electrons to complete an octet.
Gaining four would make C4−, but six protons cannot hold ten electrons. Losing four would make C4+, and that costs a huge amount of energy. So carbon shares electrons and forms covalent bonds. In methane, carbon shares one pair with each of four hydrogens.
The bond inside the molecule is strong. The pull between molecules is weak. Melting and boiling points stay low, and these compounds usually do not conduct electricity. No ions are formed.
List ten things you have eaten or used since morning. Pool the class lists into three columns: metal, glass or clay, and the rest. If one thing is made of two materials, write it in both columns.
Most items in the last column are compounds of carbon. Bread, cloth, a medicine, paper, plastic. Burning them gives carbon dioxide. Lime water turning milky is the test for that gas.
The crust has about 0.02% carbon and the air about 0.03% carbon dioxide. The amount is small. The number of compounds is huge.
| Compound | Melting point | Boiling point |
|---|---|---|
| Ethanoic acid | 290 K | 391 K |
| Ethanol | 156 K | 351 K |
| Methane | 90 K | 111 K |
| Chloroform | 209 K | 334 K |
Question: Why does methane not conduct electricity, while molten salt does?
Answer: In methane the electrons are shared, so no ions form. A current needs charged particles that can move. In molten salt the ions move, so the bulb glows.
In an objective item both C4+ and C4− are the rejected paths. The correct path is sharing of electrons.
CBSE asks the reason: the nucleus cannot hold four extra electrons, and removing four electrons costs a lot of energy.
The atomic number is 6, arrangement 2, 4.
There are four electrons in the outer shell, so the valency is four.
False — the bonding does not make ions, so they are poor conductors.
Six protons would be left holding only two electrons.
Removing four electrons costs a lot of energy, so carbon shares.
The English name is covalent.
The shared pair is called a covalent bond.
Carbon dioxide forms. Pass it through lime water. The water turns milky.
हीरा, ग्रेफाइट और C60 · NCERT · allotropes of carbon
Diamond and graphite are both only carbon. The difference is how the atoms join. In diamond every carbon is joined to four other carbons. The frame is rigid and spreads in three directions. Diamond is the hardest natural substance.
In graphite every carbon is joined to three other carbons in the same plane. Hexagonal sheets sit one above another. One bond behaves like a double bond, so the valency is satisfied. The layers slide, so graphite feels slippery. Because of free electrons it conducts electricity.
In C60 sixty carbons sit in the shape of a football. This is a fullerene. The name comes from the dome of the architect Buckminster Fuller. Small diamonds are also made by putting pure carbon under very high pressure and temperature.
Question: Diamond is an insulator and graphite is a conductor. Both are carbon, so why the difference?
Answer: In diamond all four electrons of each carbon are locked in bonds, so none is free to move. In graphite each carbon is joined to three others, and the fourth electron can move in the sheet.
In an objective item the conducting non-metal is graphite, not diamond.
CBSE asks the structure. Do not stop at the name — state four bonds or three bonds.
A rigid frame in three directions.
In diamond each carbon is bonded to four other carbons.
True — electrons can move in the sheet. Diamond does not conduct.
The first fullerene to be identified.
In C60 the carbon atoms are arranged like a football.
In diamond each carbon is locked to four carbons in a three-dimensional network, so it is hard. In graphite the hexagonal layers are held by a weak force and slide.
संतृप्त, असंतृप्त और समजातीय श्रेणी — क्रियाकलाप 4.2 · NCERT 4.2 · Activity 4.2
Carbon joins its own atoms into chains. This is catenation. A chain may be straight, branched or a ring. Silicon also makes short chains, but they stay very reactive. The carbon-carbon bond is strong and the atom is small, so the compounds last.
Compounds with only single bonds are saturated, such as ethane C2H6. A double or triple bond between carbon atoms makes the compound unsaturated. Ethene C2H4 has a double bond, ethyne C2H2 a triple bond. Unsaturated compounds are more reactive.
Compounds of only carbon and hydrogen are hydrocarbons. The saturated ones are alkanes, general formula CnH2n+2. Alkenes with one double bond are CnH2n. Alkynes with one triple bond are CnH2n−2. C4H10 has two structures. Compounds with the same formula and different structures are structural isomers.
| Carbons | Name | Formula |
|---|---|---|
| 1 | Methane | CH4 |
| 2 | Ethane | C2H6 |
| 3 | Propane | C3H8 |
| 4 | Butane | C4H10 |
| 5 | Pentane | C5H12 |
| 6 | Hexane | C6H14 |
Take the alcohol chain: CH3OH, C2H5OH, C3H7OH, C4H9OH. Each next formula has one more CH2 than the one before. Carbon is 12 u and hydrogen is 1 u, so the mass gap is 14 u. The same gap appears in all three pairs.
Line them up by increasing carbon and you get one family. The functional group is the same −OH. Such a chain is a homologous series. Alkenes do the same: C2H4, C3H6, C4H8. Melting and boiling points rise as the mass rises. Chemical behaviour stays similar because the group is the same.
Question: Find the difference in molecular mass of C2H6 and C3H8.
Working: C2H6 = 2×12 + 6×1 = 30 u. C3H8 = 3×12 + 8×1 = 44 u. Difference = 44 − 30 = 14 u. That is the mass of one CH2.
In an objective item remember 14 u. Writing 12 u or 16 u loses the mark.
CBSE can ask for the three pairs of Activity 4.2. For each pair write both CH2 and 14 u.
Look for a double bond.
Ethene C2H4 has a carbon-carbon double bond.
True — the mass also rises by 14 u.
Ethene is C2H4, not propane. n is at least 2.
The general formula of an alkene is CnH2n.
Activity 4.2. The group is the same −OH.
The same functional group and a gap of CH2 — this is a homologous series.
True — the formula is one, the carbon skeleton differs. One is a straight chain, one is branched.
The formula gap is CH2. The mass gap is 12 + 2 = 14 u. Both alcohols belong to the same homologous series.
कार्बन यौगिकों के नाम · NCERT 4.2.5 · nomenclature
If another atom or group stands in place of hydrogen, it is a functional group. That group decides the chemical behaviour, whether the chain is long or short.
The name starts from the carbon count: 1 meth, 2 eth, 3 prop, 4 but, 5 pent. A three-carbon chain is propane. If the suffix starts with a vowel, drop the final e. Propane − e + one = propanone.
A double bond replaces ane with ene, a triple bond with yne. Three carbons and a double bond = propene. Three carbons and a triple bond = propyne.
| Class | In the name | Example |
|---|---|---|
| Haloalkane | Prefix chloro / bromo | Chloropropane |
| Alcohol | Suffix ol | Propanol |
| Aldehyde | Suffix al | Propanal |
| Ketone | Suffix one | Propanone |
| Carboxylic acid | Suffix oic acid | Propanoic acid |
Question: Name CH3−CH2−Br.
Answer: There are two carbons, so the parent name is ethane. Bromine is a prefix, not a suffix. The name is bromoethane. The e stays, because bromo is added in front.
In an objective item butanone is a four-carbon ketone. Do not pick the acid or the aldehyde.
CBSE asks for the three steps of a name: count the carbons, identify the group, and see whether the e must go.
The suffix one belongs to a ketone.
Butanone is a four-carbon ketone.
The three-carbon ketone.
Propane − e + one = propanone.
There are two carbons, and bromine goes in front.
Two carbons and a −Br prefix: bromoethane.
True — methanol, ethanol, propanol. Chloro is a prefix, not a suffix.
The parent name for three carbons is propane. The suffix for a carboxylic acid is oic acid and it starts with a vowel, so drop the e. The name is propanoic acid.
दहन और कज्जली ज्वाला — क्रियाकलाप 4.3, 4.4 · NCERT 4.3.1 · Activities 4.3, 4.4
Carbon and most of its compounds give heat and light on burning. In plenty of air a saturated hydrocarbon gives a clean blue flame. An unsaturated compound gives a yellow flame and black smoke.
If air is short, even a saturated compound burns incompletely and gives soot. That is why a gas or kerosene stove has air holes. A blackened pan means the holes are blocked and fuel is being wasted.
Coal and petroleum contain some nitrogen and sulphur. Their oxides dirty the air. Coal sometimes only glows red and gives heat, because a flame forms when gases burn. The yellow of a candle flame comes from half-burnt carbon particles.
Do Activity 4.3 with the teacher. Do not burn naphthalene, camphor or alcohol on your own.
Burn naphthalene, camphor and alcohol one by one on a spatula. Note the colour of the flame and any smoke. Hold a metal plate above the flame.
Above an unsaturated or half-burnt compound the plate turns black. That black deposit is soot.
Light a Bunsen burner and turn the air hole at the base. When the hole is closed, air is short and the flame is yellow and sooty. When the hole is open, air is plenty and the flame is blue.
Question: Write the balanced equation for the combustion of methane.
Answer: CH4 + 2O2 → CO2 + 2H2O + heat and light. Carbon 1 = 1, hydrogen 4 = 4, oxygen 4 = 2 + 2.
In an objective item a blackened vessel means incomplete combustion, not wet fuel.
CBSE asks the welding question. Ethyne is mixed with oxygen, not with air, so that combustion is complete and the heat is enough.
10-second revision
The sign that the air holes are blocked.
A blackened base is the sign of incomplete combustion. Fuel is being wasted.
True — soot appears when the compound is unsaturated or air is short.
Less air, incomplete combustion.
When the air hole is closed, oxygen is short and the flame is yellow and sooty.
The plate of Activity 4.3.
The black deposit is called soot. It is carbon.
Full heat and complete combustion are needed.
Air has less oxygen. The mixture burns incompletely, soot forms, and the temperature is not enough for welding.
C2H5OH + 3O2 → 2CO2 + 3H2O. In plenty of air the only products are carbon dioxide and water.
ऑक्सीकरण, योग और प्रतिस्थापन — क्रियाकलाप 4.5 · NCERT 4.3.2–4.3.4 · Activity 4.5
Take about 3 mL of ethanol in a test tube and warm it gently in a water bath. Do not use a direct flame. Add 5% alkaline potassium permanganate drop by drop.
At first the pink colour disappears, because the permanganate is being used up in oxidising the ethanol. When all the ethanol has become ethanoic acid, the colour of an extra drop stays.
A substance that adds oxygen to another is an oxidising agent. Alkaline KMnO4 and acidified potassium dichromate turn alcohols into acids. Ethanol becoming ethanoic acid is oxidation, because oxygen is added to the molecule.
Unsaturated hydrocarbons add hydrogen in the presence of nickel or palladium and become saturated. The long chains in vegetable oils are usually unsaturated. Hydrogen is added on a nickel catalyst to turn them into solid fat. Oils with unsaturated chains are the better choice for cooking. A catalyst changes the speed and is not used up itself.
Saturated hydrocarbons stay sluggish with most reagents. In sunlight chlorine quickly takes the place of hydrogen. CH4 + Cl2 → CH3Cl + HCl This is substitution. One atom takes the place of another.
Question: Why is the change from ethanol to ethanoic acid an oxidation?
Answer: Ethanol is C2H5OH and ethanoic acid is CH3COOH. The proportion of oxygen in the acid has increased. Alkaline KMnO4 added that oxygen. So this is oxidation.
In an objective item a fading colour means the reagent is being used. A colour that stays means the alcohol is finished.
CBSE asks the definition of a catalyst on its own. Write: it changes the speed and is not used up in the reaction.
10-second revision
Oxidation of an alcohol gives a carboxylic acid.
Ethanol is oxidised to ethanoic acid.
True — no alcohol is left to use it up, so the pink colour stays.
Palladium can also cause addition. The book names nickel.
In the presence of a nickel catalyst an unsaturated oil adds hydrogen and becomes a saturated fat.
One atom takes the place of another.
Cl takes the place of hydrogen, so this is substitution.
A substance that adds oxygen to another is an oxidising agent. Alkaline potassium permanganate and acidified potassium dichromate turn an alcohol into an acid.
एथेनॉल और सोडियम — क्रियाकलाप 4.6 · NCERT 4.4.1 · Activity 4.6
The melting point of ethanol is 156 K and the boiling point is 351 K. This is the alcohol of everyday speech. It is a solvent in medicines, such as tincture of iodine. It dissolves in water in every proportion.
A little dilute ethanol causes drunkenness. Even a small amount of pure ethanol (absolute alcohol) can be lethal. Long use damages health. Methanol is more dangerous still. The liver turns it into methanal, which can harm the optic nerve and cause blindness. Industrial alcohol is made denatured by adding methanol and a blue dye, so that nobody drinks it.
At 443 K, excess concentrated sulphuric acid removes water from ethanol and makes ethene. The concentrated acid is a dehydrating agent here. C2H5OH → C2H4 + H2O
The piece of sodium should be no bigger than a couple of grains of rice. Do not touch it with a bare hand. It reacts quickly with moisture. This demonstration is only for the teacher.
Drop a small piece of sodium into absolute alcohol. Bubbles rise. The gas is hydrogen. A burning splinter at the mouth gives a pop.
The other product is sodium ethoxide. 2Na + 2C2H5OH → 2C2H5ONa + H2
Question: How will you identify the gas of Activity 4.6?
Answer: Bring a burning splinter to the mouth of the test tube. A sharp pop is the test for hydrogen. In the equation the gas is H2. Sodium ethoxide stays in the tube.
In an objective item the gas is hydrogen, not carbon dioxide. A pop is not the test for CO2.
CBSE asks the role of concentrated sulphuric acid. Write: dehydrating agent, ethene forms at 443 K.
10-second revision
A pop with a burning splinter.
The gas is hydrogen. The pop is its test.
True — the book gives this size. The teacher does the demonstration.
The formula is C2H5ONa.
The other product is sodium ethoxide.
Water leaves, and an unsaturated hydrocarbon remains.
Dehydration gives ethene and water.
Methanol and a dye are added to industrial ethanol so that it cannot be drunk. In the liver methanol becomes methanal, which coagulates cell material and can damage the optic nerve and cause blindness.
एथेनॉइक अम्ल — क्रियाकलाप 4.7, 4.8, 4.9 · NCERT 4.4.2 · Activities 4.7 to 4.9
The common name of ethanoic acid is acetic acid. A 5–8% solution in water is vinegar, a preservative for pickles. The melting point of the pure acid is 290 K. In a cold winter it freezes, so it is called glacial acetic acid.
Carboxylic acids are weaker than mineral acids. HCl is almost fully ionised, ethanoic acid is not. With a base, a salt and water form: NaOH + CH3COOH → CH3COONa + H2O
Compare the pH of dilute acetic acid and dilute hydrochloric acid. Both turn blue litmus red. Universal indicator does not show them as equally strong. The pH of acetic acid stays higher. It is a weak acid.
Take 1 mL absolute ethanol, 1 mL glacial acetic acid and a few drops of concentrated sulphuric acid. Warm in a water bath for at least five minutes. Then pour into a beaker with 20–50 mL of water.
Caution: concentrated acid stays with the teacher. Do not use a direct flame. The smell of the mixture is sweet. The compound formed is an ester, ethyl ethanoate.
Take a spatula of sodium carbonate in a test tube and add 2 mL of dilute ethanoic acid. Pass the gas into freshly prepared lime water. The water turns milky, because the gas is carbon dioxide. The same happens with sodium hydrogencarbonate.
2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2
Question: Write the ester from ethanoic acid and ethanol. Also name the catalyst and the smell.
Answer: CH3COOH + C2H5OH → CH3COOC2H5 + H2O
The catalyst is concentrated sulphuric acid. The product is ethyl ethanoate. The smell is sweet. Esters are used in perfumes and flavourings. With an alkali the ester breaks back into an alcohol and the sodium salt of the acid. This reaction is called saponification.
In an objective item vinegar is 5–8% acetic acid. The melting point of the pure acid is 290 K.
CBSE asks an experimental difference between an alcohol and a carboxylic acid. Write both the litmus test and the carbonate test.
10-second revision
The melting point is 290 K.
The melting point is 290 K, so in the cold it freezes like ice.
True — both turn blue litmus red. Acetic acid is weaker, so its pH stays higher.
An acid and an alcohol, with concentrated H2SO4.
The sweet smell is of ethyl ethanoate, which is an ester.
It is a range, not one number.
Vinegar is a 5–8% solution of acetic acid in water.
True — the gas turns lime water milky. Activity 4.9.
Ethanoic acid turns blue litmus red, ethanol does not. Ethanoic acid releases CO2 from sodium carbonate and lime water turns milky. Ethanol does not give this gas with a carbonate.
साबुन का मिसेल और कठोर जल — क्रियाकलाप 4.10 से 4.12 · NCERT 4.5 · Activities 4.10, 4.11, 4.12
Take 10 mL of water in each of two test tubes. Add one drop of cooking oil to both. Call them A and B. Add a few drops of soap only to B. Shake both for the same time.
As soon as you stop, the oil and water layers in A separate. In B the oil stays mixed for longer. Soap turns the oil into an emulsion in water. Beating the cloth, or the spin of a machine, is needed so that the dirt can enter the middle of a micelle.
Soap is a sodium or potassium salt of a long-chain carboxylic acid. The ionic end is friendly with water, that is hydrophilic. The carbon tail is friendly with oil, that is hydrophobic.
Inside water the tails hide in the middle of the drop and the ionic heads stay outside. That cluster is a micelle. Heads of the same charge do not come close, so the micelle stays suspended like a colloid and the dirt rinses away. Micelles scatter light, so a soap solution looks cloudy.
Take 10 mL of distilled water or rain water and 10 mL of hard water (a tubewell or hand-pump) in separate tubes. Add a few drops of soap to both and shake equally. More lather forms in distilled water. Hard water gives a white curdy precipitate. If hard water is not available, dissolve a hydrogencarbonate, sulphate or chloride of calcium or magnesium.
Now take only hard water in two tubes. Five drops of soap in one, five drops of detergent in the other. Shake equally. The detergent lathers. The curdy solid forms in the soap tube.
| Difference | Soap | Detergent |
|---|---|---|
| What it is | Sodium or potassium salt of a long-chain carboxylic acid | A sodium salt of a sulphonic acid, or an ammonium salt with chloride or bromide |
| Hard water | Insoluble scum with Ca and Mg | No insoluble clot, the lather remains |
| Clothes | Good in soft water; used up faster in hard water | Cleans even in hard water |
Question: Write three differences between soap and a detergent.
Answer: (1) Soap is a salt of a carboxylic acid, a detergent of a sulphonic acid. (2) In hard water soap gives a white scum, a detergent does not. (3) Soap gives little lather in hard water, a detergent keeps the lather.
In an objective item scum belongs to soap and hard water. A detergent cannot be used to test whether water is hard.
CBSE asks the cleaning action in four steps: tail in the oil, head outside, emulsion, and dirt rinsing away because of ion-ion repulsion.
10-second revision
The tail is hydrophobic.
The hydrophobic tail stays inside the oil and the ionic head faces outward toward water.
False — soap forms the scum. The charged end of a detergent does not clot with Ca or Mg.
The white curd of Activity 4.11.
Calcium and magnesium make an insoluble scum with soap.
The tube with scum has less lather.
More lather forms in distilled water or rain water. Hard water gives a white precipitate.
Soap is a Na or K salt of a long-chain carboxylic acid. A detergent is a salt of a sulphonic acid. Soap makes scum with Ca and Mg in hard water, a detergent does not. So in hard water the lather of soap falls and the lather of a detergent remains.
Pick a type. The 47 lesson checks are separate — each lesson has as many as its topic needs. All correct earns mastery ★.
No question is marked as a verified past paper. The BSEB set is a model for practice. CBSE items are CBSE-style, not a copy of any year’s paper.
One C−C and six C−H.
Ethane has 7 covalent bonds.
CO2 in air is about 0.03%.
Carbon in the crust is about 0.02%.
Free electrons in the sheet.
Graphite conducts. Diamond does not.
A football-like structure.
C60 is a fullerene.
Methane is CH4, ethane is C2H6.
Alkanes are CnH2n+2.
Five carbons, three skeletons.
Pentane has three structural isomers.
CH2 = 12 + 2.
The gap is 14 u.
The suffix one.
Propanone is a three-carbon ketone.
Pick the condition of a clean flame.
In plenty of air a saturated compound gives a clean flame.
Alkaline KMnO4.
Ethanol changes into ethanoic acid.
Substitution.
The products are chloromethane and HCl.
With concentrated H2SO4.
Ethene forms at 443 K.
The pickle preservative.
Vinegar is a 5–8% solution of acetic acid.
Ca and Mg salts.
Soap forms scum. A detergent does not.
True — the forces between molecules are weak. See Table 4.1.
False — the conducting allotrope is graphite.
False — ethene has a double bond, so it is unsaturated.
True — the book writes a caution.
True — the book describes a fast reaction in sunlight.
False — this test belongs to a carboxylic acid, not to an alcohol.
True — micelles scatter light.
False — a detergent lathers even in hard water. The test uses soap.
This property is called catenation.
The English word is catenation.
Ethanol boils at 351 K.
Table 4.1. The melting point is 156 K.
Alkynes are CnH2n−2.
Ethyne is C2H2.
The suffix is one.
Propanone.
The gas is hydrogen.
The gas of the pop.
Ethyl ethanoate is an ester.
A sweet smell.
The melting point is 290 K.
Glacial acetic acid.
The outer end is hydrophilic, or ionic.
Toward water.
ol, al, one, and chloro goes in front.
Closed hole gives soot, sodium gives a pop, the ester gives a smell, hard water gives scum.
Assertion (A): Diamond is very hard.
Reason (R): In diamond each carbon is joined to four other carbons in a three-dimensional network.
Both are true and R correctly explains A.
Assertion (A): Graphite conducts electricity.
Reason (R): Graphite is a metal.
A is true. R is false — graphite is an allotrope of carbon, a non-metal.
Assertion (A): The formula of the next homologue differs by CH2 from the one before it.
Reason (R): The difference in their molecular masses is 14 u.
Both are true. R states the mass. It does not explain the formula gap. R does not explain A.
Assertion (A): Ethanol turns blue litmus red.
Reason (R): Carboxylic acids turn blue litmus red.
A is false — ethanol does not change litmus. R is true.
Assertion (A): Clothes do not wash well with soap in hard water.
Reason (R): Calcium and magnesium salts make an insoluble scum with soap.
Both are true and R is the correct reason.
Ethane and propane are saturated. Ethene and ethyne are unsaturated.
Scum and the carboxylic salt belong to soap. A lather that lasts in hard water belongs to a detergent.
A covalent bond is a bond formed by the sharing of an electron pair between two atoms.
An atom or group that takes the place of hydrogen in a hydrocarbon and decides the chemical behaviour of the compound.
Compounds with the same molecular formula and different structures are structural isomers. Butane is C4H10 and it has two structures.
A substance that adds oxygen to another substance is an oxidising agent. Example: alkaline KMnO4.
Soap is a basic salt. It turns red litmus blue. Blue litmus stays blue.
In diamond each carbon is joined to four others, in graphite to three. Diamond is hard, graphite is soft and slippery. Diamond is an insulator, graphite is a conductor.
A family with the same functional group in which the next member is heavier by CH2 and 14 u. Example: CH3OH, C2H5OH, C3H7OH. Chemical properties match, physical properties change in order.
Hydrogenation is the addition of hydrogen to an unsaturated hydrocarbon in the presence of nickel or palladium. It is used to turn vegetable oils into saturated fat such as vanaspati.
2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2. CH3COOH + NaHCO3 → CH3COONa + H2O + CO2. In both, lime water turns milky.
The ionic end of soap is hydrophilic and the carbon tail is hydrophobic. In water the tails hide inside the oily dirt and the heads stay outside. That is a micelle. Agitation brings the dirt into the middle. Because the charges are alike, the micelles do not clump and they rinse away. Ca and Mg ions of hard water make an insoluble scum with soap, so no lather forms. A detergent does not make this scum.
Ethanol boils at 351 K, ethanoic acid at 391 K. The pure acid freezes at 290 K and is called glacial. The acid turns blue litmus red, ethanol does not. The acid gives CO2 with sodium carbonate, ethanol does not. Ester: CH3COOH + C2H5OH → CH3COOC2H5 + H2O, with concentrated H2SO4.
Carbon is a small atom and the carbon-carbon bond is strong. By catenation it makes long chains, branches and rings, such as the chain of hexane or the ring of cyclohexane. By tetravalency each carbon makes four bonds, so with hydrogen it forms methane CH4, and oxygen, nitrogen and chlorine add further groups. The two properties together give millions of compounds.
This model set is for practice. It is not a question from any year’s annual examination. Annual questions will be added only when a source page is available.
Only single bonds.
C2H6 is ethane and it is saturated.
A salt of a carboxylic acid.
Soap is a sodium or potassium salt of a long-chain carboxylic acid.
Butanone has four carbons.
But = four.
Blocked air holes make the fuel burn incompletely and soot settles on the vessel. Clean the air holes of the stove so that you get a blue flame.
2Na + 2C2H5OH → 2C2H5ONa + H2. The pop of the gas identifies hydrogen. The sodium should be the size of two rice grains and only the teacher should add it. At 443 K excess concentrated H2SO4 removes water from ethanol and makes ethene. Concentrated acid burns the skin.
These are competency-based practice questions. They are not copies of a CBSE paper.
Soap makes an emulsion.
In tube A, without soap, the layers separate sooner.
A double or triple bond is needed.
Ethene and ethyne are unsaturated, so they add hydrogen.
Assertion (A): In Activity 4.5 the pink colour of the first drops disappears.
Reason (R): Alkaline KMnO4 is used up in oxidising the ethanol.
Both are true and R is the correct reason.
Assertion (A): A detergent can lather in hard water.
Reason (R): A detergent makes the same insoluble scum with calcium ions that soap makes.
A is true. R is false — the charged end of a detergent does not make insoluble scum.
The first liquid can be ethanol. The second is ethanoic acid. The acid changes litmus and gives CO2 with a carbonate.
In a hydrocarbon the hydrophilic heads will turn inward and the hydrophobic tails will stay outward toward the solvent. In water it is the other way: tails inside, heads outside.
Switch board with BSEB | CBSE above. The lessons follow the same NCERT chapter.
This page has no verified annual-exam question, because no source page has been added. The model set below is practice in the board pattern.
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The verified label will be used only when a source page for the question is available.
These are case and assertion-reason practice items. Do not treat them as past CBSE questions.
Wrong questions return soon; correct ones return after a few days.
What you learned
| What | Keep this |
|---|---|
| Combustion of methane | CH4 + 2O2 → CO2 + 2H2O |
| Combustion of ethanol | C2H5OH + 3O2 → 2CO2 + 3H2O |
| Ethanol with sodium | 2Na + 2C2H5OH → 2C2H5ONa + H2 |
| Esterification | CH3COOH + C2H5OH → CH3COOC2H5 + H2O |
| Acid and carbonate | 2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2 |
| Homologue gap | CH2 और 14 u |
The notes are original writing. The textbook was used only for activity order and numbers. “Verified” will be used only on a question that has a source page.